porkynator
Veteran
I bothered to find a (partial) solution after all.
S: R' U' F D2 L2 D2 B2 D2 B' F2 L2 B L2 D' F2 D2 L R2 B' F2 D' B R2 U' R' U' F
F U' F U2 R' F U F'//2x2x3 (8)
inverse,
L U' L2 B2 L//EO
U B2//F2L-1
normal,
B U B' U B U B'//4C
IF gives 29
There is a pretty easy (=almost CFOP) linear continuation for 28 total moves:
F U' F U2 R' F U F'
U2 B L' B' L
B R' U R U'
U' B2 U
L' B2 L B L' B L B2
