One-Answer 3x3x3 Question Thread

[Forcefulness]

The M and U move Z perm is nice

guess i walked into that one, perhaps i should be more specific, any R/L and U z perms

 

[Cale S]

guess i walked into that one, perhaps i should be more specific, any R/L and U z perms

(R' U' R2 U) (R U R' U') (R U R U') (R U' R')

 

[Lykos]

I want to be able to almost always avoid PLLs that involve a diagonal swap. (Especially N perm) I think that should be possible since I just need two instead of one algorithm per case.

I can't imagine that I am the first one who wants to do this. Does anyone know any good resources on this idea?

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[Shiv3r]

me+ my friend are coming up with a 15 case 1 look last layer, wait till then.

 

[Daniel Lin]

I want to be able to almost always avoid PLLs that involve a diagonal swap. (Especially N perm) I think that should be possible since I just need two instead of one algorithm per case.

I can't imagine that I am the first one who wants to do this. Does anyone know any good resources on this idea?

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OLLCP. You can learn it on algdb.net
I am considering starting OLLCP since i've taken a break from zbll

 

[Daniel Lin]

(R' U' R2 U) (R U R' U') (R U R U') (R U' R')

I prefer (R' U' R U')(R U R U')(R' U R U) (R2 U' R')

 

[Lykos]

OLLCP. You can learn it on algdb.net
I am considering starting OLLCP since i've taken a break from zbll

Hm, yes. I know about OLLCP. But learning all of OLLCP is a bit too tough. If I just want to avoid diagonal PLL, a small subset should be sufficient. So I am looking for someone who already chose a sensible set of OLLCP to achieve this.

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[Daniel Lin]

Hm, yes. I know about OLLCP. But learning all of OLLCP is a bit too tough. If I just want to avoid diagonal PLL, a small subset should be sufficient. So I am looking for someone who already chose a sensible set of OLLCP to achieve this.

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if you just want to avoid diag pll, then learn any 2 ollcps for every oll. basically just learn full oll again with different algs

 

[PurpleBanana]

if you just want to avoid diag pll, then learn any 2 ollcps for every oll. basically just learn full oll again with different algs

You also have to be able to recognize CP.

 

[Lykos]

Ok, thanks. I will look into it.

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[Drad]

I just learnt a T perm and I want to learn all my PLL lags before summer would it make me forget my lags if I learn on alg a day ?

 

[PurpleBanana]

I just learnt a T perm and I want to learn all my PLL lags before summer would it make me forget my lags if I learn on alg a day ?

No, as long as you keep practicing the ones you've learnt previously.

 

[megasolver]

I don't get step 4c in roux, can somebody explain?

 

[TDM]

I don't get step 4c in roux, can somebody explain?

You're trying to permute the last four edges, similar to how you would permute the last eight LL pieces in the last step of CFOP. There are four cases (U2 M' U2, U2 M U2, U2 M2 U2, E2 M' E2).

 

[megasolver]

You're trying to permute the last four edges, similar to how you would permute the last eight LL pieces in the last step of CFOP. There are four cases (U2 M' U2, U2 M U2, U2 M2 U2, E2 M' E2).

but like, sometimes i do a case but then it doesn't solve immediately, it becomes another case.. is it supposed to be like that?

 

[TDM]

but like, sometimes i do a case but then it doesn't solve immediately, it becomes another case.. is it supposed to be like that?

This will happen if you do the algorithm from the incorrect angle. Just like how most PLLs only work from one AUF, you need to AMS (adjust M slice?) before each 4c case.

 

[Jakester5112]

I'm going to be getting a 54.5 Weilong for OH. I don't know if I should get stickerless or black. Does a stickerless cube affect any solving aspect during OH?

 

[Drad]

I'm going to be getting a 54.5 Weilong for OH. I don't know if I should get stickerless or black. Does a stickerless cube affect any solving aspect during OH?

I would get black so that you are used to color scheme.

 

[jaredye]

I'm going to be getting a 54.5 Weilong for OH. I don't know if I should get stickerless or black. Does a stickerless cube affect any solving aspect during OH?

Usually the stickerless version is a few grams lighter than the standard version due to the weight of stickers. You might want to take that into consideration. If you want a lighter cube then get the stickerless version, and if you want heavier cube get the standard version.

 

[Drad]

Usually the stickerless version is a few grams lighter than the standard version due to the weight of stickers. You might want to take that into consideration. If you want a lighter cube then get the stickerless version, and if you want heavier cube get the standard version.

I don't think a few gram makes much of a difference.