The New Method / Substep / Concept Idea Thread

Filipe Teixeira

Member
For step 2 recognition? Well you have both white and yellow edges on both layers, so you would have to recognize the specific orientation case (ie. what patter of white/yellow on the top and what pattern on the bottom) as well as permutation. For the number of cases (600+ if I'm not mistaken) learning all of that would be extremely difficult. So to answer your question, I think yes.
(White/yellow can be replaced by green/blue or orange/red, I just used this for clarity)
edges?

nice, Miranda!

ImmolatedMarmoset

Member
I'm not sure if I've ever proposed this method on this thread before, but I might as well do it now. The method utilises CP during FB just as Briggs 1 and 2 both use and is similar to Roux, but the main thing about this method is that to know it in its entirety you need 28 <RU> algorithms, with one of the algorithms simply being an R and the longest being 11 moves. The steps are as follows:

1. CPFB, 9 moves
2. Triplet at DR. This consists of an E slice edge being placed at DR with 2 corners orientated relative to it, 5 moves.
3. Orientation belt. This is where the algs come in (they require the other E slice edge to be orientated on U), 9 moves.
4. SB while preserving orientation. This uses <R2MU>, 8 moves.
5. LSE, exactly the same as Roux, 13 moves.

Average movecount≈44. Please tell me if any of my numbers are incorrect.
You can find the algs here.
In terms of speedsolving viability, it's a solid maybe. I don't see anyone getting fast with it or bothering to learn it and I also don't see people pushing it to its limit, but I like it.
I think I’ll learn it at some point and see how it is, thanks!

Anthem

Member
Does anyone know a website were u could make like Ortega algs 4 3x3

Anthem

Member
so like oll but with some yellow edges in the middle layer

Anthem

Member
and pbl 4 3x3 , just an idea

efattah

Member
The Ortega method already exists for 3x3 and there is a website for it. Also you can look in the LMCF document which is a superset of the ortega method. It's not what you're thinking though.

Anthem

Member
thank you can you give me the website

Anthem

Member
but i am talking about the whole face including gedges

WoowyBaby

Member
@Anthem Can you please use only 1 or 2 posts instead of 5? You know you can put more than a sentence into one post, and if you forgot to say something you can just edit your post and add it. I really hope I'm not sounding rude

As with your 3x3 Ortega idea, I'm just not sure what you're trying to say, tbh I don't think anyone does, if you want to explain it more that'd be great.

Aerma

@WoowyBaby I think he means like you solve one side and then do an alg to get the opposite side and then do an alg to solve the rest?
@Anthem If my interpretation of your method is correct, the number of algorithms would be ridiculously high, far too many for a human to be capable of. I image the algs for that OLL step would also be pretty poor... if you still want to be able to generate algorithms, look into the program Cube Explorer.

Anthem

Member
THANK YOU exactly, but I don't think it would be much more than full zbll

PapaSmurf

Member
For PLL there are 44 cases including 'parity'. For PBL there are (44^2)/2 cases (divided by 2 as you can't have parity on only one layer). That is 968 algorithms. ZBLL is 493.
To explain the parity bit, there are 44 ways to arrange the PLL pieces if you take them out of the cube and put them in again (as you can have 2 pieces swapped unlike normally). On the U layer for every PLL case on D you can have one of 44 PLLs. That means that you have 44^2 PLLs, but remember that this is just taking the pieces out, so you have to divide by 2 to take that into account. What it seems that you're suggesting is that but with 4 extra edges, so it is definitely not humanly viable. PBL is stretching it.

Anthem

Member
Ok thanks, but could there be 2 or 4 look pbl to make sure there are less algs

Skewbed

Member
Ok thanks, but could there be 2 or 4 look pbl to make sure there are less algs
For 2 look PBL, you could do PLL+Parity, then rotate to the other side and do PLL.

What method would this be for? Domino reduction? Belt?

Anthem

Member
Basically you solve the first layer unpermuted an then the last layer with oll than pbl so somewhat like Ortega for 3x3

Skewbed

Member
Basically you solve the first layer unpermuted an then the last layer with oll than pbl so somewhat like Ortega for 3x3
In that case, to reduce the algs, you can solve the first layer into a valid PLL to not have parity.

CFOP is better though.

PapaSmurf

Member
Just look at SSC for the best way to get to the "PBL" state, then do CP then EP.