The New Method / Substep / Concept Idea Thread

[Skewbed]

Doesn't COALL only work if the pair is already paired(like VHLS instead of ZBLS)?

In that comparison, it would be the equivalent of ZBLL. It is the last layer subset. You can get to it whether or not you already have a pair made.

 

[Pyjam]

Matthieu Aubert uses COALL.
He's well known under the nickname "Cubeur Manchot" (one-arm cuber, or is it penguin cuber?)
His algs: COALL d'un Manchot

 

[Pyjam]

So, this new and improved method I have goes like this:
- First Block
- Second Block
- EO + Stock ULUR (or UFUB)
- CLL (similar to COLL)
- Good L4E (easy M-slice)

Very similar to Pinkie Pie. Isn't it?

 

[brododragon]

Found something cool on gear ball. Is for the most common method. If don't know what that is, it's this:
1. Solve the pluses
2. Solve the gears + Solve a slice (Happens naturally)
3. Solve edges
4. Oreint gears

Right before step 3, This should be what your F face looks like:
Instead of working spamming R U until it's solved (What you would normally do), you can do this alg: L' U' R' D' L' U'. You also don't really have to memorize it. It's just a kind of circle and a half movement.

 

[ari(a cuber)]

just an idea, i average 40 seconds but i'm a roux noob, so who knows, it might be good
roux+ fildrich
1. first block
2. second block
3.coll
4.eo
5. orientate and permute edges on top and bottom side using m and u

 

[ImmolatedMarmoset]

just an idea, i average 40 seconds but i'm a roux noob, so who knows, it might be good
roux+ fildrich
1. first block
2. second block
3.coll
4.eo
5. orientate and permute edges on top and bottom side using m and u

That is roux.

 

[PetrusQuber]

just an idea, i average 40 seconds but i'm a roux noob, so who knows, it might be good
roux+ fildrich
1. first block
2. second block
3.coll
4.eo
5. orientate and permute edges on top and bottom side using m and u

Well, as stated above, that’s Roux... First Block and Second Block is the same. Then we have COLL, which is CMLL, but restricted by preserving top cross edges and F2L. Then EO and MU to solve edges - that is how you do LSE, if I’m not mistaken.

 

[Cubinwitdapizza]

just an idea, i average 40 seconds but i'm a roux noob, so who knows, it might be good
roux+ fildrich
1. first block
2. second block
3.coll
4.eo
5. orientate and permute edges on top and bottom side using m and u

I think you might be doing roux like this:
FB
SB
Bottom line
CFOP LL
This is what I thought roux was at first and then I learned, that’s not what it is.
Also, roux has absolutely no Fridrich vibes what so ever.

 

[Deleted member 51471]

Allrighty, I got this idea for a petrus variant :

1. 2x2 in back
2. 223 in back
3. EO from front, (front determines the orientation of the E edges, like in ZZ)
4. Left and right F2L pairs
5. COLL
6. L5EP
This could be good since you don't have to rotate, you have more ergonomic 22 and 223s, you get to orient 4 edges at a time instead of 2, and you have less pieces to solve after EO.

 

[ProStar]

Allrighty, I got this idea for a petrus variant :

1. 2x2 in back
2. 223 in back
3. EO from front, (front determines the orientation of the E edges, like in ZZ)
4. Left and right F2L pairs
5. COLL
6. L5EP
This could be good since you don't have to rotate, you have more ergonomic 22 and 223s, you get to orient 4 edges at a time instead of 2, and you have less pieces to solve after EO.

Wait, last 5 edges? Am I missing something?

 

[Deleted member 51471]

Wait, last 5 edges? Am I missing something?

It's like an edge PLL except with the DF edge taken into account. Nothing big, just 12 extra algs.

 

[ProStar]

It's like an edge PLL except with the DF edge taken into account. Nothing big, just 12 extra algs.

Oh, you don't do the last cross edge.

 

[WoowyBaby]

Yes, @ProStar , last five edges.

Here's what a solve with @WarriorCatCuber 's method might look like:

Scr: L2 U2 B D2 R F2 R2 U' F2 U2 B' L2 U2 L2 U2 B' D2 F L2 R'
(y2)
L' D2 R U2 B2 // 222
F U2 R2 U R D R' D' // 223
L' U2 L F // EO
U2 L' U L F2 U' F2 U F2 // 2P
U2 l' U' L U R U' r' F // CLL
U' R2 D r2 B2 R2 D r2 B2 U2 // L5E
(45)

Overall, I think it is a great method! Only has about 50 algorithms and has great lookahead because the 2x2x3 is totally in the back, differently than petrus. I like this!

 

[ProStar]

Yes, @ProStar , last five edges.

Here's what a solve with @WarriorCatCuber 's method might look like:

Scr: L2 U2 B D2 R F2 R2 U' F2 U2 B' L2 U2 L2 U2 B' D2 F L2 R'
(y2)
L' D2 R U2 B2 // 222
F U2 R2 U R D R' D' // 223
L' U2 L F // EO
U2 L' U L F2 U' F2 U F2 // 2P
U2 l' U' L U R U' r' F // CLL
U' R2 D r2 B2 R2 D r2 B2 U2 // L5E
(45)

Overall, I think it is a great method! Only has about 50 algorithms and has great lookahead because the 2x2x3 is totally in the back, differently than petrus. I like this!

Petrus-B! Also, shouldn't it've been COLL instead of CLL? Because the edges are already oriented.

 

[brododragon]

Why not just do the last cross edge? 2-3 more moves for better recognition and less algs.

 

[Deleted member 51471]

Why not just do the last cross edge? 2-3 more moves for better recognition and less algs.

Last cross ege is tough in this method. Plus, you get to do F2 moves and M' U2 M, which helps a lot.

 

[brododragon]

Last cross ege is tough in this method. Plus, you get to do F2 moves and M' U2 M, which helps a lot.

You can just do a double flick with your pointer and middle finger.

 

[Deleted member 51471]

You can just do a double flick with your pointer and middle finger.

I know, but no cross edge helps a lot with freedom.

 

[ProStar]

What if one of the F2L edges is where the cross edge normally goes? How do I take that out without disturbing EO/The pair already there? Doing M' U2 M ruins EO

 

[Etotheipi]

Doing M' U2 M ruins EO

No it does nothing to EO.