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can you tell me which blue edge would be easiest to flip, and how? sorry, i'm a newbie!! :p

All of them would be equally easy to flip; you're just taking the piece out and putting back in the other way lol. But flipping the blue-yellow edge would result in an easier last layer to finish for you. Just turn the blue side about 45 degrees, and then pry the edge piece out of the cube. Then pop it back in so that the blue sticker would be next to the blue center.
 
I'm new to the 4x4 (about 10 solves up to parity) and I have a newb question. I already know 3x3. So far I've intuitively learned to solve centers and edge pairing except for when I only have two pairs left. I haven't learned how to deal with parity yet.

My question:

I solve white and yellow centers first then add the remaining 4 centers. I sometimes put the last four centers in the wrong position (twice out of 10 attempts) Is there an alg that swaps two centers wether adjacent or opposite while preserving edge pairs? Or should I just keep practicing until I never make that mistake?
 
I'm new to the 4x4 (about 10 solves up to parity) and I have a newb question. I already know 3x3. So far I've intuitively learned to solve centers and edge pairing except for when I only have two pairs left. I haven't learned how to deal with parity yet.

My question:

I solve white and yellow centers first then add the remaining 4 centers. I sometimes put the last four centers in the wrong position (twice out of 10 attempts) Is there an alg that swaps two centers wether adjacent or opposite while preserving edge pairs? Or should I just keep practicing until I never make that mistake?

If two centers are adjacent and need to be swapped, I do: Rw U2 Rw Lw' U2 Lw (start with centers on top and in front)
If two centers are opposite and need to be swapped I do: Rw2 U2 Rw2 Lw2 U2 Lw2 (start with centers on top and in front)

With some practice, this will usually never happen. Or you could be like me, and always solve the last four centers in the same order. :p
 
I'm new to the 4x4 (about 10 solves up to parity) and I have a newb question. I already know 3x3. So far I've intuitively learned to solve centers and edge pairing except for when I only have two pairs left. I haven't learned how to deal with parity yet.

My question:

I solve white and yellow centers first then add the remaining 4 centers. I sometimes put the last four centers in the wrong position (twice out of 10 attempts) Is there an alg that swaps two centers wether adjacent or opposite while preserving edge pairs? Or should I just keep practicing until I never make that mistake?

If two centers are adjacent and need to be swapped, I do: Rw U2 Rw Lw' U2 Lw (start with centers on top and in front)
If two centers are opposite and need to be swapped I do: Rw2 U2 Rw2 Lw2 U2 Lw2 (start with centers on top and in front)

With some practice, this will usually never happen. Or you could be like me, and always solve the last four centers in the same order. :p

For opposite swaps you can just do M2 Uw2 M2 Uw2. It doesn't matter which way you hold it, cause any two opposite swaps will make it solvable, but it swaps F and B.
 
So i'm using the CCT timer and i need to know what direction a z cube rotation is.....and maybe all the other ones too:rolleyes:
 
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