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hi, new here. not sure if this is the right place but i think so..

is there an 3x3 algorithm to rotate two opposite corners on 3x3?

(using method where i permute then orient the last layer)

Do you know how to twist two adjacent corners? If you do, you can do that twice in order to get the effect of twisting two opposite corners.

R' D' R D R' D' R U2 R' D R D' R' D R

F (L' U' L U' L' U2 L) (R U R' U R U2 R') F'

F' R D2 R' F U2 F' R D2 R' F

r u' R2 u r' U2 r u' R2 u r'

Pick your poison.
 
Do you know how to twist two adjacent corners? If you do, you can do that twice in order to get the effect of twisting two opposite corners.

R' D' R D R' D' R U2 R' D R D' R' D R

F (L' U' L U' L' U2 L) (R U R' U R U2 R') F'

F' R D2 R' F U2 F' R D2 R' F

r u' R2 u r' U2 r u' R2 u r'

Pick your poison.

right now i do the adjacent twisting one twice, but i was looking for a more efficient way, thanks :)
 
Is there any list of ZBLS algs with cross-on-left? I'd assume that a reasonable chunk of the cases would just be "rotate and then do the normal ZBLS alg", but I think there are some that are nicer with a different alg, like this flipped edge case:

Normal: R2' U2' F R2 F' U2' R' U R' (regripless but the F' is a bit awkward)
COL: U' R U' R2' F' U2' F R2 U2' (a bit nicer imo)

(I'm not intending to learn full ZBLS, just a few of the easy-to-recog cases.)
 
Hello,

Bill the newb here.
I solve the 4x4 like this ............ Centres then corners then put the rest in one by one. Sometimes in pairs or even 4's if I get lucky and they happen to fall out that way

If I end up with 3 unsolved cubelets I can usually solve all 3 on my last manouvere, but sometimes I end up with 2 unsolved cubelets and my one at a time method fails as it relies upon having three wrong ones to play with. I then have mess things up a bit and start again from halfway.

Am aware of the pseudo 3x3 method but I enjoy doing what I have figured out for myself.

Have tried various searches and always end up on pages about parity and am not interested as the methods seem to rely upon the pseudo 3x3 method.

Any hints or methods or algorithms or key words I should search on to help my one at a time method deal with having only 2 wrong ones to play with ? See attached photo.

2wrongcubicles.png


I doubt I will ever be seriously speedsolving to break records or compete with others, I just enjoy solving the cube.

Thanks

Bill
 
Last edited:
Hello,

Bill the newb here.
I solve the 4x4 like this ............ Centres then corners then put the rest in one by one. Sometimes in pairs or even 4's if I get lucky and they happen to fall out that way

If I end up with 3 unsolved cubelets I can usually solve all 3 on my last manouvere, but sometimes I end up with 2 unsolved cubelets and my one at a time method fails as it relies upon having three wrong ones to play with. I then have mess things up a bit and start again from halfway.

Am aware of the pseudo 3x3 method but I enjoy doing what I have figured out for myself.

Have tried various searches and always end up on pages about parity and am not interested as the methods seem to rely upon the pseudo 3x3 method.

Any hints or methods or algorithms or key words I should search on to help my one at a time method deal with having only 2 wrong ones to play with ? See attached photo.View attachment 8149

I doubt I will ever be seriously speedsolving to break records or compete with others, I just enjoy solving the cube.

Thanks

Bill
In general. Rather than putting an unsolved piece where it looks like it should go put it in the solved piece next to it then put that piece in to the unsolved position. So in your case, unsolved green/yellow to solved green/yellow to unsolved red/yellow.
 
Hi
I have a general alg question i guess.
Say i have this alg:
F' L' U' L U L' U' L U F L' U' L U L F' L' F
Is there a way manipulate that alg so that i have a <RUF> alg that solves the same case afterwards?
 
Hi
I have a general alg question i guess.
Say i have this alg:
F' L' U' L U L' U' L U F L' U' L U L F' L' F
Is there a way manipulate that alg so that i have a <RUF> alg that solves the same case afterwards?

You could rotate it to R' F' U' etc. but then it'd be a very F-heavy alg, which is probably not what you want. At best you can replace the L' U' L U L F' L' F with U2 F R U' R' U R U R' F'.
 
I'm looking for the set of algorithms that permutes the last 5 edges of the cube (UF, UL, UR, UB, DF) (4 edges on top and on eon bottom) after they have already been oriented thus results in a solved cube. This is the only page I found online regarding these algorithms…

https://www.speedsolving.com/wiki/index.php/L5E

Some are okay, but they don't show recognition and some are really slow. I'm just wondering if there are any better ones.
 
OH alg for this zbll case? R2 D' L D R' U2 R2 D' U' F2 U L' D R
R' U' R U' R2 D R' U R D' R U R2 U2 R'
R' U2 R2 U R D' R U R' D R2 U' R U' R'
R D' R U' R U2 R U2 R' U R' D U' R' U' R U R'

L R' U' R U L' U2 R' U R U' R' U R U' R' U2 R
R U2 R' U' R U R' U' R U R' U2 L' U R U' L R'
 
R' U' R U' R2 D R' U R D' R U R2 U2 R'
R' U2 R2 U R D' R U R' D R2 U' R U' R'
R D' R U' R U2 R U2 R' U R' D U' R' U' R U R'

L R' U' R U L' U2 R' U R U' R' U R U' R' U2 R
R U2 R' U' R U R' U' R U R' U2 L' U R U' L R'

Where did you get these? These (at least some of them) aren't to find in any databases i know of
 
When the last F2L pair is misoriented, you end up having to do a cube rotation or insert the pair in a weird way. And while we are at inserting the pair in a weird way, we might a well orient the edges.

I'm sure someone has a lost somewhere.
 
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