Z
Zubin Park
Guest
I'll be completely honest: learning x amount of algs and countless hours of dedication, practice, and hard work... for a sub-2 2x2 solve? I'm not cut out for this lol
This is just basically biggeners because you almost always have atleast 1 oriented corner during first layer, which you could make the tripod peiceTripod on a 2x2. LOL feel free to scream at me.
3/4 of a layer
tripod piece
without disrupting the tripod piece, solve the rest of the first layer
solve the last layer with 1 or 32(?) algorithms
this wasnt on any list of 2x2 methods i could find lol. I am calling it Tripod-2
Look at my post i said it was bassically the beggeners method/lbl because like i said you normally almost always have one top edge solved and you said you COULD do it with one alg, anyway this is just a worse form of LBL+CLL because it barely has less algs+you have to preserve a corner during first layerView attachment 13940View attachment 13939
Just like tripod on a 3x3 except it is on a 2x2. And no it isnt a beginners method. What kind of beginners method on a 2x2 would have 32 algs (dont answer this)?
Edit: Example Solve
Scramble:F2 R U2 F' U2 F' R2 F2 R'
U F L // Tripod 1st Layer
y2 R U2 R' // Tripod Piece
U y L F' L' F L F' L' F L F' L' F // rest of first layer
y R U R' U' R' F R F' // T2LL (Tripod 2 Last Layer)
U2 // AUF
alg.cubing.net
alg.cubing.net
Not a good solve but it was somethin. 9.33TPS or more would be a sub-3 solve.
View attachment 13940View attachment 13939
Just like tripod on a 3x3 except it is on a 2x2. And no it isnt a beginners method. What kind of beginners method on a 2x2 would have 32 algs (dont answer this)?
Edit: Example Solve
Scramble:F2 R U2 F' U2 F' R2 F2 R'
U F L // Tripod 1st Layer
y2 R U2 R' // Tripod Piece
U y L F' L' F L F' L' F L F' L' F // rest of first layer
y R U R' U' R' F R F' // T2LL (Tripod 2 Last Layer)
U2 // AUF
alg.cubing.net
alg.cubing.net
Not a good solve but it was somethin. 9.33TPS or more would be a sub-3 solve.
ZZ that reduces LL to H? This has been thought of many times before and its better off to use TUL if you want to reduce ZBLL during LS.Hi. The H method uses few algorithms. Two examples:
D' F2 U' B2 F2 D2 U' L2 D2 R2 B' L B2 F2 R B' U' F L R2
z2
F2 U L R' F L R' D
U L' R' U' R2 U2 L U2 R
U2 L U L U L2 U L U' L // LS
R U2 L' U' L U2 R' // HLS
U R' F' R U2 R U2 R' F U' R U' R' // COLL
U2 M2 U' M' U2 M U' M2 U' // EPLL
D' R2 U R2 U2 B2 F2 U F2 L2 U' F' D2 L' B' F2 D' B R2 B R2
z2
L' B' U L' D' F
U2 R2 U2 R U2 L R2 U2 L2 U' L'
U R U' R U2 R2 U' R2 U' R' U // LS
U R U2 R' // HLS
R' F' R U2 R U2 R' F U' R U' R' // COLL
U2 M2 U M' U2 M U M2 U // EPLL
ZZ that reduces LL to H? This has been thought of many times before and its better off to use TUL if you want to reduce ZBLL during LS.
It would be alright I guess. It isn't too hard to do for R U' R' cases. You need insert, sexy insert, insert with U2, inverse sexy insert with U2.
There’s not a lot to develop, it’s all pretty much in that post.
All the algs to gen are in that post.by develop i mean gen algs
yea mean 2Do you mean last 2 pairs? Still, is probably worse than HK.
All the algs to gen are in that post.