Ninjascoccer
Member
Ya Ik this is just supposed to be a fun methodThis seems like (worse) 42 without the transformation bit and L7E can be done intuitively.
its not supposed to be taken that seriously
Ya Ik this is just supposed to be a fun methodThis seems like (worse) 42 without the transformation bit and L7E can be done intuitively.
If this was a real method, the italic text would be the hardest parts.solve top corners while preserving EO
Solve Midges in 1 look
Rotate and Solve S layer which is now the M layer 1 look
only solving Midges would be somewhat hard because you have to look at the bottom. the other two are easy. solving corners is just COLL and Solving S layer edges is just roux L4E or L3EIf this was a real method, the italic text would be the hardest parts.
yeah but what about preserving EO?only solving Midges would be somewhat hard because you have to look at the bottom. the other two are easy. solving corners is just COLL and Solving S layer edges is just roux L4E or L3E
LOL. COLL is the algorithm set to solve the corners and preserve EO.yeah but what about preserving EO?
Hopefully you know more than himI actually saw someone think of this method called EPCL (cubetycubes) but he turned it into a disaster lol.
how exactly lol?I actually saw someone think of this method called EPCL (cubetycubes) but he turned it into a disaster lol.
oh k.I'm pretty sure this columns first variant has already been mostly proposed by others but dismissed because it's bad. Lookahead sucks during F2L, COLL isn't that great of an algset, and solving midges has bad lookahead and is not ergonomic.
ohhh sorry i never learned COLL. I use roux.LOL. COLL is the algorithm set to solve the corners and preserve EO.
NP.ohhh sorry i never learned COLL.
COOLI use roux.
I've had this idea many times with different finishes. The thing that makes this method hard to make viable would be 6CO/6CP algs which generally aren't the best. (A lot of R2 and such.) Not a terrible idea.Alright, don't get angry with me for bringing up another method (fell free to call me dumb for inventing another method that already exists)
I came up with this in like 10 min.
Steps
Solve a 1x1x3 (should be connected to the centres) and place it in DL position
Belt
EO
6CO
6CP
Insert the cross edge that goes between the two corners on the right thus creating another 1x1x3. align both the 1x1x3s to their respective centres using u / u' / u2.
Solve LSE like Roux.
Here are some examples
B2 D F2 L2 D2 B2 R2 F2 U' B2 D' F' R B' L B2 F U2 R' U'
y' L2 U' L' // 1x1x3
R' U' R' u2 U R M R U R' M' // Belt
M2 U' M U' M // EO
U' R' U2 R U R2 U' R U2 R // 6CO
U' x U2 R' D' R U2 R' D R x' // 6CP
D2 // Roux F2B with EO and CMLL done
M' U2 M U M' U2 M2 U2 M' U // LSE
49 STM
U2 D' L D' B L2 F B2 U B' D2 R2 F2 L2 F2 D2 L2 B' U2 B' D2
x2 y L' B2 // 1x1x3
u' R2 u R2 u R // Belt
M' U' R2 U R' r' // EO
U D' R U R' U2 R U R' D // 6CO
U2 R2 D' R2 U R2 U' R2 U' D R2 U R2 // 6CP
M2 U' S' U2 S M2 u' // Roux F2B with EO and CMLL done
M U2 M U' M' U2 M' // LSE / L5E
51 STM
D' F' B D2 B U' B D2 L' B' L2 D2 F' L2 F L2 F' U2 L2 D2 B
F U' L' F2 y // 1x1x3
U' R u' U' R u' R2 r2 R U R' r2 // Belt
M R2 U' M r2 // EO
U' R' D' R U R' D R // 6CO
U' R U2 R' D' R' D R' D' R' U2 R' // 6CP
U2 M' U2 M D // Roux F2B with EO and CMLL done
U M' U2 M U x' U2 M U2 M' // LSE
55 STM
D' L2 R2 D F2 R2 D2 F2 L2 F2 R2 U F R B2 R2 D' B' F R' U
x2 F2 U F' // 1x1x3
u' U2 R' u2 R' U R' u' R U R' // Belt
U M2 U' M U' M // EO
R D' R U' R' D R' // CO
U F U F' R2 F U' F' U' R2 // 6CP
S' U2 S u2 // Roux F2B with EO and CMLL done
M U2 M' U' M2 U' M U2 M U' // LSE / L5E
51 STM
U L2 U' L2 R2 U' F2 L2 B2 D F2 U2 B' R' F2 L' U' B L2 U2 B' R'
y2 x D2 B U2 L // 1x1x3
u R' u2 R' U' R' u2 r2 B U2 B' r2 // Belt
M' U' M' U M U' M // EO
U' R2 U2 R' U R' U R U2 R' // 6CO
U2 F U F' R2 F U' F' U2 R2 // 6CP
S' U2 S u // Roux F2B with EO and CMLL done
M U2 M U' M' U2 M U2 M2 U2 // LSE
57 STM
U B2 F2 U2 B2 U' L2 U' R2 U2 L2 F' R U' F' D L' D B D2 F'
U B U' F2 // 1x1x3
r U' r' u U' R' u R u R U' R' // Belt
U' M2 U' M U' M // EO
R U' R' U R' U R' U' R // 6CO
R2 U' D' R2 U R2 U' R2 // 6CP
S' M' U M U2 S // Roux F2B with EO and CMLL done
U' M' U2 M U' // Somehow left with L3E
50 STM
F' L2 D2 L2 U2 F' R2 F' D2 F R2 B2 L U2 B' F R' D' F' D L
x' D2 L // 1x1x3
U' R2 U' R' u2 R2 U' R' // Belt
U R F R2 F' R // EO
R2 U2 R' U R' U2 R U R' // 6CO
U' R2 U R2 U R2 D R2 U' R2 U R2 // 6CP
D' // Roux F2B with EO and CMLL done
M' U2 M U M' U2 M2 U2 M' U' // LSE
48 STM
L' F2 D2 F2 U2 F2 R' B2 F2 R' F2 L' F' R U2 B' F' U' L' F U2
x' y U' L' // 1x1x3
u R u' R2 u' R U R' // Belt
U' F' L' F U F L F' D' // EO
U2 R U' R U2 R' U R' U R U R' // 6CO
U2 R2 U R2 U' D R2 U' R2 U R2 D' R2 // 6CP
S' M' U' M S u2 // Roux F2B with EO and CMLL done
M U2 M' U' M' U2 M U' // LSE
58 STM
U' L2 B2 D R2 B2 L2 F2 D2 U' R2 U2 F U' L D2 B2 D' B F' L
y2 U' B2 U2 F2 // 1x1x3
u R2 U2 R u2 U2 R2 M U R' M2 U' M // Belt + EO
R' D' R U' R' D R // 6CO
U2 D' R U' R' U2 D R2 U2 R2 D' R U R' // 6CP
D2 y M2 U2 M2 S' M' U M U2 S U' // LSE (But not Roux style)
49 STM
U2 F2 L2 D' B2 D F2 L2 U F2 R2 F2 L' B2 D' L U B2 D2 B' R2 F
x' y' R2 U L // 1x1x3
u' R2 u R2 u r' U r // Belt
U2 M' U' M // EO
U2 R2 U2 R' U R' U2 R U R' // 6CO
R2 U D R2 U' R2 U R2 // 6CP
y M2 U S' U2 S // Roux FB with EO and CMLL done
U' M2 U M2 U M' D2 M' D2 // LSE
47 STM
Average movecount = 51.5 STM
You mean this method is not a terrible idea?I've had this idea many times with different finishes. The thing that makes this method hard to make viable would be 6CO/6CP algs which generally aren't the best. (A lot of R2 and such.) Not a terrible idea.
I will work on that. I will probably leave L7EP for the end.EDIT: For example, you could ignore edges and leave L7E for the end with this approach. Things like that.
OkI would say this method is just a worse roux. Basically if you take out the pointless eo step in the middle and use dcal+cdrll to solve corners (better algs than 6CO+6CP) You have essentially just made up a different way to do SB.
But half belt being ~5 moves or less and DCAL being ~9 moves, it is not a terrible SB (although it is partial). 64% algorithmic as well.I would say this method is just a worse roux. Basically if you take out the pointless eo step in the middle and use dcal+cdrll to solve corners (better algs than 6CO+6CP) You have essentially just made up a different way to do SB.
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