next (0, -4) / (0, 3) / (-5, -5) / (-1, -4) / (4, -5) / (-3, 0) / (-4, 0) / (3, 0) / (3, 0) / (4, -3) / (2, 0) / (4, 0) / (-4, -5)
Oops, didn't see your post when I started writing mine, sorry for the hijack >.<
Solution:
z2 -4,-1 / 0,3 / -2,0 / 2,0 / -1,0 / -3,0 / # cubeshape, noting that there's a yellow corner bar on DL (preserved through the 2-gen shield/kite cubeshape solution)
0,3 / 3,0 / 4,1 / -1,-4 / # obl, bleh don't like this case, may be faster to just go to 3-edge swap
1,4 / -3,0 / 3,3 / 0,-3 / # cp, setting up for u/adj, which is faster for me than other alternatives
5,3 / 3,3 / 1,0 / -2,-2 / 2,0 / 2,2 / -1,0 / -3,-3 / 0,2 / 0,-3 / 1,1 / -3,0 / -4,6 # ep, u/adj
Next: (4,0) / (6,0) / (0,3) / (-4,-4) / (-2,-5) / (3,0) / (-4,-3) / (-3,0) / (0,-1) / (-4,0) / (0,-5) / (2,-3) / (-4,-2)
Solution:
-2,3 / 2,0 / -4,0 / -2,-1 / -3,0 / # cs, keeping DL bar alive; thought I was gonna have a CO skip, but the U layer corners in kite-scallop were opposite T__T
0,1 / -3,0 / -3,0 / # obl, welp at least this was easy

-1,-3 / -3,0 / 3,3 / 0,-3 / # cp, set up for -/adj (aka, solve all the blocks, notice it'll be -/adj)
0,6 / 0,3 / -3,0 / 3,0 / -3,0 / 0,-2 / -2,0 / 0,2 / 0,-4 / 2,0 / -2,0 / -4,1 / -3,0 / 6,0 / E2 # ep, doing the 6,6 by double-flicking the middle layer
Next: (0, -4) / (-3, 0) / (3, 0) / (0, -3) / (3, 0) / (6, -5) / (3, 0) / (1, -4) / (-2, 0) / (0, -4) / (-4, 0) / (2, 0) / (0, -5) / (6, -4)