# The New Method / Substep / Concept Idea Thread

#### fdskljgrie

##### Member
Nice! What do you average using it?

#### Triangles_are_cubers

##### Member
hey i thought about making a 4x4 method like meyer but instead of pairing edges like in yau, its like in hoya (cause i use hoya and wondered if it could work)

solve u/d centers
solve ur block center+ adj center (i usually do b center)
solve block edges like in hoya cross (and insert the block corners)
solve DR edge in the remaining slot
solve the 2 remaining centers (alternatively u could insert the block corners after this step for more freedom on this step)
pair edges (3-2-3)
put block on left, U2 R2 (solve DR edge) + 3x3 stage (roux)

is this a good method or could there be improvement?

#### PapaSmurf

##### Member
It's about as good as Meyer and Hoya on 4x4 and therefore suffers from the drawbacks they both have, and it's also not new (unfortunate, but is kinda expected with two common methods).

#### Xnightslayer99

##### Member
Funni Method might not be viable.
1. Make a Roux block
2. Turn it into a Petrus block
3. Do Petrus untill F2L-1 and do ZB For the rest
4. Alternatively finish F2L and do a ZBLL

#### Thom S.

##### Member
Do Petrus untill F2L-1 and do ZB For the rest
4. Alternatively finish F2L and do a ZBLL
In Petrus you always do EO then F2L. There's no need for ZBLS
Funni Method might not be viable
And also not new.

#### DuckubingCuber347

##### Member
Funni Method might not be viable.
1. Make a Roux block
2. Turn it into a Petrus block
3. Do Petrus untill F2L-1 and do ZB For the rest
4. Alternatively finish F2L and do a ZBLL
This is literally Petrus. Roux FB turning into "Petrus Block" is a 223. Petrus calls for building a 223, just like APB and Mehta. You get to that stage through the fastest way possible, your proposal is actually the recommended way for 223.

Also 3 and 4 don't make sense. If you do Petrus until F2L-1 then you don't need to do ZBLS (part of ZB) because EO is already done.

Very viable method, but it's not funny or original.

#### DuckubingCuber347

##### Member
So, here's another method idea:
1) Standard Roux FB on left
1.5) Solve the BR/BDR F2L pair.
2) Use keyhole to solve the rest of the first layer, minus DF and DFR pieces
2.5) Solve DFR while making sure FR edge is oriented - maybe 4 moves on average
3) EODF
4) CPLE - Corner permutation + last F2L edge, I'm pretty sure this has 12 algs (6 if you just mirror the others)
5) 2GLL

You could also do CPFB as the first step and adjust the other steps a bit to avoid having to recognize CP mid-solve.
Very cool idea, I think it's worth bumping. Have algorithms for CPLE been created?

#### mkt

##### Member
Neat idea; however, why force that case in particular? To me it seems like you came up with the name first and then built a method around it. Generally forcing an Anti-ZBLL is suboptimal.
thank you!
The main focus of this technique is the simplification of dot OLL.
It also has the potential to make your hated OLL a simple procedure.

Otherwise, choice OLL PLL.

This method is choice, not force.

#### levi.m

##### Member
here's the tutorial on my Rubik's cube method if you want speed solve it:

LBr

#### Skewbed

##### Member
I don't know if this has been proposed before, but if the recognition is worth it, you can conjugate OLL and PLL in CFOP.

Steps:
1. Cross
2. F2L-1
3. 1x1x2 in the U-layer (less moves than last pair)
4. Do an R/R' (depending on the location of the corner and the edge in the pair)
5. OLL
6. PLL
7. Undo the R/R'

Example Solve (regular CFOP would be faster for this one, but just an example):
L2 D' B2 F2 R2 D U2 R2 F2 U' B2 U R F2 U F' L' D2 R2 F U'

z2 // inspection
F' (R L) (B F2) // cross
R' U' R L' U2 L // 1st pair
y R U2 R2' U' R2 U R' U2 L' U' L // 2nd+3rd pair
U2 R' F R F' y' R' // setup psuedo-LL
M R U R' U R U2 R' U M' // OLL
U R' U2 R U2 R' F R U R' U' R' F' R' // PLL with cancellation

#### OreKehStrah

##### Member
I don't know if this has been proposed before, but if the recognition is worth it, you can conjugate OLL and PLL in CFOP.

Steps:
1. Cross
2. F2L-1
3. 1x1x2 in the U-layer (less moves than last pair)
4. Do an R/R' (depending on the location of the corner and the edge in the pair)
5. OLL
6. PLL
7. Undo the R/R'

Example Solve (regular CFOP would be faster for this one, but just an example):