[Help Thread] 4x4 Discussion

[avgdi]

I just started doing 4x4 and I use thispage for all my parity algorithms. It's very helpful.

 

[jiggy]

I'm not positive, but I think if you are careful about what you are doing, you can avoid parity on a 5x5. If you can't, you can use the 4x4 OLL Parity to fix it right up (so you don't have to learn anything extra for the 5x5).

I am by no means a big cube expert, I solve them slowly and just for fun =P so I'm fully prepared to be corrected on this. However, I think that you can come across two forms of edge-pairing parity on the 5x5, one of which can be solved with the 4x4 OLL parity alg, the other requires a different alg.

1 _________ 2 ______ 2
2 ___ Or ___ 1 ______ 2
1 _________ 1 ______ 1

 

[RCTACameron]

Yes, but technically it is this:

1 or 2 2
1 or 1 2
1 or 1 1

The 1 in the middle in the first case is just flipped.

There are also combinations of the cases, when the last two pairs look very confusing, but you just have to use both algs.

 

[jiggy]

Yes, but technically it is this:

1 or 2 2
1 or 1 2
1 or 1 1

The 1 in the middle in the first case is just flipped.

Fair point, I was just trying to make them visually distinct, but you are technically correct...the best kind of correct.

 

[Tsopi]

4X4X4 SpeedSolving

What is the best method to solve the rubiks revenge?

 

[chris410]

To begin try searching on K4 or reduction.

 

[mr6768]

there are 2 methods . reduction and K4 . K4 is much harder and has a lot algorithms but i'm not sure its the fastest .
I suggest reduction

 

[Fire Cuber]

Reduction

Reduction

Reduction

Reduction

Reduction

yes, it is reduction

 

[Kirjava]

K4 is much harder and has a lot algorithms

lol K4 is like two algorithms

I suggest Yau.

 

[Fire Cuber]

there are 2 methods . reduction and K4 . K4 is much harder and has a lot algorithms but i'm not sure its the fastest .
I suggest reduction

REALLY?

 

[deadalnix]

there are 2 methods . reduction and K4 . K4 is much harder and has a lot algorithms but i'm not sure its the fastest .
I suggest reduction

It's always fun to act like you know everything in front of somebody which is even more ignorant than you are, right ?

Anyway, reduction, K4 or Yau's method are both very effective.

 

[rachmaninovian]

sandwich D:
just kidding its too hard

 

[mr6768]

REALLY?

Based what i've read on this page :http://snk.digibase.ca/k4/index.htm
yes , there were a lot algs .
Am I wrong anyway ?

 

[emolover]

Reduction

 

[masterofthebass]

Based what i've read on this page :http://snk.digibase.ca/k4/index.htm
yes , there were a lot algs .
Am I wrong anyway ?

every one of those "algs" is just an intuitive commutator that thom wrote out for people. I personally haven't learned 1 ELL alg for K4.

 

[Cride5]

Reduction is a pretty loose classification IMO. There are a number of different approaches which can be used in a reduction-based method - mainly in the choice of edge pairing and 3x3 method used in the final solve.

Technically I do 'reduction' but the edge pairing phase and final solve are much more ZZ-ish than a CFOP-based reduction method: http://www.speedsolving.com/forum/showthread.php?t=23617

 

[vinylen]

4x4 edge pairing, best method?

Thought i'd start with some 4x4 practicing, how do you pair up for edges? two at a time or more? do you have any tips/good tuts on utube to help me out?

cheers

 

[emolover]

You could use something like the Yui method and pair up 3 at a time, but what I preference is reduction. You just have to be good at lookahead on the 4x4. Yui is also hard to learn.

 

[vcuber13]

its yau, and its still reduction its just a variation

 

[emolover]

its yau, and its still reduction its just a variation

Wow I failed. Everything is a type of reduction unless you solve the 4x4 like a 3x3.