ProStar
Member
Since the phased edges are in the same orientation, the remaining two edges are in the same orientation as well. Thus there are 4 eo possibilities: f/b unoriented, l/r unoriented, all unoriented, and none unoriented. Thus the total number of algorithms will be exactly 4 times ZZLL, which is 169 algs. Thus this method has 4 * 169 + 6 = 682 algs, compared to ZB's 799. The f2l pair and phasing take less than 1 look, as they are simple and easy to plan through lookahead. Thus in reality, this method takes ~2.5 looks or less, if you understand what I mean. On the other hand, each of the steps of ZB have pretty complicated recognition, and will take 2 looks. Thus I think the total recognition time for my method and the ZB method will not be too different.
ZB doesn't have complicated recognition. It's probably easier than your method, although I can't say for sure.