obelisk477
Veteran
What's the number of possible LS positions, disregarding pre-AUF? I can't figure out how to not double count AUF psotions, I always get confused
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What's the number of possible LS positions, disregarding pre-AUF? I can't figure out how to not double count AUF psotions, I always get confused
if the corner is in U, always bring it above the last slot
for cases where the corner is in place, it can be in one of 3 orientations, and the edge can be in place oriented, in place flipped, in U oriented, or in U flipped. One of these cases is solved so 3*4 - 1 = 11 cases with the corner in place
for cases where the corner is in U, it can still be in one of 3 orientations, and the edge can be in place oriented, in place flipped, or in any of the 4 U positions flipped or oriented. 3*10 = 30 cases with the corner in U
11 + 30 = 41
basically all these: http://algdb.net/Set/F2L
Doh...I meant including LL CO and EO
The top 100 3x3 singles are about to all be sub 7!
He was talking about indervidual people.Just out of interest, how many of those are feliks? Half?
Just out of interest, how many of those are feliks? Half?
The maximum possible TPS is around 947,045,759 TPS.
Maximum "radius" of a cube is diagonal to center, so 57 cm * sqrt 2 * 0.5 * 0.01 m/cm = 0.403050865 m
Multiply by pi/2 for length of arc: 0.633110819 m
divide by speed of light: about 2.1 ns
1/x: 947,045,759 TPS
Edit: oops unit fail multiply answer by 10:
9,470,457,590 TPS
Seriously no one got this idea?? (Everything is hypothetical)(cube it friction less)
Assume that the corners (of the corners of the cube) are moving at light speed and the cube is regular 57mm.the corners would be (57/2)*sqrt2 away form the axis of rotation.therefore the circumference would be (57/2)*sqrt2*2pi = 57*sqrt*pi.dividing it by 4 to get the length traveled by the corner in one Quater turn (57*sqrt2*pi/4).Dividing this by speed of light (in mm/s) to get the minimum time taken for one quarter.(2.112 x 10^-10 sec per move)And then multiplying this value with god number ie. 26 (in QTM). The final answer is 5.491 * 10^-9 seconds or approx 5.5 nano seconds
Ok what year will all the top individual 100 singles be sub 6? I'm gonna say 2021
Did OLL parity and lost my grip and damaged the sticker in a rather interesting way...
View attachment 5724
Including parity, how many cases are there for solving the square-1 that's cubic with 1 alg? Would it be in the thousands?
i think it would be 8!x8!/8/2 (rotations and Aufs)= ~46million