Renslay
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why are step 3-4 of Roux faster then finishing f2l(pairing and placing F and B edges)+OLL+PLL?
it seems that oll+pll is the fastest way to do LL and placing those 2 edges is really fast when you pair them like you would do 4B(with more freedom since the U layer isnt completed at all so that you dont need to orient them first).Also the recognition, for every steps seems easier (e.i placing the 2 edges doesnt touch the corners orientation making the oll recog very quick). So how is that slower than CLL+L6E?
thanks!
And for me it seems that finishing F2L + OLL + PLL is much slower than CMLL + L6E in most cases. And requires much, much more moves. CMLL and OLL are nearly the same (move counts, number of algorithms, zero-time-recognition, etc.) The recognition and the movecount of the PLL and the L6E is again, nearly the same (e.g., recognize the PLL from 2 side is nearly as hard/easy as a one or almost one look L6E). Plus, every L6E case is finger/fingertrick-friendly (unlike PLL-s like N-perms). So placing DF and DB edges seems unnecessary for me. Of course there are cases when it is easier (e.g., DF or DB or both are already solved), but those are rare.