Gordon
Veteran
Any way to swap the two wrong cross pieces without destroying the rest of the F2L?
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Any way to swap the two wrong cross pieces without destroying the rest of the F2L?
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Yes, I just copy & pasted.Did CubeX label the first 4 algorithms as being 6f? They are also 10f.
Did CubeX label the first 4 algorithms as being 6f? They are also 10f.Here are some short ones CubeX found:
M' U2 S' U S M (6f*)
M' S' U' S U2 M (6f*)
S' U2 M' U' M S (6f*)
S' M' U M U2 S (6f*)
R' F' R F D' R' F R D F' (10f*)
R' D F R F' D' R F R' F' (10f*)
F R F' R' D F R' F' D' R (10f*)
F D' R' F' R D F' R' F R (10f*)
I am not sure exactly what cases you are referring to, despite that I have an idea of what you possibly want. Regardless, read from this point on in the 4x4x4 parity algorithms wiki page. If none of the cases you wanted were in the PLL parity section, they are probably here:Heya guys, can I have a good alg for 4x4 PLL parity for vertical and diagonal last corners swap and edges swap? all PLL, thanks!
Are there any good OH T and Y perms?
i need a easy and fast to execute algo for the headlights oll. i currently use R2 D R' U2 R D' R' U2 R' which takes me about 5 seconds.( my average is 19 seconds)
When you asked for a "wingflip", I wasn't sure if you wanted an odd number of 2-cycle swaps or an even number. I also assume that you want "pure" flips, and not something like this (the following is an OLL parity algorithm):I am looking for a 5x5 flip wing edges algorithm, but I can only use U, Uw, and R and Rw.
I can do a surrogate F on one or two layers, but not sure how well it would work with the wingflip.
(bandaged 5x51x3x5 block is bandaged)
Are there any good OH T and Y perms?
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Well, I didn't come up with those optimal <U,r> solutions. Kåre Krig found them using his k-solve program and cuBerBruce found them using k-solve as well.r U2 r' U2 r U2 r U r U r U2 r2 U2 r U2 r U r' U' r2 U2
this one did the trick.. thank you SO much.
How on earth do you know all this?? I searched till I saw blue in the face and decided to ask here in the end.. thanks again!!
Is there an algo with only M and U to solve the M2s M layer pieces?