Status
Not open for further replies.
Is the dayan zhanchi 2x2 best 2x2 cube?
Are there any 3x3 cubes that are better than dayan ones?
Are 4x4 and 5x5 shengshou cubes best, or are there better?
 

Most likely not much. I can tell you the YJ does not use screw springs. Its mechanism is bad.

If you notice at the top of the page they both say YJ 3x3

How well does colored duct tape work as stickers?

and slightly off topic: how does one carve/cut numbers and symbols into a 3/4 inch square block of wood? 1 symbol/number per face

They would peel really easy.

Your best bet is either a woodburner, or a dremel/rotary tool. if you have stencils or can make them, I would use stencils and a marker to mark the spot before burning,carving.

Soft woods that can be widdled would not be good for a cube. If that is what you are doing.




I have a YJ 6x6 and the U/D middle slice misaligns. I assume because only one center piece has the preattached wings. Is there a fix for this. I have search for a while and haven't been able to find anything
 
Last edited:
So, hopefully I can ask this correctly...

Recall the unit circle, if you would
r0cvoo.gif

Let's just say we super impose a single face of the rubik's cube on a Unit Circle with the Center Perfectly lined up at the origin and the center of the 4 edge pieces perfectly lined up at (1,0),(-1,0),(0,1),(0,-1).
Like so:
16jh6ok.jpg

(Not drawn to scale, just approximations.

I believe that this orientation would put the center of the corner pieces on the points (1,1),(-1,1),(-1,-1),(1,-1).
This is an assumption based of observation, but I am quite sure it is correct.

Now let's say we turn the cube face 45 degrees clockwise
Heres what I know:
The center does not change position
The Edge piece that was at co-ordinates (0,1) moves to (sqrt(2)/2,sqrt(2)/2), and likewise for all the other Edges except positive or negative in x and/or y.

I do not however know what happens to the position of the corner, and I have been trying to figure out. If anyone knows the exact co-ordinates that it would move to (from (1,1)) could you please tell me?

I am using this information to program a simulator. Nothing serious, just recreational. However I can't get the corners to follow the edges properly with what little understanding of trigonometry I have.

This became a long post sorry lol
 
So, hopefully I can ask this correctly...

Recall the unit circle, if you would
r0cvoo.gif

Let's just say we super impose a single face of the rubik's cube on a Unit Circle with the Center Perfectly lined up at the origin and the center of the 4 edge pieces perfectly lined up at (1,0),(-1,0),(0,1),(0,-1).
Like so:
16jh6ok.jpg

(Not drawn to scale, just approximations.

I believe that this orientation would put the center of the corner pieces on the points (1,1),(-1,1),(-1,-1),(1,-1).
This is an assumption based of observation, but I am quite sure it is correct.

Now let's say we turn the cube face 45 degrees clockwise
Heres what I know:
The center does not change position
The Edge piece that was at co-ordinates (0,1) moves to (sqrt(2)/2,sqrt(2)/2), and likewise for all the other Edges except positive or negative in x and/or y.

I do not however know what happens to the position of the corner, and I have been trying to figure out. If anyone knows the exact co-ordinates that it would move to (from (1,1)) could you please tell me?

I am using this information to program a simulator. Nothing serious, just recreational. However I can't get the corners to follow the edges properly with what little understanding of trigonometry I have.

This became a long post sorry lol

(1,1)->(sqrt(2),0)
(1,-1)->(0,-sqrt(2))
(-1,-1)->(-sqrt(2),0)
(-1,1)->(0,sqrt(2))

because the length of the line from (0,0) to (1,1) is sqrt(2) and the centre piece is at (0,0), the length of the line from (x,y) to (0,0) must also be sqrt(2), and since its a 45 degree turn, x=0 or y=0 so the other one must be sqrt(2) or -sqrt(2)
 
Last edited:
(1,1)->(sqrt(2),0)
(1,-1)->(0,-sqrt(2))
(-1,-1)->(-sqrt(2),0)
(-1,1)->(0,sqrt(2))

because the length of the line from (0,0) to (1,1) is sqrt(2) and the centre piece is at (0,0), the length of the line from (x,y) to (0,0) must also be sqrt(2), and since its a 45 degree turn, x=0 or y=0 so the other one must be sqrt(2) or -sqrt(2)

Thanks a ton, that makes perfect sense. :)
 
Status
Not open for further replies.
Back
Top