Blindsolving Discussion and Help

Julian said:
First you would memorize FL, because that's the first target.
Now you have your buffer piece, so shoot to any unsolved target. In my lettering scheme, "A" is UL, so that would be next.
After that, the targets go RF, BR, FD, UB, FU, DB, UL.
Now you have your buffer piece again. Now I would shoot to DR ("D"), because A, B, and C are all solved.
After that, the targets go LD, LB, RD.

So the final edge memo is FL UL RF BR FD UB FU DB UL DR LD LB RD.
Click to expand...
thank you so much. :) this helped a lot! (this would have parity right?)
 
minime12358 said:
Ok, chris, I have to ask this, Ive been wondering for a long time: how do you picture a genderless singular pronoun???
En : en (genderless singular pronoun)

Im sticking with 5 hour energy....
Click to expand...

I picture the aliens described in the Poul Anderson story Starfarers :) In the story these aliens have no gender, so when referring to one of them in the third person humans will say "en" rather than "it" because of the psychological implications. It looks kind of like the snail creature from the Star Wars Cantina scene actually, at least how I picture it when I read it.
 
So, I was thinking about this concept for BLD, except that it wouldn't work, unless someone came up with a way to fix it.

Here it is:

I learned Ortega recently, and thought about how the history of it is that it originally started as a corners first 3x3 method. I grabbed my 3x3, and solved the corners like the Ortega method. I found this much faster than what I use for BLD, Old Pochmann. However, the only problem was the edges getting mixed up, so there would be no proper way to solve them. However, for corners, I was thinking that the concept to memorize and solve them would be sort of like Speed BLD, except there would be an easier way to it. Once again, the only problem is the edges getting mixed up.

My question to you guys is, would there be any way to somehow memorize the position of the edges, then just do a regular BLD solve, using Ortega for corners? I'm not looking for "memorize the edges like Speed BLD".

I know that this would not evolve as a BLD method, but tell me your thoughts.
 
JyH said:
So, I was thinking about this concept for BLD, except that it wouldn't work, unless someone came up with a way to fix it.

Here it is:

I learned Ortega recently, and thought about how the history of it is that it originally started as a corners first 3x3 method. I grabbed my 3x3, and solved the corners like the Ortega method. I found this much faster than what I use for BLD, Old Pochmann. However, the only problem was the edges getting mixed up, so there would be no proper way to solve them. However, for corners, I was thinking that the concept to memorize and solve them would be sort of like Speed BLD, except there would be an easier way to it. Once again, the only problem is the edges getting mixed up.

My question to you guys is, would there be any way to somehow memorize the position of the edges, then just do a regular BLD solve, using Ortega for corners? I'm not looking for "memorize the edges like Speed BLD".

I know that this would not evolve as a BLD method, but tell me your thoughts.
Click to expand...

I think Mátyás Kuti did some of his "blindfold" solves like this!
 
JyH said:
So, I was thinking about this concept for BLD, except that it wouldn't work, unless someone came up with a way to fix it.

Here it is:

I learned Ortega recently, and thought about how the history of it is that it originally started as a corners first 3x3 method. I grabbed my 3x3, and solved the corners like the Ortega method. I found this much faster than what I use for BLD, Old Pochmann. However, the only problem was the edges getting mixed up, so there would be no proper way to solve them. However, for corners, I was thinking that the concept to memorize and solve them would be sort of like Speed BLD, except there would be an easier way to it. Once again, the only problem is the edges getting mixed up.

My question to you guys is, would there be any way to somehow memorize the position of the edges, then just do a regular BLD solve, using Ortega for corners? I'm not looking for "memorize the edges like Speed BLD".

I know that this would not evolve as a BLD method, but tell me your thoughts.
Click to expand...

There is no efficient, fast way to memorize the changing permutation of the edges, and that is why no one does this. I highly doubt that there is a good enough system.
 
Does anyone use commutators for 4x4 edges? If so, what do you use for parity? Right now I use:
Setup so they are "paired"
pure oll parity
x' (180 U center turn which is R U R' U' *5) x
undo setup. Im sure there is a better way though.
 
minime12358 said:
Does anyone use commutators for 4x4 edges? If so, what do you use for parity? Right now I use:
Setup so they are "paired"
pure oll parity
x' (180 U center turn which is R U R' U' *5) x
undo setup. Im sure there is a better way though.
Click to expand...

Are you solving edges before solving centers? I personally solve edges last so that I can use the parity algs without having to also rotate center groups.

If you are solving centers after edges then either do what you're doing, or also use this alg with setups as well:
l' U2 l' U2 F2 l' F2 r U2 r' U2 l2

On a supercube this alg will rotate the U layer center group 180 degrees, so you would need to rotate it back like you are doing now.
 
hey chris, I am indeed solving edges after centers (I have never understood why you wouldnt solve centers first...) However, with setup moves, the 180 degree turn of the U face will result in the centers being messed up... Maybe there is an easier way? (As your post indicates that you dont rotate the centers, I would assume so)

EDIT: Ohh I didnt try the algorithm! Thank you, this will help greatly.
 
Last edited:
Has anyone experimented with doing something like this: d' r d r' (Which is 2 3 cycles on F R U and L B D) (Bunch of outer turns) r d' r' d ? Id imagine that that might be very efficient, however For some reason I can't think how that would work
 
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