Status
Not open for further replies.
Here are the pictures. I couldn't find a corresponding algorithm to this on Big Cubes site. I've had to break it into 3 steps. Must be an easier way.

IMG_1265.jpg

IMG_1266.jpg

IMG_1267.jpg
 
Here are the pictures. I couldn't find a corresponding algorithm to this on Big Cubes site. I've had to break it into 3 steps. Must be an easier way.
IMG_1265.jpg

IMG_1266.jpg

IMG_1267.jpg
With the orange face on top, blue face on the front, and yellow as the right face,
This is probably the easiest algorithm to memorize (heck, I made it by intuition rather than thinking too much or applying any particular one of my methods): y (Lw2 F2 U2 l' U2 F2 Lw2) (F2 r U2 r' l' U2 l F2) y' (25,15).

But here are some optimal solutions as well (the first two are optimal in half turns and the last two are most likely optimal in quarter turns)

y x Rw B2 r F2 l' U2 l U2 r' U2 r U2 (f2S2b2) Lw' z2 x' y' (21,14) (Kenneth Gustavsson)
y l2 F2 U2 l' U2 l2 F2 l' U2 l2 U2 F2 l' F2 y' (25,14) (from CubeExplorer)

y Uw' Rw Uw r Uw' Rw2 Dw Rw' Uw r Uw' R Dw' Rw Uw y' (16,15)
y Uw' Lw Uw l Uw' Lw2 Dw Lw' Uw l Uw' L Dw' Lw Uw y' (16,15)

or you could just conjugate the directly opposite alg case:
R' U F' Lw' U2 Lw' U2 F2 Lw' F2 Rw U2 Rw' U2 Lw2 (22,15)

EDIT:
Here's a long, but cool solution:
y 3l U 3l' U2 3l' U2 3l U2 3l U 2L' U' 3l' U2 3l' U2 3l U2 3l U 2L2 U2 3l' y' (31,23) (SiGN)
 
Last edited:
Thank you guys for these algorithms. I just woke up and have to head to work. I'll give them a try when I finish. Kind of curious why the Big Cubes site wouldn't have them as it seems to occur quite a bit. (at least for me)
 
what oll's do you guys recommend for oll's 35, 36, 39 and 55?
35 y' R' U2 (R l) U' R' U l' U2 R really confused what to use for this case.
36 R' U' R U' R' U R U R B' R' B looks better than y2 (L' U' L U') (L' U L U) (L F' L' F)
39 y2 R U R' F' U' F U R U2 R' this looks nicer than L F' L' U' L U F U' L' which is what I currently use
55 I use r U2 R2 F R F' U2 r' F R F' and do not really like it. I can not find a good algorithm.
 
Does anyone (cmowla?) know an optimal double parity algorithm for 4x4? I use optimal for OP because it looks cool, but my r,l,F2,U2 or whatever doesn't look cool at all.
 
what oll's do you guys recommend for oll's 35, 36, 39 and 55?
I use those:
35) R U2 R2' F R F' R U2 R'
36) (L' U' L U') (L' U L U) (L F' L' F)
39) L F' L' U' L U F U' L' or y2 R B' R' U' R U B U' R'
55) R' U2 R2 U R' U R U2 x' U' R' U
 
Rawrbert where have you been all of my life? I've never seen that alg for 39. Even though it has a small regrip in how I'm executing it now, I think I already prefer it to the RUB one. Thanks.
 
Does anyone (cmowla?) know an optimal double parity algorithm for 4x4? I use optimal for OP because it looks cool, but my r,l,F2,U2 or whatever doesn't look cool at all.
I believe all of these algorithms are optimal in btm and most are optimal in BQTM (for what they do).

Opposite 4-cycle double parity that doesn't discolor centers
[r F2 l': [U2, l U2 r'] [l F2: r] ] [B2, r'] (21,14) (I am not the original founder of this one)

Adjacent 4-cycle double parity that doesn't discolor centers
[r2 F Rw' F': [U2, r] [r2 U2: r] ] (23,16) (My alg)

Opposite 4-cycle double parity that discolors centers
[Rw' F2: [F u F', D2] [D2: l] ] (15,12) (My alg)
[Rw2 B2: [B2, U r' U'] [U2: r] ] (17,12) (My alg)
[Rw2 B2: [B2, U' r' U] [U2: r] ] (17,12) (My alg)
[Rw2 B2: [B2, U f U'] [U2: l'] ] (17,12) (My alg)

4-cycle double parity that discolors centers and destroys pseudo 3x3x3 state:
[B2: [B2: l'] [B u B', D2] [D2, l] B2] (13,11) (My alg)
[Rw2 B2: [B2, U r' U'] [U2: r] U2] (15,11) (My alg)
[Rw2 B2: [B2, U' r' U] [U2: r] U2] (15,11) (My alg)
[Rw2 B2: [B2, U f U'] [U2: l'] U2] (15,11) (My alg)

Adjacent 4-cycle double parity that discolors centers
[r2 U Rw' U R U: r'] (15,13) (My alg)
[r2 F' U2 F r U2: r'] (19,13) (My alg)

Here are double parities which are not 4-cycles of wings:

[r U2: r'] [D2, r] [B2, r] (19,13) (My alg)

cuBerBruce's algorithm set that destroys pseudo 3x3x3 state
Choose any (one) move in the curly braces before and after the algorithm.
{Uw, u, d } R' b E' d' L' b L u' b2 Uw M' B' {Uw, u, d}(15,15)
{Uw, u, d } S L B' R u d f' u d L B' R S {Uw, u, d}(15,15)
{Uw, u, d } S L' F R' u d f' u d L' F R' S {Uw, u, d}(15,15)

cuBerBruce's algorithms that discolor centers and destroy pseudo 3x3x3 state:
Uw L U B U' d Fw2 u' Fw2 L' Uw2 y (14,11)
Uw L U B d Fw2 u' Fw2 U' L' Uw2 y (14,11)

EDIT:
Just in case you were wondering if I ever attempted to make an optimal opposite 4-cycle double parity algorithm which doesn't discolor centers, I have, and this is the best I came up with, but it does discolor 3 X-center pieces (and it's not optimal in btm for sure)
[Fw: [Rw2 Fw': r'] [Bw': [r, Fw']] ] [U2, r] (17,15)

All of these algorithms are in my "A Collect of Algorithms" PDF in my Methods Thread.

EDIT:
Well I guess for even cubes only, I guess we can have a 14 btm alg ^
[Fw': [Fw' Uw2 Fw, d] ] (l) [U2, l] (19,14)
 
Last edited:
17 -

L' U' L U' L F' L' F U2 L F' L' F

F' L F L2 l U' L' U L U M'

43 -

f' L' U' L U f

F' U' L' U L F

44 -

f R U R' U' f'

F U R U' R' F'

29 -

F' L F' L2 U L U L' U' L F2

30 -

L' U' L U L' U L F U F' L' U' L

Conrad Rider's alg translator is your friend.

EDIT: Immediately after posting this I realized you were looking for OH algs, and you use your left hand. Damnit.
 
OH algs for olls 17, 43, 44, 29, and 30. I use my left hand.
some suggestions ...
17) R U R' U (R' F R F') U2 (R' F R F') // F R' F' R2 r' U R U' R' U' M'
43) f' L' U' L U f // y2 F' U' L' U L F
44) f R U R' U' f' // y2 F U R U' R' F'
29) y2 r U2 R' U' R U' r' R' U2 R U R' U R
30) r' U2 R U R' U r R U2 R' U' R U' R'

ANyone got a nice short square 1 partity alg or algs that work as well the ones I have seen are like 20 moves counting (3,4)/ as one
Define "short" ...

The "standard" parity alg is:
/ (-3,0) / (0,3) / (0,-3) / (0,3) / (2,0) / (0,2) / (-2,0) / (4,0) / (0,-2) / (0,2) / (-1,4) / (0,-3) / (0,3) [13|27]
or if you don't mind swapping some more edges I suggest Z/op or O
/ (3,3) / (1,0) / (-2,4) / (2,-4) / (0,4) / (2,2) / (-3,0) / (-3,-3) / (-3,0) [9|23]
(1,0) / (2,2) / (0,-2) / (3,3) / (1,0) / (-2,-2) / (-2,0) / (2,2) / (-1,0) / (-3,-3) / [10|25]

You can also check out my Sq-1 EP page.
 
Last edited by a moderator:
I'd like to know the algorithm for the 4x4x4 corner parity (During the 3x3 phase, the corners are oriented incorrectly. Two of the colors on each piece are switched.)

As well as how to position it beforehand and when to do it... Anything I need to know.

Also, if I would need to use any pre-existing algorithms, could you post the entire thing instead of just the name of it?
 
Status
Not open for further replies.
Back
Top