You don't actually need all the letters though. Something I did when I created my letter scheme was to make Q my edges buffer so I don't need to use letter pairs involving Q :)

So how many letter pairs do you use in 3BLD?
 
I use around 550, I think. I mostly come up with them on the fly, so I am not too good yet. I need more practice, but you really don't need to memorize or make a list of all your pairs.

But isn't that insane? 550 words.
 
Yes, I thought that too. But they are often SUPER easy, such as AC (air conditioning), PN (porn), or OL (Oatmeal). They are easy enough to come up with in a second or two, even for beginners. It took me a while to get the hang of it, but now it isn't so bad!

Also, try downloading Anki, which you can then use to quiz yourself with your letter pairs quite easily!
 
Yes, I thought that too. But they are often SUPER easy, such as AC (air conditioning), PN (porn), or OL (Oatmeal). They are easy enough to come up with in a second or two, even for beginners. It took me a while to get the hang of it, but now it isn't so bad!

Also, try downloading Anki, which you can then use to quiz yourself with your letter pairs quite easily!

Where can I download that?
 
Just a suggestion if the terminology of solving stickers etc is too much to take in, perhaps try learning 3OP from here. It is a very old/inefficient method but it will present at least some advantages for you (PhD):

1. It gives you a summary of what blind solving is about
2. You memorize orientation and permutation separately, and both concepts are explained very clearly.
3. Memorization is doubled, but the nature of 3OP allows you to test out different memory methods for each piece type and for orientation/permutation separately. It also helps you to familiarize with memorizing.
4. Sub-2 times are perfectly feasible and sub-1 times are possible (as a previous user of this method this is true.)
5. You will get an idea of how cycles work and how to memorize them.

When you're able to solve the cube blindfolded on your own, then consider how to solve orientation and permutation together with half of the memory load (Old Pochmann, M2/R2, TuRBo or 3-cycles)
 
Just a suggestion if the terminology of solving stickers etc is too much to take in, perhaps try learning 3OP from here. It is a very old/inefficient method but it will present at least some advantages for you (PhD):

1. It gives you a summary of what blind solving is about
2. You memorize orientation and permutation separately, and both concepts are explained very clearly.
3. Memorization is doubled, but the nature of 3OP allows you to test out different memory methods for each piece type and for orientation/permutation separately.
4. Sub-2 times are perfectly feasible and sub-1 times are possible (as a previous user of this method this is true.)
5. You will get an idea of how cycles work and how to memorize them.

Thanks!
 
When you are shooting a piece to the middle layer in M2, and your M slice is not correct, do you memorize a different letter pair (for example, mine would be B instead of Q), or do you simply realize it when you are solving and you know that your second target in your letter pair should be "shot" to the opposite spot?
 
When you are shooting a piece to the middle layer in M2, and your M slice is not correct, do you memorize a different letter pair (for example, mine would be B instead of Q), or do you simply realize it when you are solving and you know that your second target in your letter pair should be "shot" to the opposite spot?
You memorize it as normal, recognize the m-slice being off during execution.
Or at least I've never heard of someone doing otherwise.

I think memo could get confusing if you weren't memorizing the pieces as they are.
 
When you are shooting a piece to the middle layer in M2, and your M slice is not correct, do you memorize a different letter pair (for example, mine would be B instead of Q), or do you simply realize it when you are solving and you know that your second target in your letter pair should be "shot" to the opposite spot?

You memorize the letter pairs normally. So just ignore the M-slice parity while memoing. And since you memo in letter PAIRS you automatically know if your M-slice is "correct" (when you are executing the first letter of the pair) or "wrong" (when you are executing the last letter of the pair).Then you just apply the correct alg for the case.

For example you memo pieces UF and UB in this order so you would do:
U2M'U2M' (alg to shoot to UF normally since the UF is first piece in the pair)
M2 (just shoot to UB)

thats simple. Now what if you memoed UB and UF after that? You would have to:
M2 (first shoot to UB)
now notice that your M-slice is off by M2 making the memoed UF sticker to beat DB locationsoyou need to shoot to DB insead of UF
MU2MU2 (shoot to DB)

hope this cleared it up
 
I want to try to move for something faster for corners (I am using OP for corners and M2 for edges).
I have heard about boomerang method (http://renslay.byethost11.com/boomerang.html).
Is it worth learning or better try to switch to commutators right a way?
My times are usually around 2:05-2:15 with some sub2 sometimes. I can do most commutators cases without blindfold and some thinking (usually over 30 seconds per case, but I started learning it recently)
 
I want to try to move for something faster for corners (I am using OP for corners and M2 for edges).
I have heard about boomerang method (http://renslay.byethost11.com/boomerang.html).
Is it worth learning or better try to switch to commutators right a way?
My times are usually around 2:05-2:15 with some sub2 sometimes. I can do most commutators cases without blindfold and some thinking (usually over 30 seconds per case, but I started learning it recently)

I think there is no point for you to learn boomerang. My main reasoning for this is that it has a pre-orientation step, and because of this, I think it would actually be easier to switch from OP to comms, than from boomerang to comms.

I would advise you to try and learn comms. I think that it isn't necessary to wait until you are sub 1. Try and force yourself to use them in solves and just use OP when you can't figure them out. Using a few comms can't hurt anyone.

However, I think that, at a 2 minute average, you should work really hard on you memo.
 
I want to try to move for something faster for corners (I am using OP for corners and M2 for edges).
I have heard about boomerang method (http://renslay.byethost11.com/boomerang.html).
Is it worth learning or better try to switch to commutators right a way?
My times are usually around 2:05-2:15 with some sub2 sometimes. I can do most commutators cases without blindfold and some thinking (usually over 30 seconds per case, but I started learning it recently)

If you are really ambitious, don't wait, learn commutators. It will be hard, so don't expect such improvement soon. But eventually it worths the effort.
 
3BLD: When I reach the buffer, and have to start a new cycle, I saw in NoahCubes tutorial he says I should touch the pieces that I've already solved. But what I don't understand about this is, when you start your new cycle how do you start your new letter pairs?
 
3BLD: When I reach the buffer, and have to start a new cycle, I saw in NoahCubes tutorial he says I should touch the pieces that I've already solved. But what I don't understand about this is, when you start your new cycle how do you start your new letter pairs?

So imagine you've solved your first few pieces, ABCD, and you've reached your buffer piece. I figure out that the pieces that are left are VWXYZ (and for the sake of this example, the last cycle is VWXYZ, so V needs to go to W etc.)

1. Choose any piece, solve it as normal. (V)
2. Solve the rest of the cycle (WXYZ)
3. Solve the FIRST piece at the end as well. (V[SUB]2[/SUB])

So you are solving that second cycle as (VWXYZV). If there are no other cycles/pieces that need to be solved, you've finished that piece set.
 
So imagine you've solved your first few pieces, ABCD, and you've reached your buffer piece. I figure out that the pieces that are left are VWXYZ (and for the sake of this example, the last cycle is VWXYZ, so V needs to go to W etc.)

1. Choose any piece, solve it as normal. (V)
2. Solve the rest of the cycle (WXYZ)
3. Solve the FIRST piece at the end as well. (V[SUB]2[/SUB])

So you are solving that second cycle as (VWXYZV). If there are no other cycles/pieces that need to be solved, you've finished that piece set.


How did you figure out the second cycle has to be VWXYZV? ( I know they are the pieces that are left ) but how do you start to count the new cycle? which sticker do you start to count letters from ?
 
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