dougbenham
Regular
No, it's a conjugation: PQP' where P = F2 U F' U' and Q = (R U R' U')3. Commutators are of the form PQP'Q'.its just a commutator
Ah yes my bad. Thanks for that.
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No, it's a conjugation: PQP' where P = F2 U F' U' and Q = (R U R' U')3. Commutators are of the form PQP'Q'.its just a commutator
This is for OLL 23: (R U2' R' U) (L' U2 R U' R' U2 L)
M U M2 U M2 U M U2 M2 U'
I like doing M' over M. But you can make that
M' U M2 U M2 U M' U2 M2 U'
right?
I like doing M' over M. But you can make that
M' U M2 U M2 U M' U2 M2 U'
right?
That algorithm is already up on the Wiki. I was just pointing out that you can do M over M'. I have an easier time with that.
Wow... someone that prefers M over M'? You don't see that everyday.
Wow... someone that prefers M over M'? You don't see that everyday.
Me. You see me quite often, don't you?![]()