Odd WCA stats/ Stats request Thread

[Ollie]

Could someone compile a list of ID with no members? Probably need to spoiler it though.

With no members?

 

[guysensei1]

With no members?

I assume he means list of 4 letter strings with no corresponding WCA ID's, AAAA would be one of them.

 

[Ollie]

I assume he means list of 4 letter strings with no corresponding WCA ID's, AAAA would be one of them.

I calculated 440741 combinations that have been unused. Definitely too many to list!

Lazy/bad R code:

library(data.table)

## calculate all possible ID combinations
test <- expand.grid(letters, letters, letters, letters)
test <- paste0(test$Var1, test$Var2, test$Var3, test$Var4)

length(test) # 456976

# used IDs
df <- fread("WCA_export_persons.tsv", select = 1)
df <- unique(substr(df$id, 5,8))

length(df) # 16235

# unused IDs
length(test) - length(df) # 440741

 

[shadowslice e]

Out of the people with no nemesis, who has the highest sum of ranks?

 

[guysensei1]

Out of the people with no nemesis, who has the highest sum of ranks?

Used to be Nicolas Naing since he only did mega and had a WR

 

[Jaysammey777]

HAs there ever been a mbld rank in competition decided by number of cubes missed (ie points and time were the same)?

 

[Torch]

HAs there ever been a mbld rank in competition decided by number of cubes missed (ie points and time were the same)?

Worlds 2013, Stefan Pochmann and Natán Riggenbach
US Nats 2016, Ryan DeLine and Tim Wong
US Nats 2014, Angel Lim and Riley Woo

I'm sure it's happened other places, but those were the easiest to find.

BONUS: Actual tie with no tiebreaker (Worlds 2015, Ariel Burak and Augusto Rosa Esteves)

 

[sam596]

Has anyone ever got an official MBLD result before they've had an official BLD solve?


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[CJK]

Out of the people with no nemesis, who has the highest sum of ranks?

Or, the other way around:
Out of the people with at least one nemesis, who has the lowest sum of ranks?

 

[guysensei1]

Or, the other way around:
Out of the people with at least one nemesis, who has the lowest sum of ranks?

Would it suffice to only check the people with 1 nemesis?

 

[CJK]

Would it suffice to only check the people with 1 nemesis?

Yes, it would.
I just said that so it sounds better.

 

[TheCoolMinxer]

Has anyone ever got an official MBLD result before they've had an official BLD solve?


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At German Open 2015 I first got a 4/6 mbld and then later the day my first official 3bld, but I think you're asking to have it done in different comps But technically I did so lol

 

[Bubtore]

Has anyone ever got an official MBLD result before they've had an official BLD solve?

Some time ago 1/2 was enough to get a MBLD result, so I guess there are many people who have done that (including myself).

 

[CJK]

Would it suffice to only check the people with 1 nemesis?

After I rethought about this, the answer is no:
Imagine if two people are at #WR1 and #WR2 in all events, but not nemesis of each other and a third person is at #WR3 in all events, then the third one has two nemesis but is still the one with lowest SoR out of everyone who has at least one nemesis.

 

[Berd]

Has anyone ever got an official MBLD result before they've had an official BLD solve?


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Me!

 

[1973486]

Or, the other way around:
Out of the people with at least one nemesis, who has the lowest sum of ranks?

Isn't this just the slowest 3x3 solver?

 

[CJK]

Isn't this just the slowest 3x3 solver?

I thought that if you don't have a rank in an event, for SoR the event is number of participants in that event+1?

 

[Username]

I thought that if you don't have a rank in an event, for SoR the event is number of participants in that event+1?

yep

 

[sam596]

Me!

So you have!


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[pinser]

Youngest person to get an official 3BLD success?