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It seems I forgot to take into account that standard pll parity influences centers as well. Undo the algorithm I gave, and use this one instead. You'll have to do a weird manual algorithm instead.

https://alg.cubing.net/?puzzle=4x4x...y2_L-_U-_L_U_F_U-_F-_Uw2_U2_F_U_F-_U-_L-_U_L-

This is an algorithm that should swap two edges without affecting the centers. It seems really long, but it's a pair of 3 cycles in the edges.

From this point - if things go according to plan, you'll have a pair of edges to swap, and a pair of corners to swap (based on your pictures you might have to orient a pair of corners too). Hopefully you'll be able to solve the 3x3 stage of your puzzle, and you'll have it solved, or you'll be left with a rotated center.

hmmm tried that, it kept the top layer exactly the same but messed up 2 middle layer edges lol

I must be missing something soo obvious..... I've tried some 3x3 PLL moves and nothing seems to be working.

EDIT: FINALLY DONE IT OUT OF PURE LUCK!! NOOO IDEA HOW!!

I really need to figure this out as I cant be bothered spending days on the same part every time...kinda taking the fun away from it!
 
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hmmm tried that, it kept the top layer exactly the same but messed up 2 middle layer edges lol

I must be missing something soo obvious..... I've tried some 3x3 PLL moves and nothing seems to be working.

EDIT: FINALLY DONE IT OUT OF PURE LUCK!! NOOO IDEA HOW!!

I really need to figure this out as I cant be bothered spending days on the same part every time...kinda taking the fun away from it!

That's good haha. I'm guessing you found a way to solve it via a standard 3x3 method, and fixed the center as well.
 
That's good haha. I'm guessing you found a way to solve it via a standard 3x3 method, and fixed the center as well.

Just solving it again come up with the same issue, after a long time of trial and error I found a very vague bit of information on the internet!

The information did not state what the parity was or what orientation to do it etc, but I tried it anyway followed by a few standard sunes etc and left me with a 180 centre rotation!

hopefully this will work each time..... r2 U2 B2 l r U2 M' U2 r2 B2 U2
 
Just solving it again come up with the same issue, after a long time of trial and error I found a very vague bit of information on the internet!

The information did not state what the parity was or what orientation to do it etc, but I tried it anyway followed by a few standard sunes etc and left me with a 180 centre rotation!

hopefully this will work each time..... r2 U2 B2 l r U2 M' U2 r2 B2 U2

That's interesting, I would not have thought of that. My approach would have been to solve it like a 3x3 after you executed the longer parity algorithm, since all your edges and centers are solved, and parity is also fixed as well. As long as you figured out something that works for you, that's all that matters haha.
 
Code:
                                   TOP
                                   -------------------------
                                  |####|####|####|####|####|
                                   -------------------------
                                  |####|####|####|####|####|
                                   -------------------------
                                  |####|####|####|####|####|
                                   -------------------------
                                  |####|####|####|####|####|
                                   -------------------------
                                  |####|####|####|####|####|
                                   -------------------------
      LEFT                         FRONT                        RIGHT                        BACK
      -------------------------    -------------------------    -------------------------    -------------------------
     |&&&&|&&&&|&&&&|&&&&|&&&&|   |OOOO|OOOO|OOOO|OOOO|OOOO|   |XXXX|XXXX|XXXX|XXXX|XXXX|   |^^^^|^^^^|^^^^|^^^^|^^^^|
      -------------------------    -------------------------    -------------------------    -------------------------
     |&&&&|&&&&|&&&&|&&&&|&&&&|   |OOOO|OOOO|OOOO|OOOO|OOOO|   |XXXX|XXXX|XXXX|XXXX|XXXX|   |^^^^|^^^^|^^^^|^^^^|^^^^|
      -------------------------    -------------------------    -------------------------    -------------------------
     |&&&&|&&&&|OOOO|&&&&|&&&&|   |OOOO|OOOO|XXXX|OOOO|OOOO|   |XXXX|XXXX|^^^^|XXXX|XXXX|   |^^^^|^^^^|&&&&|^^^^|^^^^|
      -------------------------    -------------------------    -------------------------    -------------------------
     |&&&&|&&&&|&&&&|&&&&|&&&&|   |OOOO|OOOO|OOOO|OOOO|OOOO|   |XXXX|XXXX|XXXX|XXXX|XXXX|   |^^^^|^^^^|^^^^|^^^^|^^^^|
      -------------------------    -------------------------    -------------------------    -------------------------
     |&&&&|&&&&|&&&&|&&&&|&&&&|   |OOOO|OOOO|~~~~|OOOO|OOOO|   |XXXX|XXXX|XXXX|XXXX|XXXX|   |^^^^|^^^^|~~~~|^^^^|^^^^|
      -------------------------    -------------------------    -------------------------    -------------------------

                                   BOTTOM
                                   -------------------------
                                  |~~~~|~~~~|^^^^|~~~~|~~~~|
                                   -------------------------
                                  |~~~~|~~~~|~~~~|~~~~|~~~~|
                                   -------------------------
                                  |~~~~|~~~~|~~~~|~~~~|~~~~|
                                   -------------------------
                                  |~~~~|~~~~|~~~~|~~~~|~~~~|
                                   -------------------------
                                  |~~~~|~~~~|OOOO|~~~~|~~~~|
                                   -------------------------

I was cage-solving my 5x5x5 and didn't notice the centers were askew until after solving the first two layers. Usually I abandon the effort and center the 3rd slice. In this case, I decided to plod along to see what kind of monstrosity I was left with at the end. It looks like a horizontal center 4-cycle with the two middle edges swapped and flipped from front-to-back on the last layer.

My 5x5x5 solver is at depth 14 and still no solution.

Any solutions would be appreciated!
 
Hello- this is a problem i came across while solving my 2x2 today. I am fairly inexperienced cuber, and usually average sub 10 on 2x2. When solving, I sometimes come across a case where the white and yellow sides are both solved, and the back face is solved, but there are vertical bars around the rest of the cube. Does anyone have an algorithm to solve this?
 
Hello- this is a problem i came across while solving my 2x2 today. I am fairly inexperienced cuber, and usually average sub 10 on 2x2. When solving, I sometimes come across a case where the white and yellow sides are both solved, and the back face is solved, but there are vertical bars around the rest of the cube. Does anyone have an algorithm to solve this?

Does R' U R U' R U' R' U' R' F2 U' R2 work?

EDIT: Also, to answer the question you don't know how to ask yet, this algorithm is the PBL step of the Ortega method. You should check it out
 
Hello- this is a problem i came across while solving my 2x2 today. I am fairly inexperienced cuber, and usually average sub 10 on 2x2. When solving, I sometimes come across a case where the white and yellow sides are both solved, and the back face is solved, but there are vertical bars around the rest of the cube. Does anyone have an algorithm to solve this?

This seems to be a case in the Varasano / Ortega Method. If you look it up on YouTube or something, you should be able to find an algorithm for the case. If you take your solved 2x2 and do this algorithm, you should get the case you discussed, If I was correct based on your description.



https://alg.cubing.net/?puzzle=2x2x2&alg=R2_U-_R2_U2-_y_R2_U-_R2_&setup=R2_U_R2_y-_U2_R2__U_R2_
 
hey has anyone generated algs for skewb eg-1? I know cale schoon has eg-2 algs. http://bit.do/skewbEG2
If anyone has them please put them on a google doc and post them. Also, what is the average movecount?

I know, learning eg for skewb is overkill, since sarahs advanced is fast. but i want to learn at least some fast cases.
 
hey has anyone generated algs for skewb eg-1? I know cale schoon has eg-2 algs. http://bit.do/skewbEG2
If anyone has them please put them on a google doc and post them. Also, what is the average movecount?

I know, learning eg for skewb is overkill, since sarahs advanced is fast. but i want to learn at least some fast cases.

EG-1 doesn't exist on skewb because it's skewb
 
What do i do if i get kite on top and fist on bottom for square-1 advanced cubeshape?

There's a number of things you can do with that actually.

Here's a link to the tree for cube-shapes. Pick a path that you think works best for you.

http://www.jaapsch.net/puzzles/square1d.htm

Keep in mind you don't have to memorize all the ways to do cube-shapes, that's not how it works. Just look at how the path goes through different shapes, and why they get you to where you are. Understanding this often reduces your need for memorization when it comes to cube-shape.
 
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Need a 13x13x13 alg

image.jpg
 
Square 1 opposite parity

also if you could explain how to memorize too:D

To help break down the opp-opp alg I'm providing, I'm going to show the standard O-perm parity algorithm.

O-perm algorithm: / (3,3) / (1,0) / (-2,-2) / (-2,0) / (2,2) / (-1,0) / (-3,-3) / (3,2) / (-2,-2) /

If you look at the part that I highlighted in red, you'll see that you are performing a 6-cycle swap on top with the corners. Essentially, you are cycling 6 corners with one another. If you think about it, this is something that is not possible on a standard 3x3 cube, ( you can do odd cycles i.e an A perm, but not even cycles), which therefore indicates that you are creating parity! Or, in this case, you're undoing it. Fun fact, when you get the O-perm parity case, it looks like you are solving the edges, in reality, you're solving the corners, the edges are never effected in the algorithm.

Here is the algorithm that I use for opp-opp parity: / (3,3) / (1,0) / (-2,-2) / (-2,0) / (2,2) / (0,-2) / (-1,-1) / (0,3) / (-3,-3) / (3,2) / (-2,-2) /

EDIT: here is another way to do the algorithm, but by swapping the edges in the front and back, rather than the left and right.

/ (3,3) / (1,0) / (-2,-2) / (2,0) / (2,2) / (0,-2) / (-1,-1) / (0,3) / (-3,-3) / (0,2) / (-2,-2) /

If you notice, it uses the same idea as the O-perm. you make a shape with 6 corners on top, then you do a cycle, and undo the steps used to create the shape. The only difference, is that it performs a z perm at the end of the algorithm. This is because if you do O-perm parity on a opp-opp parity case, you get a z-perm. This algorithm decides to solve the z perm midway through the end.

Not sure if this helps, but that is how I view most parity algorithms on square-1. You essentially set it up to a case where you can influence parity, do so, then undo your moves back to cube-shape. Very similar idea to a commutator.
 
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