How do I stay quieter while doing blind solves?

Whenever I solve(not that often), I'm always saying what I'm thinking out loud. It's gotten to the point where I need to do BLD solves in my room with the doors closed so I don't bother anybody.

Practice? There's no harm in mouthing the words, so just practice saying them soundlessly. Perhaps what that means is you need to do BLD solves in the company of others so they'll tell you to quiet down when you get too loud. It might be good feedback.
 
How do I stay quieter while doing blind solves?

Whenever I solve(not that often), I'm always saying what I'm thinking out loud. It's gotten to the point where I need to do BLD solves in my room with the doors closed so I don't bother anybody.

Please get into BLD! I would like BLD and MBLD at your next comp. ;)

On topic, yeah, I used to do the same thing, you'll find that as you get faster it will get easier to silence it.
 
How do I stay quieter while doing blind solves?

Whenever I solve(not that often), I'm always saying what I'm thinking out loud. It's gotten to the point where I need to do BLD solves in my room with the doors closed so I don't bother anybody.

Practice? There's no harm in mouthing the words, so just practice saying them soundlessly. Perhaps what that means is you need to do BLD solves in the company of others so they'll tell you to quiet down when you get too loud. It might be good feedback.

That's a good idea. I always said my memo but then someone told me it was illegal for comp. So I just did all my solves without talking. Not too bad.
 
That's a good idea. I always said my memo but then someone told me it was illegal for comp. So I just did all my solves without talking. Not too bad.

It's an interesting question whether or not it's illegal for a competition. There's this rule:
A5a) While inspecting or solving the puzzle, the competitor must not communicate with anyone other than the judge. Penalty: disqualification of the attempt (DNF).

but I could see a claim that you're saying it to the judge, or you're saying it to no one in particular, so you're not actually trying to communicate.

Then there's this rule, which is probably more applicable:
2k) The WCA Delegate may disqualify a competitor from the competition (i.e. from all events of the competition) if the competitor:
... 2k4) Interferes with, or distracts others during, the competition.

It's probably reasonable to argue that saying memo out loud distracts others, and so qualifies for this. If so, it's pretty serious - it would disqualify not just your BLD solve, but the whole competition. I guess I would argue that, since most BLD competitors use ear protection of some sort to block out noise, relatively quiet recitation of memo probably shouldn't qualify as a violation of this rule. And if it is a violation, in many cases I'd think you could disqualify lots of audience members for talking among themselves during BLD events.
 
Does anyone have suggestions on how to keep track of new cycles. For instance, I start memo for edges and I have 4 letter pairs done and need to start a new cycle, it takes me forever to backtrack my memo to see which edges haven't been memo'd yet. I can do corners pretty well, since there are only 8 pieces to keep track of, but with edges I get lost on where I need to start my new cycle.
 
Does anyone have suggestions on how to keep track of new cycles. For instance, I start memo for edges and I have 4 letter pairs done and need to start a new cycle, it takes me forever to backtrack my memo to see which edges haven't been memo'd yet. I can do corners pretty well, since there are only 8 pieces to keep track of, but with edges I get lost on where I need to start my new cycle.

That really comes with practice... I used to have the same problem, but now I just somehow "know" where I can start the new cycle.
Altough I currently have the same problem with 4x4 wings because there are 24 of them (mostly when there are 2-cycles in the end), but I hope that it will also get better with practice, and I just somehow start to remember what pieces I have already memoed....

Obviously as your memo gets faster it's easier to remember instantly what pieces have already been memoed
 
this might help
also you can post the scramble that you want and I'd be happy to post the solution for you :)

I would love that. Only I can not give the scramble, because I do not know how to reconize parity. I want a normal scramble solve, one with edge parity and one with corner parity. That is all what can happen right? Or do also corner plus egde parity exist?
 
I would love that. Only I can not give the scramble, because I do not know how to reconize parity. I want a normal scramble solve, one with edge parity and one with corner parity. That is all what can happen right? Or do also corner plus egde parity exist?
Parity = Odd number of edges and odd number of corners. There is no corner parity and edge parity, there is only one

Just give us a few scrambles and we will give you some solutions
 
I would love that. Only I can not give the scramble, because I do not know how to reconize parity. I want a normal scramble solve, one with edge parity and one with corner parity. That is all what can happen right? Or do also corner plus egde parity exist?

In 3x3 there is only one parity.

You see, the total number of 2 swaps needed to solve the cube must always be even (therefore its impossible to swap just 2 edges or just 2 corners).

In blindsolving it's called parity when edges AND corners have an odd number of swaps (because if one has odd number of swaps, then the other also has to have an odd number so that total number of swaps becomes even).

And to tell how to deal with parity we need to know your memo and solving order.

But if you do it like me: memo edges first and execute corners first, one easy way to do it is:

If you have an odd number of edge targets then memo corners so that the sticker that NORMALLY would go to UBL now goes to UBR.

Then, at the end of solve after shooting to the last edge target, simply do: M2 y' L2 [T-perm] L2 y M2
 
I would love that. Only I can not give the scramble, because I do not know how to reconize parity. I want a normal scramble solve, one with edge parity and one with corner parity. That is all what can happen right? Or do also corner plus egde parity exist?

Parity has already been explained above. It makes sense if you think about your PLL. there is not a case of 2 swapped corners that do not also have swapped edges (like Jperm Tperm, etc).

A interesting trick that can be used to notice if a scramble has parity or not is to count the number of quarter turns in the scamble(like R,R' but not R2). If the number is odd then you have parity. If it is even, then there is not parity. The half turns do not matter because they are an even number of quarter turns. For example

U L2 F2 U' F2 U2 L2 F2 D' L2 D L U' B' F U B' F' R B F has 14 quarter turns so you do not have parity

R2 D2 B2 U2 F' R2 F L2 F R2 B' R' D R2 F' D' F2 L F D2 R' has 11 quarter turns so you have parity

U2 R2 does not have parity but

U2 R does have parity
 
Two examples for Marcel:
One has parity, one doesn't. Note I do a lot of Jb perms. You may want to do more T perms.
T is t-perm
J is Jb-perm
L-perm is Ja(L)-perm (I do R' U L'... so UL<->UB)
Y is Y-perm
Y2 is Y-perm without F/F' (sometimes I execute more like Y, sometimes Y2)
R-perm is Ra-perm (I do L U2 L' U2...)

L2 R2 D R2 B2 L2 R2 D2 B2 F2 U' B R2 U2 F D U2 F2 L R2

x2
T
L' T L
d L T L' d'
d' L' T L d
M2 J M2 (D L2 T L2 D')
y' L-perm y (M2 D' L2 T L2 D M2)
J (M2 D L2 T L2 D' M2)
D L2 T L2 D' (I don't like L perms as much)
d L' T L d'
d M' J M d' (hate this case)

D2 R Y R' D2
D Y2 D'
U2 J U2
R' Y R
Y2
R L-perm
R2 Y R2
R2 L-perm R2

D2 B2 U' R2 D L2 U' F2 D' U' F' R' F D' B2 D' U' L' U (Parity)
L2 T L2
T
M2 J M2 (D L2 T L2 D')
D2 L2 T L2 D2
d2 L' T L d2
d2 L T L' d2
L T L'
M' L-perm M (M D' L2 T L2 D M')
L' T L
D' L2 T L2 D
L' T L

y' R-perm y (parity fix)

L-perm
F2 Y F2
R Y R'
D2 Y2 D2
F2 Y2 F2 (F Y F')
R Y2 R'
R' Y2 R

There you go.
 
In 3x3 there is only one parity.

You see, the total number of 2 swaps needed to solve the cube must always be even (therefore its impossible to swap just 2 edges or just 2 corners).

In blindsolving it's called parity when edges AND corners have an odd number of swaps (because if one has odd number of swaps, then the other also has to have an odd number so that total number of swaps becomes even).

And to tell how to deal with parity we need to know your memo and solving order.

But if you do it like me: memo edges first and execute corners first, one easy way to do it is:

If you have an odd number of edge targets then memo corners so that the sticker that NORMALLY would go to UBL now goes to UBR.

Then, at the end of solve after shooting to the last edge target, simply do: M2 y' L2 [T-perm] L2 y M2

Thanks so much!

U2 R2 does not have parity but

U2 R does have parity
Ahh.. ;) Finally I get it.

Two examples for Marcel:
One has parity, one doesn't. Note I do a lot of Jb perms. You may want to do more T perms.
T is t-perm
J is Jb-perm
L-perm is Ja(L)-perm (I do R' U L'... so UL<->UB)
Y is Y-perm
Y2 is Y-perm without F/F' (sometimes I execute more like Y, sometimes Y2)
R-perm is Ra-perm (I do L U2 L' U2...)

L2 R2 D R2 B2 L2 R2 D2 B2 F2 U' B R2 U2 F D U2 F2 L R2

x2
T
L' T L
d L T L' d'
d' L' T L d
M2 J M2 (D L2 T L2 D')
y' L-perm y (M2 D' L2 T L2 D M2)
J (M2 D L2 T L2 D' M2)
D L2 T L2 D' (I don't like L perms as much)
d L' T L d'
d M' J M d' (hate this case)

D2 R Y R' D2
D Y2 D'
U2 J U2
R' Y R
Y2
R L-perm
R2 Y R2
R2 L-perm R2

D2 B2 U' R2 D L2 U' F2 D' U' F' R' F D' B2 D' U' L' U (Parity)
L2 T L2
T
M2 J M2 (D L2 T L2 D')
D2 L2 T L2 D2
d2 L' T L d2
d2 L T L' d2
L T L'
M' L-perm M (M D' L2 T L2 D M')
L' T L
D' L2 T L2 D
L' T L

y' R-perm y (parity fix)

L-perm
F2 Y F2
R Y R'
D2 Y2 D2
F2 Y2 F2 (F Y F')
R Y2 R'
R' Y2 R

There you go.

You are awesome! Thanks. I can analyze this!
 
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