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I think there's R U F B' R2 F' B U R' and R U R U R2 U' R' U' R' U2 for the first one.
Those are good, but it will be even better if I can find something that would also work on a 5x5
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I think there's R U F B' R2 F' B U R' and R U R U R2 U' R' U' R' U2 for the first one.
The cube explorer page goes down a lot; I don't know where you can download it atm.Hello fellows. Can someone help me to find convinient algs for those edges cases (and their inverses):
UF->BR->UB
UF->RB->UB
UF->FR->UB
UF->RF->UB
Also, I could do it using cube explorer but I can't find where to download it now. Can you help me there as well? Please![]()
The cube explorer page goes down a lot; I don't know where you can download it atm.
Is that page working for you? It isn't for me.
Is that page working for you? It isn't for me.
The webpage isn't available for me, and I remember it not being available for a long time between me finding out about it, and me being able to actually download it. It's a bit unreliable...I can view the page fine, I haven't tried downloading it though since I already have CE.
Something tells me that the link is broken.
__
Okay, I found what I was looking for by myself. CubeExplorer isn't a very good thing to find algs that are very convinient to execute, as long as you aren't patient enough to look through the list of tens of trash algorithms for each case.
Something tells me that the link is broken.
__
Okay, I found what I was looking for by myself. CubeExplorer isn't a very good thing to find algs that are very convinient to execute, as long as you aren't patient enough to look through the list of tens of trash algorithms for each case.
Earlier I used this:
UF->BR->UB z x [U M' U', R2] and z x [U r U', R2] for wings
UF->RB->UB z x [U' M2 U, R2] and r2 instead of M2 for wings
UF->FR->UB z' x' [U' M' U, L2], r instead of M for wings
UF->RF->UB z' x' [U M2 U', L2] (for its symmetrical), r2 for wings
After a while of consideration and asking other people for it:
UF->BR->UB R D' [M, U2] D R' for 3x3, [Rw U' [R2, U' r' U]] for 5x5 and [Rw U [L, U r' U']] for its symmetrical 5x5 case
UF->RB->UB [R; [M' D M, U2]] and [Rw; [D, r' U2 r]]. There's impossible to make a cancellation for its inversed case in 5x5, however [L' [r D' r', U2]] is faster than the old one.
UF->FR->UB R' D' [M, U2] D R for 3x3 and still z x [U r U', R2]. I timed average time of this alg execution and compared it with others (like x' l [l U2 l' D] l' x). The average time seems to be faster with the old alg.
UF->RF->UB Rw' D' M' U2 M D M' U2 R for 3x3, still [z x' [R2, U r2 R'] for 5x5 and [L; [l D l', U2]] for 5x5 inversed case
Also, nice wings U-perm: Rw U' R' U' r' U R U' r U2 Rw'
I plugged this into my 5x5x5 solver and found some shorter algs for you. These are all single slice turn metric 10-turn results, even though the scramble made use of your wide moves.
http://lightningcloudcomputing.com/cubes/5x5x5_LL_alg.png
You've probably looked at it hundreds of times, but I doubt many people find it easy to read off algs from that image.
Omnia Obtorquebantur 5x5x5 Version 1.0.5, March 28, 2015. Copyright 2015 by Ed Trice.
TOP
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LEFT FRONT RIGHT BACK
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|&&&&|&&&&|&&&&|&&&&|&&&&| |OOOO|XXXX|OOOO|OOOO|OOOO| |XXXX|^^^^|XXXX|XXXX|XXXX| |^^^^|OOOO|^^^^|^^^^|^^^^|
------------------------- ------------------------- ------------------------- -------------------------
|&&&&|&&&&|&&&&|&&&&|&&&&| |OOOO|OOOO|OOOO|OOOO|OOOO| |XXXX|XXXX|XXXX|XXXX|XXXX| |^^^^|^^^^|^^^^|^^^^|^^^^|
------------------------- ------------------------- ------------------------- -------------------------
|&&&&|&&&&|&&&&|&&&&|&&&&| |OOOO|OOOO|OOOO|OOOO|OOOO| |XXXX|XXXX|XXXX|XXXX|XXXX| |^^^^|^^^^|^^^^|^^^^|^^^^|
------------------------- ------------------------- ------------------------- -------------------------
|&&&&|&&&&|&&&&|&&&&|&&&&| |OOOO|OOOO|OOOO|OOOO|OOOO| |XXXX|XXXX|XXXX|XXXX|XXXX| |^^^^|^^^^|^^^^|^^^^|^^^^|
------------------------- ------------------------- ------------------------- -------------------------
|&&&&|&&&&|&&&&|&&&&|&&&&| |OOOO|OOOO|OOOO|OOOO|OOOO| |XXXX|XXXX|XXXX|XXXX|XXXX| |^^^^|^^^^|^^^^|^^^^|^^^^|
------------------------- ------------------------- ------------------------- -------------------------
BOTTOM
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Solutions To: Scramble = Rw U' R' U' r' U R U' r U2 Rw'
Solution [0001] = R U2 F 2U F' U2 [inside 04-TFS] ---> F 2U' F' R' @ 000000000097498503 nodes [time = 00:28]
Solution [0002] = R' B' 2D B U2 B' [inside 04-TFS] ---> 2D' B U2 R @ 000000000204188719 nodes [time = 00:58]
Solution [0003] = 2R 2L D2 2L' U 2L [inside 04-TFS] ---> D2 2L' U' 2R' @ 000000000280334696 nodes [time = 01:20]
Solution [0004] = 2L U' 2R D2 2R' U [inside 04-TFS] ---> 2R D2 2L' 2R' @ 000000000685563724 nodes [time = 03:18]
Solution [0005] = F U' B 2U2 B' U [inside 04-TFS] ---> B 2U2 B' F' @ 000000001810170187 nodes [time = 08:46]
Solution [0006] = F B 2U2 F' U F [inside 04-TFS] ---> 2U2 F' U' B' @ 000000001847014351 nodes [time = 09:00]
Solution [0007] = F' R' 2D R U R' [inside 04-TFS] ---> 2D' R U' F @ 000000001851629435 nodes [time = 09:02]
Solution [0008] = F' U' B' 2D2 B U [inside 04-TFS] ---> B' 2D2 B F @ 000000001876504531 nodes [time = 09:11]
Solution [0009] = F' B' 2D2 F U F' [inside 04-TFS] ---> 2D2 F U' B @ 000000001912279964 nodes [time = 09:23]
Solution [0010] = B U' R 2U R' U [inside 04-TFS] ---> R 2U' R' B' @ 000000002566085986 nodes [time = 13:36]
Solution [0001] = R U2 F 2U F' U2 F 2U' F' R'
Solution [0002] = R' B' 2D B U2 B' 2D' B U2 R
Solution [0003] = 2R 2L D2 2L' U 2L D2 2L' U' 2R'
Solution [0004] = 2L U' 2R D2 2R' U 2R D2 2L' 2R'
Solution [0005] = F U' B 2U2 B' U B 2U2 B' F'
Solution [0006] = F B 2U2 F' U F 2U2 F' U' B'
Solution [0007] = F' R' 2D R U R' 2D' R U' F
Solution [0008] = F' U' B' 2D2 B U B' 2D2 B F
Solution [0009] = F' B' 2D2 F U F' 2D2 F U' B
Solution [0010] = B U' R 2U R' U R 2U' R' B'
I need an algorithm to solve the edge parity on my 3x3 void cube. I need to switch the two remaining corner pieces because they are permutated incorrectly. I have all the other edge pieces solved and the two other corners solved. I tried to upload a picture but by the time it was sized small enough to fit it was impossible to see. Thanks again.
An interesting 2gen sequence (ignore the centers):
M U' M' U M' U M' U' M
A variation which only affects the E centers:
M U' M' U M' u M' u' M
And finally, a void parity:
M U' M' U M' U M' U' R U R' U' M U R U' R'
What is M?
Sorry for the noob question but is there a way to get only the top front edge and the bottom front edge to stay where they are but flip the colors. The cube is solved except for those two edges. They are in the right spots just the colors are backwards
amazing. Thanks!x ((M' U)3 M') U2 ((M' U)3 M') x'. There are shorter and faster, but this one is okay and is the easiest to remember I think. The first and last sequence of moves is the same.