Status
Not open for further replies.
I was reading the WCA regulations, and there was this rule:

5b5b) If one part with one coloured face is affected, the puzzle is considered solved.

Does this mean that, if let's say an oblique pops out of my 6x6, I can choose not to put it back, and there will be no penalty?
 
Are 12-colored Megaminxes allowed in competition?

Are 12-colored Megaminxes allowed in competition? I would like an answer ASAP, like, today!
 
If its an official competition, check the regulations
If it is an unofficial competition, ask the organisers
In case youre too lazy to find, the stickerless ones are not, however, those witht one solid colour body and 12 colours of stickers, yes
Pretty sure all megaminxed are 12 colored.
Isnt it 13? People usually have black on white, so...
Some people use white on white, though, so....
 
How can i recognize a adjacent swap from a diagonal swap (during olls)? at which sticker should i look at?

In your head, imagine rotating all the corners such that their U color faces up. Then, figure out which two (or zero) corners have to be "switched" in order for the corner permutation to be solved.

This is the best way to LEARN how to recognize CP, but if you want to be a cheater, you can always look up the COLLs on boca.bee.pl and see which corner patterns are which CP.
 
I was reading the WCA regulations, and there was this rule:

5b5b) If one part with one coloured face is affected, the puzzle is considered solved.

Does this mean that, if let's say an oblique pops out of my 6x6, I can choose not to put it back, and there will be no penalty?
Yes, there is no penalty. Same as if a corner/edge/centre cap on a 3x3 popped (but not the entire corner/edge!)

If you mean are stickerless megaminxes allowed in competition the answer is no.
I think you can get 6 colour megaminxes.

Sorry for asking, im not familiar with this. How do you orient corners during or before F2L? Using Petrus or ZZ method? Sledgehammering pairs?
You do orient edges during ZZ and Petrus, yes. Sledgehammers can also be used to orient some edges, although only those in UR and FR. You can use R U R', R U' R' and AUFs to adjust where your misoriented edges are so that sledgehammering will orient all last layer edges as you insert the last pair (if you have two misoriented edges).
 
Yes, there is no penalty. Same as if a corner/edge/centre cap on a 3x3 popped (but not the entire corner/edge!)


I think you can get 6 colour megaminxes.


You do orient edges during ZZ and Petrus, yes. Sledgehammers can also be used to orient some edges, although only those in UR and FR. You can use R U R', R U' R' and AUFs to adjust where your misoriented edges are so that sledgehammering will orient all last layer edges as you insert the last pair (if you have two misoriented edges).

Thanks. Does this also mean that youll only really need ZBLL if you use Petrus or ZZ?
 
Sorry for asking, im not familiar with this. How do you orient corners during or before F2L? Using Petrus or ZZ method? Sledgehammering pairs?
Well, I am sub 30 and use CFOP. I am learning PLL so I was wondering what to learn afterwards. COLL or OLL? I think I could learn edge control to orient edges.
 
Sorry for asking, im not familiar with this. How do you orient corners during or before F2L? Using Petrus or ZZ method? Sledgehammering pairs?

To orient "corners", you can use Winter/Summer Variation or Rowe Last Slot. You can also use Human Kociemba and other Redux methods. Certainly, you mean "edges."

To orient edges during CFOP F2L, you incorporate F moves while solving pairs to change the orientations of certain pieces. After investing a few extra moves during F2L, you will be left with a LL case with the cross already formed on top, vastly decreasing the number of possible LL states.


Thanks. Does this also mean that youll only really need ZBLL if you use Petrus or ZZ?

Yes, and if you invest just another move or two, you can "phase" the LL edges such that opposite LL edges are opposite of one another (but not necessarily correctly solved). That will reduce the number of LL states by a factor of 3 from 493 to 167. And if you "phase" the edges in such a way that you completely solve the LL edge permutation, (which only takes ~5 moves at the end of F2L), you can reduce the LL to 84 cases known as L4C. Many of these cases are just commutators, pure corner orientations, and 2LOLLs that you should already know.

Well, I am sub 30 and use CFOP. I am learning PLL so I was wondering what to learn afterwards. COLL or OLL? I think I could learn edge control to orient edges.

If you do ~100 solves with Petrus, you won't need to "learn" edge control at all. It will become second nature.

Realistically, you should first learn OLL if you solve with standard CFOP.
 
To orient "corners", you can use Winter/Summer Variation or Rowe Last Slot. You can also use Human Kociemba and other Redux methods. Certainly, you mean "edges."

To orient edges during CFOP F2L, you incorporate F moves while solving pairs to change the orientations of certain pieces. After investing a few extra moves during F2L, you will be left with a LL case with the cross already formed on top, vastly decreasing the number of possible LL states.




Yes, and if you invest just another move or two, you can "phase" the LL edges such that opposite LL edges are opposite of one another (but not necessarily correctly solved). That will reduce the number of LL states by a factor of 3 from 493 to 167. And if you "phase" the edges in such a way that you completely solve the LL edge permutation, (which only takes ~5 moves at the end of F2L), you can reduce the LL to 84 cases known as L4C. Many of these cases are just commutators, pure corner orientations, and 2LOLLs that you should already know.



If you do ~100 solves with Petrus, you won't need to "learn" edge control at all. It will become second nature.

Realistically, you should first learn OLL if you solve with standard CFOP.

Thanks for making it clear for me. Id rep you if i could :)
 
sicnce i am white-yellow cross solver, if i replace (for example)my oranges stickers with black stickers can it be easier to be 3color cross solver?
have someone ever tried that?

probably the most stupid question in this thread but who cares
 
sicnce i am white-yellow cross solver, if i replace (for example)my oranges stickers with black stickers can it be easier to be 3color cross solver?
have someone ever tried that?

probably the most stupid question in this thread but who cares
Not a stupid question. I would not imagine it being any easier, as one of the problems with lookahead during colour neutral solves when making the transition from not colour-neutral is the identification of F2L edges, and by changing the cross colour this is not made any easier.
 
Status
Not open for further replies.
Back
Top