Blindsolving Discussion and Help

minime12358 said:
:P Ok I'm going to start an FAQ on google docs, if anyone is interested in helping me, just let me know and I can add you. At the end, we can hopefully get a stickied thread. Im just saying cause I think that question has been asked like 3 times in the past 5-10 pages.

Orr If you really dont want me to, just let me know.
Click to expand...

I guess I'll help you. I'm bored.
BTW, I use OP corners, M2 edges.
 
JyH said:
You have parity. If you counted your Y-Perms in the beginning, you would have an odd number, so you would do the R-Perm after the corners were done. Then do all the edges, then do U' F2 U M2 U' F2 U, then the R-Perm.
Click to expand...

If you solve the corners first, you can just do U' F2 U M2 U' F2 U after the corners and your parity is fixed. That's what I do, anyway.
 
NeedReality said:
If you solve the corners first, you can just do U' F2 U M2 U' F2 U after the corners and your parity is fixed. That's what I do, anyway.
Click to expand...

Yes you can but I just do R perm (my R perm needs no rotation, and for 2x of them I can have both performed sub3 total) and then the parity alg, because I find it easier to know during each beginning letter of each object in my sentence has the M slice not off. I'm willing to sacrifice 3 seconds for a safer solve.
 
wait, what exactly is the advantage of using R perm?? I use the U' F2 U M2 U' F2 U alg. I still know whether the M slice is off or not. Why would you do ~30 unnecessary turns?
 
Rpotts said:
wait, what exactly is the advantage of using R perm?? I use the U' F2 U M2 U' F2 U alg. I still know whether the M slice is off or not. Why would you do ~30 unnecessary turns?
Click to expand...

No advantage, just did it to begin with and now I just do it. If I ever get sub1 I might just switch due to me being able to save 3 seconds, but it's just easier for my brain to know at this point during execution that the first letter per object/location is M slice not being off.
 
Hey, I was wondering if anyone had a commutator for 4x4: UbR to UbL to UfR

I have been unable to find one that isnt incredibly long. For instance, I could set it up like
x' d y R U2
and then do a regular commutator
y' u L' U L u' L' U' L y
And then undo to get
x' y d R U2 y' u L' U L u' L' U' L y U2 R' y' d' x
But... thats a long alg :P any ideas for a shorter one? Or is this simply a bad case.

and also, now looking, something is wrong with that.
 
minime12358 said:
Hey, I was wondering if anyone had a commutator for 4x4: UbR to UbL to UfR

I have been unable to find one that isnt incredibly long. For instance, I could set it up like
x' d y R U2
and then do a regular commutator
y' u L' U L u' L' U' L y
And then undo to get
x' y d R U2 y' u L' U L u' L' U' L y U2 R' y' d' x
But... thats a long alg :P any ideas for a shorter one? Or is this simply a bad case.

and also, now looking, something is wrong with that.
Click to expand...

If you're going BH move optimal, that case is 9 turns to solve. Look at how you would solve the corner cycle:
ULB -> BLD -> BRU

Same idea for your wing cycle
 
A B9 is an 8 mover with a setup where the setup cancels with the interchange. An A9 is where it cancels with the insertion. I'm pretty sure, for corners, that they're never optimal.
 
Wow, lots of BH discussion :)

two clarifications:
on 4x4x4 the cycle: UbR to UbL to UfR
is an A9 cycle.

And yes, on corners all B9 cases are actually optimal at 8 moves with a pure commutator. On other piece types there are cases that are optimal with a B9 alg.
 
cmhardw said:
Wow, lots of BH discussion :)
two clarifications:
on 4x4x4 the cycle: UbR to UbL to UfR
is an A9 cycle.

And yes, on corners all B9 cases are actually optimal at 8 moves with a pure commutator. On other piece types there are cases that are optimal with a B9 alg.
Click to expand...
Woops! I think I might have wrote it wrong :fp ( I Scribbled it on a piece of paper so that I could look at it after a test)
I believe the reverse though would be B9? (By that I mean Ufr to UbL to UbR)?
I definitely see the A9 in the one I originally wrote though
(y' r2) (r' B2 r) (F2) (r' B2 r) (F2) (r2 y)

And the reverse of the cycle would be:

(y' r2)(F2)(r' B2 r)(F2)(r' B2 r)(r2 y)

Is that correct?

Edit: Oh wait fail xD thats an A9 too, just in the form BAB'A'
 
Last edited:
minime12358 said:
(y' r2) (r' B2 r) (F2) (r' B2 r) (F2) (r2 y)

And the reverse of the cycle would be:

(y' r2)(F2)(r' B2 r)(F2)(r' B2 r)(r2 y)

Is that correct?
Click to expand...

These are swapped. It should be that:

UbR to UbL to UfR:
(y' r2)(F2)(r' B2 r)(F2)(r' B2 r)(r2 y)
Click to expand...

And the reverse: UbR to UfR to UbL:
(y' r2) (r' B2 r) (F2) (r' B2 r) (F2) (r2 y)
Click to expand...

Also, in case you're interested, I would execute these as:

UbR to UbL to UfR:
x u2 L2 u' R2 u L2 u' R2 u' x'

and

UbR to UfR to UbL:
x u R2 u L2 u' R2 u L2 u2 x'
 
Rpotts said:
wait, what exactly is the advantage of using R perm?? I use the U' F2 U M2 U' F2 U alg. I still know whether the M slice is off or not. Why would you do ~30 unnecessary turns?
Click to expand...

It depends on whether you solve corners or edges first. If you solve edges first, U' F2 U M2 U' F2 U is all that's necessary. If you solve corners first, you need to do the short fix followed by an R perm.
 
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