one user said:

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http://www.speedsolving.com/forum/threads/the-fmc-thread.13599/page-209)

do EO Line and put E slice edges in the slice disregarding permutation, orient all corners, and solve as a domino. However, I am having a hard time optimizing domino so here's a solution up to that state if you guys would like to help me out. Thanks!

Scramble: F2 U' R2 U L2 U B2 D F2 L2 D2 F D' R' D2 L U' F' U L2 D

F' R' U B' R' U// EO with domino style belt (6) **solved belt unintentional

R2 L2 D' R' L2 U' D' R D2 R'// Corner Orientation (domino redux) 10/16

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another user said:

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http://www.speedsolving.com/forum/threads/the-fmc-thread.13599/page-209)

If you switch to the invserse scramble, you can do

(U' L2 D' U' R2 U L2 U R2 U) which leaves 3 corners. I'd ask

@Attila for domino advice.

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Attila said:

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http://www.speedsolving.com/forum/threads/the-fmc-thread.13599/page-209)

So, in my opinion, such a random domino reduction, will not be finished with a few moves.

I tried many random domino scrambles,and the average movecount around 13-14 (optimal with CE). The average human solution is obviously more than that.

That's why we need some trick, that reduces the 2nd phase movecount.

I'll explain in more detail, as I usually solve.

In the next logical order:

1st: solve all corners in 2 phase, orient first, then permute with domino moves

2nd: orient corners and solve a few edges (as much as possible)

3rd: swith to inverse, and permute corners (while caring for the existing ce-pairs)

4th: swith back to normal scramble, with inverted permutation moves

5th: orient corners again (here you can see clearly where the edges are to be moved)

6th: orient the remaining edges with Roux-style LSE algs

7th: solve the 5th and 6 step, without inverted premoves

8th: permute corners on normal (and it will be solved all edges).

Let's look at an example using your actual scramble:

F2 U' R2 U L2 U B2 D F2 L2 D2 F D' R' D2 L U' F' U L2 D

1st: D' R B' U' B U R2 D R2 D' F2

2nd: U F' B R2 B L' D' L orient corners and 4 edges,

3rd: switch to inverse with premoves L' D L B' R2 B' F U'

(F2 D R2 D' L2 U') permute corners,

4th:swith to normal with premoves U L2 D R2 D' F2

5th: U F' B R2 B L' D' L orient corners and 4 edges,

6th: L2 U' D' L B' U2 D2 F R' 2 more edges (exceptionally, the last 2 edges will be solved later)

7th: U F' B R2 B L' D' L-L2 U' D' L B' U2 D2 F R' orient corners and 6 edges,

8th: D2 B2 U2 - F U D' L' - D' B2 D F2 D' L2 D U' domino 2nd phase, with inserted F U D' L' moves.

Final solution: U F' B R2 B L' D' L' U' D' L B' U2 D2 F R' D2 B2 U2 F U D' L' D' B2 D F2 D' L2 D U' 31 moves.

I hope this is useful, if there is any question, I can help, if I can.

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another user said:

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http://www.speedsolving.com/forum/threads/the-fmc-thread.13599/page-209)

I don't understand the purpose of step 1? You don't seem to use it later on in your solution.

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Attila said:

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http://www.speedsolving.com/forum/threads/the-fmc-thread.13599/page-210)

1st step : D' R B' U' B orient corners

2nd step: instead of D' R B' U' B, I do d M' D2 r B' U' B /U F' B R2 B L' D' L without rotations/ 4 edges solved,

3rd step: instead of ( F2 D R2 D' R2 U') , I do (F2 D R2 D' L2 U') save ce-pairs.