Random Cubing Discussion

So I have these transparent Aolong V2 force cubes and I'm curious, how much do you guys think they're worth? I'm thinking about selling them on the Buy, Sell, Trade forum eventually since I really only use the blue one. They aren't stickered but are all lubed and tensioned and mostly unused, only turned to see if the tensioning was good.

I'd say $2-3 more than what an Aolong normally costs.
 
okay, how many algs for:
1) move all white to the bottom, all yellow to the top with 1 alg
2) solve everything with 1 alg

Hey, guess what method I've been working on :P

So, counting all AUFs/ADFs as different, and all mirrors/inverses as different, there are 4900 different OBL cases and 331,776 different PBL cases. Eliminating only AUFs and ADFs, this goes down to 336 and 20,736. Practically, 'tho, after reducing for most of the common symmetries, there are only 74 different OBL cases, and 1936 PBL cases. Because of this, I think that 1-alg OBL is tractable, but PBL is gonna have to be two algs for a good while.

4900 OBLs = (8 choose 4)^2, choose which of the 8 corners/edges will be white, twice
331776 PBLs = 4!^4, 4! for each set of U/D layer corners/edges

336 ABF-unique OBLs = computer-generated with a program my girlfriend wrote - sorry no better source :< We're working on making the method actually fully nice-looking and usable first.
20736 ABF-unique PBLs = (3! * 4!)^2, fix one corner in each layer, and permute the other pieces

74 unique OBLs = again, computer-generated. Accounts for L-R symmetry (eg, we count 1,0 / 3,0 / the same case as 0,-1 / 3,0 /), U/D symmetry (eg, we count 1,0 / 3,0 / the same as 1,0 / 0,3 /), and yellow-white symmetry (we count the solved case to be the same as / 6,6 /). There's actually another possible symmetry case one could use, which is corner-edge symmetry (so, 1,0 / -1,-1 / is the same as 1,0 / 2,2 /), but the algs "feel" different enough and most people [at least, in my experience] don't normally visualize this symmetry, so most of our work will be focused on not using that symmetry.
1936 unique PBLs = 44^2, there are 44 "unique" PLLs including the solved case (this is easily confirmed by looking up Square-1 PLL alglists, which all list 43 different algs)
 
(slightly off-topic)
What happened to your Youtube channel btw?

One of my videos got removed, I think it was the thing about scrambles in the description. Then somehow that was considered "repeated or severe violations" and the channel was suspended. I appealed the video removal, and they said the video got put back, but the channel is still suspended. Now I don't know what to do :( I can't appeal the suspension.
 
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