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[U2] R2 U2 R2 U' R2 U' R2shortest algo for the triple sexy move f2lcase?

1- swap two adjacent pieces with T perm/J perm/R' F R F' R U2 R' U R U2 R'I'm looking to make a checkered patter with my 2x2 and 4x4. Not the one where you just flip the sides, but where three sides flip (eg. blue, red and white are checkered, and then green, orange and yellow are checkered).... NOW I understand that it is not actually possible because it is an even numbered cube, but I saw where only the blue, red and white side was checkered and not the other three sides. That is what I would like to figure out how to do.
like this
View attachment 4248
I'm looking to make a checkered patter with my 2x2 and 4x4. Not the one where you just flip the sides, but where three sides flip (eg. blue, red and white are checkered, and then green, orange and yellow are checkered).... NOW I understand that it is not actually possible because it is an even numbered cube, but I saw where only the blue, red and white side was checkered and not the other three sides. That is what I would like to figure out how to do.
like this
View attachment 4248
For 2x2:
U2 F' U' F2 R U F U' R U' (10f*)
Edit: ninja'd. TDM's solution may be longer, but easier to memorize.
Thank you. Is TDM's the 4x4? That still confuses me.
Can you not just invert your Ua perm?I need a Ub perm alg for the 3x3x2.
2x2: alg.cubing.netThank you. Is TDM's the 4x4? That still confuses me.
Can you not just invert your Ua perm?
2x2: alg.cubing.net
However, if you use all double layer turns, the pattern can also be done on a 4x4: alg.cubing.net
Can you not just invert your Ua perm?
Does anyone have a good alg for this case and the mirror.
Thanks, I should probably look through those.F U' R' U R U F' R U R2 U R2 U2 R' and the inverse. From Ben's tripod algs.
If you don't include equivalent positions after a rotation around the UFR corner, but you do include inverses and the solved case, there are 24 cases. I will work on generating good algs and post them here.Is there an alg set that solves the 3 remaining edges if you already have a tripod (F2L-1, and 2x2x1 on U layer)? If not, does anyone want to find out how many cases there would be? Also, this would disregard the 4 remaining corners.
If you don't include equivalent positions after a rotation around the UFR corner, but you do include inverses and the solved case, there are 24 cases. I will work on generating good algs and post them here.