Welcome to the Speedsolving.com, home of the web's largest puzzle community! You are currently viewing our forum as a guest which gives you limited access to join discussions and access our other features.

The probability of getting double parity 5 times in a row, though (if the probability of getting it once is actually 0.25), is 0.0009765625. That doesn't happen very often.

OLL:
First 3 corners have 3 orientations that can occur (so 3x3x3 possible) and these orientations determine the orientation of the last corner so 1/27

PLL:
If you ignore auf for now (simplifies but gives same result) then you fix the first corner, you can then place 3 corners in the spot adjacent then two in the diagonal spot and only one left in the last spot. So you have 1x3x2x1=6 positions ignoring auf and only one of those is a skip. If you incluse auf then you just have 4 times as many combinations but you then divide by 4 for chance of skip

Just took all the stickers off my new Weilong and i tried wiping off the residue but now its really sticky and I think there may be a bit of it that got inside the cube. What should I do to get it off?

Just took all the stickers off my new Weilong and i tried wiping off the residue but now its really sticky and I think there may be a bit of it that got inside the cube. What should I do to get it off?

The residue comes off if you just rub it with your fingers. You can also try wiping it off with a paper towel. Diassemble the cube to make sure there is no sticky residue between the pieces on the contact points.

How can I save csTimer for offline use? If I save the webpage and disconnect the internet, I can use the timer, but I can't view scrambles, or use the EOLine solver, etc.

Just took all the stickers off my new Weilong and i tried wiping off the residue but now its really sticky and I think there may be a bit of it that got inside the cube. What should I do to get it off?

On 4x4, for 3-2-3 edge pairing, sometimes I finish the first 3 edges and notice that a fourth has coincidentally been made, resulting in the four remaining broken edges being in the top layer. Is there a quick way to solve these four edges? The way I do it seems awkward and lengthy.

On 4x4, for 3-2-3 edge pairing, sometimes I finish the first 3 edges and notice that a fourth has coincidentally been made, resulting in the four remaining broken edges being in the top layer. Is there a quick way to solve these four edges? The way I do it seems awkward and lengthy.

In that situation, I usually do 1-3. I used to do a similar thing if an edge had been made during centres+cross (do 2-2-3), but now I insert it into the F2L and use it as my first edge for 3-2-3.

On 4x4, for 3-2-3 edge pairing, sometimes I finish the first 3 edges and notice that a fourth has coincidentally been made, resulting in the four remaining broken edges being in the top layer. Is there a quick way to solve these four edges? The way I do it seems awkward and lengthy.