[Help Thread] Void Cube Discussion

[aronpm]

Still gets parity =/

Parity can be fixed with 1 move, without having to resolve a lot of the cube.

 

[Godmil]

Interesting. But could you post some text in your posts please instead of just a video.

 

[BrainOfSweden]

I didn't set a new PB? o_O

I think he ment that even if you do, you'd still be angry

OnT: Why do you care about color scheme on this type of puzzle? Personally a like a little variation. I keep my speedcubes the same though.

 

[d4m4s74]

in fact, as far as I understand it's a completely new design by Mr. Okamoto

 

[benskoning]

Interesting. But could you post some text in your posts please instead of just a video.

sure i will edit the now.

 

[JohnLaurain]

If this gets good reviews I might just have to get one

 

[Johnny]

Void cube parity solution in plain English?

I know that this question has been asked, but I cannot understand what the hell they are talking about. Can anyone just straight up give me the algorithms?

 

[Username]

M'

 

[Ollie]

This? l U r' U M U' M' r U' R' U M U'

 

[DrKorbin]

z2 (R U R' U' y)*7

 

[antoineccantin]

I would do M' U' M' U M U M U2 r U R' U' M' U R U' r' which does an O-perm

Spoiler: Explanation

M' -->fix parity
U' M' U M U M U2 M' --> Solve F2L
R U R' U' M' U R U' r' -- Solve OLL

 

[qqwref]

(M' U)2 (M' U')2 M' U2 (M' U')2

 

[ben1996123]

M'

yes.

 

[TheMachanga]

M.


Just do an M move (middle slice), and solve again from there.

 

[Ton]

M'

With the M or M' move you basically move 4 pieces let say 1 2 3 4 in the order 2 3 4 1 because you can get from 1 2 3 4 with 2 pair swaps like swap 1 2 than 2 3 and than 3 4 , we used 3 pair swaps , that makes it an odd parity

It follow the same principles as numbers so a odd and odd parity is even and an odd and a even remains odd

 

[chardison1980]

Solve it using roux

 

[AndersB]

I just do an E and resolve from there (better for CFOP then doing M).

 

[Stefan]

I just do an E and resolve from there (better for CFOP then doing M).

How is destroying all four F2L pairs better than destroying just two cross edges which are trivial/fast to repair and even keeps corners oriented (and permuted)?

 

[MWilson]

(R' F D2 r U) M' (U' r' D2 F' R)

Put all LL edges in M layer such that they are all facing the same way around the x axis:
R' F D2 r U

Cycle them while fixing center parity:
M' (or M, but that's awkward, and M2 is just a H PLL)

Put the LL edges back:
U' r' D2 F' R

Does a CW ELL cycle and CW M layer center cycle, and can be done easily with no regrips.


If you only need to swap two edges, you can use any of the following

Swap UF and UR:
M U M' U2 F2 U M' U' F2 (U)
M U' F2 U2 M U' M' U' F2 (U)

Swap UF and UL:
M U' M' U2 F2 U' M' U F2 (U')
M U F2 U2 M U M' U F2 (U')

Swap UB and UR:
F2 U M U M' U2 F2 U M' (U')
F2 U M U' F2 U2 M U' M' (U')

Swap UB and UL:
F2 U' M U F2 U2 M U M' (U)
F2 U' M U' M' U2 F2 U' M'(U)

I personally like M U' M' U2 F2 U' M' U F2. For swapping two adjacent edges just use setup moves.

 

[Lucas Garron]

I find qq's alg the best. It's been 5 years, and I still haven't forgotten it. (Wait... *five*? Yikes.)

(M' U)2 (M' U')2 M' U2 (M' U')2

There's a thread about it here with early discussion when void cubes came out.

(Please consider searching a bit more carefully next time before asking a question, or use the One Answer Question thread.)