brododragon
Veteran
There are way less algs
Petrus is like, so dead now.
- Thread starter PetrusQuber
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PetrusQuber
Legend
But is learning it worth it over ZBLL if I didn’t care about alg count?
brododragon
Veteran
I would learn zbll if I had that will power.
PetrusQuber
Legend
Maybe I should use Petrus-blah when I finish two sets of ZBLL, until I complete the whole set.
Tao Yu
Veteran
Personally, I find Pi and H to be the ZBLL sets with the hardest recognition and the worst algs. Forcing them every solve doesn't sound like a good time, but maybe you could make it work if you have better algs and a better recognition system than me.
brododragon
Veteran
I find the easiest way to learn recognition is just practice and let your subconscious do the work.
D
Deleted member 36445
Guest
lol you're telling Tao Yu to practice? xD
D
Deleted member 51471
Guest
Like he doesn't do that enough learning full ZB and having sub-10 singles with 10 different methods.
brododragon
Veteran
I'm just saying how I do it.
D
Deleted member 51471
Guest
We were just joking.
brododragon
Veteran
I know. I was just clarifying.
Tao Yu
Veteran
This is how I learned ZBLL recognition. I'm saying that in my experience, I found it easier to subconsciously learn patterns in the T, U, L, S and As sets than in the Pi and H sets.
dudefaceguy
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- Joined
- Feb 17, 2019
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I use a variation of the Petrus corner method as 2-look CMLL in Roux (and any other time I need to solve corners). Permuting first enables 2-look CMLL with only 4 algorithms. Here's my prior post about it, with a flowchart:
www.speedsolving.com
The New Method / Substep / Concept Idea Thread
Anybody here know of alternative 2-look CMLL methods? I've refined the permutation-first Petrus variant that I posted a few weeks ago. Here's a new flowchart: I can't find anything else besides orient-first methods that use 9 algorithms. I don't care if the other methods are good or fast - I...
www.speedsolving.com
fuzzballcat
Member
Who else here uses Petrus on 2x2?
brododragon
Veteran
PetrusQuber
Legend
I guess? I mean, it’s kinda hard to distinguish from other methods which do LBL, like ortega...
ProStar
Legend
I once made a joke about 3x3 methods on 2x2. Even if you do Roux or Petrus, it's still just 1st layer LL in some way lol
dudefaceguy
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- Feb 17, 2019
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Roux is actually very similar to Petrus, and I really see it as an improved version of Petrus. This is because the last layer in Petrus is the same as the last steps of Roux, but less convenient than Roux. In both methods, you solve the last layer’s corners first and then solve edges. But Roux gains an advantage by leaving 6 edges unsolved until the last step, rather than solving the DF and DB edges early (too early).
The Allan algorithm that the Petrus method uses to solve the last 4 edges is a conjugate of the same 4-move commutator that Roux uses to solve the last 4 edges. In Petrus, the DF and DB edges are already solved so we have to perform and undo setup moves. In Roux we avoid this by leaving the DF and DB edges unsolved.
So Roux and Petrus are really the same, except for the DF and DB edges. In Petrus you solve them early, which restricts your moves without any substantial benefit, and also requires you to break and restore them in the last step. So, just do Petrus but leave these 2 edges unsolved until the last step. This is Roux.
The Allan algorithm that the Petrus method uses to solve the last 4 edges is a conjugate of the same 4-move commutator that Roux uses to solve the last 4 edges. In Petrus, the DF and DB edges are already solved so we have to perform and undo setup moves. In Roux we avoid this by leaving the DF and DB edges unsolved.
So Roux and Petrus are really the same, except for the DF and DB edges. In Petrus you solve them early, which restricts your moves without any substantial benefit, and also requires you to break and restore them in the last step. So, just do Petrus but leave these 2 edges unsolved until the last step. This is Roux.
brododragon
Veteran
Well, Petrus-W is a compromise.
PetrusQuber
Legend
We... Don’t... Really use Allan now. (F2 U’ R’ L F2 R L’ U’ F2). Plus you can 1LLL the last layer.
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