Consider the following. L6E for Roux, orientation does not matter, just permutation. the L&R edges are in DB and DF, in no particular order. Centers can be in any order. How many positions are there?
I tried doing it like this; The L&R edges could be positioned in 1 of 2 ways. Centers are 4. U layer edges have 12 possible positions. So a total of 96. It should be 48, where am I going wrong?
I don't think anyone answered this, and I'm probably not right here, but I'll throw in what I see. You said "the L&R edges are in DB and DF, in no particular order.", implying that their position is negligible in the positions, but then factored in the 2 to the final number. Unless I'm misunderstanding the question, that would be your 96? Or I'm just an idiot, either one.
But then wouldn't that also mean that he shouldn't count the centers according to how he worded it?
Either way, it doesn't matter because you could do this another way, saying that the number of permutations of the edges on U is 4! (disregarding parity), and the number of permutations of centers is 4, and since that determines the permutation of the edges on D (because there are only two, and the total permutation parity has to be even), it would be 96.
I'm confused too :confused: