Random Cubing Discussion

Another programming question: Has anyone tried to write a program that approaches solving a cross the way a human being would approach it?
 
No not really the point wasn't really to go fast though it was to have fun. I never looked up a tutorial or anything.

Rawr.
I used to use it and avged like 1:20 (fast for me at the time)
Now I pair *most* of the edges before LSE. Gotten some sub-1s with it (fast for me at the time, i havent touched 4x4 for months).
It's not awfully awful.
 
I found it that the harder i made it the more fun it would be. So, I solved the block on the right/left did corners then i solved the rest of the centres then using 5x5 parity algs solved the other edges.

Edit: after the edges were all paired up I just did lse normally.
 
Make slow turning the new thing!
Also how does it feel to be the fastest cuber in the world?

I'm feeling Feliks' Fanboys running furiously towards you... I don't know if I'm the fastest tbh. I have the fastest avg100 sure but...

Eh, well it feels nice to be fast- I don't exactly feel like a champion, but it makes me excited to see whether I can break any records at my next comp.

It doesnt feel like I am one of the fastest though. Although I've had a very fast avg100 it doesn't feel like I am fast- it feels it'll need to be done officially.
 
Unifficial event: a random time is generated, The timer is covered and the competitors have to get as close to that time as possible, but not be under it.

I.e scramble is generated along with time, 15.68. Timer is covered up, competitor solves as usual but attempting to get as close to 15.68 seconds as possible without going under it. Why? Because.
 
Unifficial event: a random time is generated, The timer is covered and the competitors have to get as close to that time as possible, but not be under it.

I.e scramble is generated along with time, 15.68. Timer is covered up, competitor solves as usual but attempting to get as close to 15.68 seconds as possible without going under it. Why? Because.

Well, if you average a few seconds over that, then you would just go flat out. So giving faster cubers less of an advantage. I'm assuming that bang-on would be 0.00, 17 seconds (using your example of 15.68) would be a time of 17 - 15.68 = 1.32, and a time under 15.68 would be DNF. So, what would the average be? Ao5 would mean you would only be able to have 1 DNF.
 
Yes, the whole idea is that faster cubers don't have an advantage. Most cubers never have a hope in hells chance I winning anything, but something like this would be fun for everyone. Kinda like the Magic, makes people think they are good at something. Yes finishing too soon would be a DNF, but that's the risk you have to take.
 
Hm... What kind of cube-pranks do you know? For example, I just found a way how to play a trick on a non-cuber (or not-so-experienced cuber):

Perform this on a solved 4x4: u2 M2 Uw2 M2 U2 M
Cuber: "If you can solve this for me in a few seconds, I pay you a beer!"
Non-cuber: "Yeah, free beer!" (Get the cube) "Wait, what?" (Doing R L R' L2 R etc.)

Another prank (whick I actually use... occasionally... sorry) is the next one:

Cuber: "If I scramble the cube with only ONE move, can you undo it?"
Non-cuber: "Sure!"
Cuber: (Execute R'UR' or a similar fingertrick - it is one move after all... even in its sound) "Your turn."
Non-cuber: (blinks)
Cuber: (Do the inverse with the same speed)
 
Hm... What kind of cube-pranks do you know? For example, I just found a way how to play a trick on a non-cuber (or not-so-experienced cuber):

Perform this on a solved 4x4: u2 M2 Uw2 M2 U2 M
Cuber: "If you can solve this for me in a few seconds, I pay you a beer!"
Non-cuber: "Yeah, free beer!" (Get the cube) "Wait, what?" (Doing R L R' L2 R etc.)

Another prank (whick I actually use... occasionally... sorry) is the next one:

Cuber: "If I scramble the cube with only ONE move, can you undo it?"
Non-cuber: "Sure!"
Cuber: (Execute R'UR' or a similar fingertrick - it is one move after all... even in its sound) "Your turn."
Non-cuber: (blinks)
Cuber: (Do the inverse with the same speed)

Swap two adjacent faces.
 
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