Hssandwich
Veteran
Exeter Open 2016
D R F' D' L2 B2 L' D F2 B U2 B' U2 L2 B U2 B2 D2 R2
I know I DNFed, but I was quite content with my 22 moves to 4C, sadly, it was two 2 cycles.
B2
F' U F U R' U2
L F' D F
R D' R' D2 B2
L' D L B D2 B'
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Exeter Open 2016
D R F' D' L2 B2 L' D F2 B U2 B' U2 L2 B U2 B2 D2 R2
Nice, thanks for the tip! Still wouldn't have beaten your solution though.Wow didn't have an F2L-1 this short! Your continuation is obvious enough after that, but how about this...
R D' F' U F' U' F R2 F R' D // 3 corners (think of it as building the RBW block in a convoluted way, while making an extra pair)
Skeleton B2 U * L F2 D R' F B2 R D' F' U F' U' F R2 F R' D
Insert B' L F2 L' B L F2 L' to cancel 4 moves = 23 moves![]()
Switch to inverse then D L B L' F' R' B R F B' D' to leave 3 cornersI know I DNFed, but I was quite content with my 22 moves to 4C, sadly, it was two 2 cycles.
B2
F' U F U R' U2
L F' D F
...
Cool solution! I knew that the solve would not beSwitch to inverse then D L B L' F' R' B R F B' D' to leave 3 corners
Skeleton B2 * F' U F U R' U2 L F' D F B' D B R' B' R L B' L' D' (23)
Insert at * D' F' U2 F D F' U2 F to cancel 3 moves
28 moves
Optimal double insertion from your actual skeleton gets you 30 btw. What else did you expect apart from two 2cycles when you had 4 corners left? 2+2 and 3+1twisted are both just double insertions.
Not that the dadams scrambles are the highest honor in all of FMC, but I really think these two solutions are beyond suspicious. They seem like Kociemba 2-phase solutions to me.
https://www.ocf.berkeley.edu/~dadams/fmc/profile/218/
It is a cyclic shift ABA' CB'C'This way the structure is much clearer, but I still have no idea how and why they work.
Anyone?
From time to time the insertion finder uses a special kind of edge commutators I do not understand.
Example:
L F R U' R' F' L' B' U B
One thing I noticed is that you can swap moves, so the commutator above can be written like this:
F (R U' R') F' L' (B' U B) L
This way the structure is much clearer, but I still have no idea how and why they work.
Anyone?
Ahh thanks, IF couldn't come up with anything.Optimal for your L3C skeleton is 29:
U F R2 F' L' [@1] F R2 F' R L' D R' B2 L' D L D' B L2 B2 U B U'
Insert at @1: L' B2 L F' L' B2 L F
Fewest moves: 29. 2 moves cancelled
The final solution: U F R2 F' L2 B2 L F' L' B2 L F2 R2 F' R L' D R' B2 L' D L D' B L2 B2 U B U'
However the cruel truth is that, if you had done a different cycle at the same place you'd get a 26:
U [@1] L2 R D R' B2 L' D L D' B L2 B2 U B U'
Insert at @1: F L' B L F' L' B' L
After the 1st insertion: U F L' B L F' L' B' [@2] L' R D R' B2 L' D L D' B L2 B2 U B U'
Insert at @2: B L B' R' B L' B' R
Fewest moves: 26. 6 moves cancelled
The final solution: U F L' B L F' B' R' B L' B' R2 L' D R' B2 L' D L D' B L2 B2 U B U'
I have two differet nice solutions for this week's weekly scramble.
Scramble: U L2 F2 B R2 L B2 U' R2 B' U2 F' B R F2 D2 L R' B' U2
"Standard" solution with nice ending (24 HTM)
Corners first/domino solution (24 HTM)(B2 U') //Square (2/2)
B2 //Another square (1/3)
U' F' U2 R' //XXcross (4/7)
F L' D2 L F' D //All but 4c4e (6/13)
(R F R U2 R) D2 (R' U2 R' F' R') //Conjugate and solve (11/24)
B' * U' L F' //Orient corners (4/4)
* = B2 D2 B2 D2 B2 D2 //Domino reduction (5/9)
U2 R2 D' F2 L2 U L2 F2
B2 U' B2 U B2 U B2