Hssandwich
Veteran
If it doesn't matter whether edges and corners are retained, try:
2R U 2R' U' 2R' F 2R2 U' 2R' U' 2R U 2R' F'
I hope I am understanding this correctly and that this helps.
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The "Request an Alg" Thread
- Thread starter StachuK1992
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If it doesn't matter whether edges and corners are retained, try:
2R U 2R' U' 2R' F 2R2 U' 2R' U' 2R U 2R' F'
I hope I am understanding this correctly and that this helps.
TheCoolMinxer
Veteran
Most common OH alg for v,e and f perm? I am still using my 2h algs which kinda suck...
FakeMMAP
Regular
V: hold block in the back, and do R U' L' U R' U' R U' L U R' U2 L' U2 L
F: hold bar in front, and do R U R' U' R' U R U2 L' R' U R U' L U' R U' R'
E: x' R U' R' D R U R' Uw2 R' U R D R' U' R'
hope this helps
F: hold bar in front, and do R U R' U' R' U R U2 L' R' U R U' L U' R U' R'
E: x' R U' R' D R U R' Uw2 R' U R D R' U' R'
hope this helps
Quote Adam:"I NEED to know what algorithms to use!
1. The last centre orientation. All colours in the right place, two need swapping but keeping all other centres ok. Solve as it is or solve using last two centres at the same time"
Not a very scientific answer, but I've just tried randomly swapping centre pieces from one group of 4 to an adjacent centre group of 4 until they were all back in their correct centre, and your two-adjacent-centre-pieces-needs-swapping came up fairly easily , but the alg posted above by Harry is effective. Plenty of other varieties of centre-shuffles can be obtained the same way, eg. cycles of 3 pieces within a group of 4, so you only need to involve the one other centre in finding your solution.
I'm not at the stage of posting any algs, but I'm sure you can work something out.
1. The last centre orientation. All colours in the right place, two need swapping but keeping all other centres ok. Solve as it is or solve using last two centres at the same time"
Not a very scientific answer, but I've just tried randomly swapping centre pieces from one group of 4 to an adjacent centre group of 4 until they were all back in their correct centre, and your two-adjacent-centre-pieces-needs-swapping came up fairly easily , but the alg posted above by Harry is effective. Plenty of other varieties of centre-shuffles can be obtained the same way, eg. cycles of 3 pieces within a group of 4, so you only need to involve the one other centre in finding your solution.
I'm not at the stage of posting any algs, but I'm sure you can work something out.
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Right. I'm in the mood to smash this thing up now. I can't figure out what the h3ll I am missing?!
Solving again. This time only one edge out on the top cross?!
Can't flip the edge as destroys the rest of cube and goes back the same after re solving. Have mixed up in its 3x3 format and tried again. Still that one side out.
I don't get it? It's a 3x3 format but still I can't solve it!!
Any help with this one??
Need that right edge of the cross flipping to fit. Which I'm assuming that move would put the centre either right or 180 out. Which is fine.
Sent from my iPhone using Tapatalk
Solving again. This time only one edge out on the top cross?!
Can't flip the edge as destroys the rest of cube and goes back the same after re solving. Have mixed up in its 3x3 format and tried again. Still that one side out.
I don't get it? It's a 3x3 format but still I can't solve it!!
Any help with this one??
Need that right edge of the cross flipping to fit. Which I'm assuming that move would put the centre either right or 180 out. Which is fine.
Sent from my iPhone using Tapatalk
I'm going to say the obvious: isn't this the so-called 'OLL Parity' case? One edge-pair flipped, (and some knock-on centre disturbances).
It certainly looks like it's part of your probem. See the previous Hardwick link I posted.
Though I haven't got one, it would appear that this puzzle should display all the quirks of 4x4x4 'super-cubes' , OLL & PLL parity problems, and where centre-four rotation matters.
It certainly looks like it's part of your probem. See the previous Hardwick link I posted.
Though I haven't got one, it would appear that this puzzle should display all the quirks of 4x4x4 'super-cubes' , OLL & PLL parity problems, and where centre-four rotation matters.
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The "Request an Alg" Thread
Right sorted that out.
Now left me with another issue.
The corner parity. Now I've followed the steps for this on the 4x4 method and it just screw up the orientation of some of the centres!!
Is there an algorithm for this picture?
I love this cube but I'm struggling with specific algorithm for it as a lot of the 4x4 ones 'work' but change the orientation of the shaped cubes etc. If anyone can help with specific algorithms for this cube??
Centre 90 out and parity with the corners, 2 correct and 2 out.
Thanks again!
Right sorted that out.
Now left me with another issue.
The corner parity. Now I've followed the steps for this on the 4x4 method and it just screw up the orientation of some of the centres!!
Is there an algorithm for this picture?
I love this cube but I'm struggling with specific algorithm for it as a lot of the 4x4 ones 'work' but change the orientation of the shaped cubes etc. If anyone can help with specific algorithms for this cube??
Centre 90 out and parity with the corners, 2 correct and 2 out.
Thanks again!
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stoic
Premium Member
Anything good for OLL 12 from the y2 angle?
I'd translate the standard alg but I don't like B moves.
Like this: (green front)
I'd translate the standard alg but I don't like B moves.
Like this: (green front)
penguinz7
Veteran
U M' Backsune U' M
Bindedsa
Veteran
r U R' U R U2 x' U L' U L U2 L'
Sam N
Regular
- Joined
- Jun 9, 2015
- Messages
- 89
It looks like you will have to do a pll-parity alg to solve that. It will swap two edges, giving you a 3x3 last layer which is solvable via standard 3x3 algorithms. Here is the standard alg for that : Uw2, Rw2, U2, r2, U2, Rw2, Uw2
This should leave you with a t-perm ( or f perm depending how you do it) looking case for your last layer. I'm not sure if two corners need to be orientated by the picture you gave, but that might be something you'll have to do.
Last edited:
The "Request an Alg" Thread
Can you confirm your notation for this? I tried it based on 'w' being 2 layers and 'x' being the middle layer?
Kinda screwed my cube up other than last later, undone it back to how it was though.
I've tried a corner algorithm which works, but messed up the rest of the cube. As it is I have 2 corners solved and a 90 on the centre.
So frustrating as its a fantastic cube to solve, just a few parts I need to sort as at the min I'm spending a day to try and solve and most times its out of luck :-(
Sent from my iPhone using Tapatalk
Can you confirm your notation for this? I tried it based on 'w' being 2 layers and 'x' being the middle layer?
Kinda screwed my cube up other than last later, undone it back to how it was though.
I've tried a corner algorithm which works, but messed up the rest of the cube. As it is I have 2 corners solved and a 90 on the centre.
So frustrating as its a fantastic cube to solve, just a few parts I need to sort as at the min I'm spending a day to try and solve and most times its out of luck :-(
Sent from my iPhone using Tapatalk
Sam N
Regular
- Joined
- Jun 9, 2015
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- 89
Here is a video that shows how the algorithm is executed. https://www.youtube.com/watch?v=i_eza0B-uFM
You should hold the cube with the screwed up center on top, and the two incorrect corners in the front so they are the top left and top right corners respectively. This should leave you with a last layer where your center is messed up, you have 2 corners that need swapping, and two edges ( in terms of 3x3) that need swapping after you execute the algorithm. you should be able to solve all the corners and edges from that point
A bit confused now, the video only shows edge parity and no corner ones?
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Sam N
Regular
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- Jun 9, 2015
- Messages
- 89
Yes, that's very true, however you need to keep in mind that edge parity and "corner parity" are one in the same. On 4x4 puzzles, you can't ONLY swap two corners, it's impossible. It looks like that is what you have to do, but in reality the parity is created in the edges. The algorithm I showed will swap two edges, which will essentially solve the parity that you have. You will then be able to solve the last layer like a normal 3x3 cube. If you execute the parity algorithm like I addressed earlier, this will like you with a T-perm for your last layer.
Here is a picture of what that looks like https://www.google.com/search?q=3x3...hWCST4KHfweAUEQ_AUIBygC#imgrc=hfN-J-iJiOSauM:
You essentially have to swap two opposite edges, and two adjacent corners, which is something that you can solve on a normal 3x3. Here is a video showing you how to do that.
https://www.youtube.com/watch?v=1058SurCnRU
NOTE: the T perm is addressed at 0:32 seconds into the video.
stoic
Premium Member
Thanks for the replies.
I like that, but I'll have to disqualify it because of the AUF.
That's not bad.
Anyone got anything else??!!
Bindedsa
Veteran
There's also M' U R' U' R U' R' U2 R U M
obelisk477
Veteran
There's nothing better with <M> or <r> through depth 14 than the one bindedsa just posted (the M' U one). As for <RUF>, theres:
F U R U2 R' U R U R' U R U' R' F' (14f)
....and that's the only decent one through depth 16
Doing your algorithm messed up my front and back centre at the same time as the top layer.....
Any other thoughts?
Picture shows the now mixed front centre. Same as the back
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Sam N
Regular
- Joined
- Jun 9, 2015
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- 89
It seems I forgot to take into account that standard pll parity influences centers as well. Undo the algorithm I gave, and use this one instead. You'll have to do a weird manual algorithm instead.
https://alg.cubing.net/?puzzle=4x4x...y2_L-_U-_L_U_F_U-_F-_Uw2_U2_F_U_F-_U-_L-_U_L-
This is an algorithm that should swap two edges without affecting the centers. It seems really long, but it's a pair of 3 cycles in the edges.
From this point - if things go according to plan, you'll have a pair of edges to swap, and a pair of corners to swap (based on your pictures you might have to orient a pair of corners too). Hopefully you'll be able to solve the 3x3 stage of your puzzle, and you'll have it solved, or you'll be left with a rotated center.
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