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35 htm
x z
L' R' D' // 3/4 cross
R' F U' F' R // f2l1 + f2l2
y' U L' U2 L // f2l3
U R' U F' r U R U' r' F // cls
M' U' M U' M' U' (M) // last cross edge + eo
(M2) U' M2 U2 M2 U' M2 // pll

D2 L U2 F' R2 F2 D' L' D' F2 R2 B2 L2 U2 R2 D' F2 R2 D L2 R

after inserting the first pair all 3 other pairs were somehow already made and in the top layer (can go crazy with multislotting)

Spoiler: reconstruction

z x2 // inspection
R B D' L // cross
R' U2 R L' U L// 1st pair, at this point all 3 pairs are made
U' R' U R// 2nd pair
U2 R' F R F' // 3rd pair
U L U' L' // 4th pair
U2 R' U' F' U F R // OLL
U M2 U M U2 M' U M2 // PLL
U2 // AUF

Ok, but if it's from a 2x2 then it wouldn't be consider lucky for 3x3 because the scramble doesn't even belong to a 3x3. Is like saying you got an easy scramble on a 4x4, but that scramble was from a 2x2 or 3x3.