[Help Thread] FMC Discussion

[Hssandwich]

Exeter Open 2016
D R F' D' L2 B2 L' D F2 B U2 B' U2 L2 B U2 B2 D2 R2

I know I DNFed, but I was quite content with my 22 moves to 4C, sadly, it was two 2 cycles.

B2
F' U F U R' U2
L F' D F
R D' R' D2 B2
L' D L B D2 B'

 

[G2013]

Under 25 FMC solves are genius solves/solvers or stupid scrambles. Mostly the 1st one, though.
I have to start doing FMC again

 

[Mollerz]

Exeter scramble was bad I had too many options and not enough good continuations, obviously I missed all the good ones! Always ended up with 4 corners or 3c but with a skeleton that was just too long. I need to work on my efficiency going through an attempt I think.

 

[Evan Liu]

Wow didn't have an F2L-1 this short! Your continuation is obvious enough after that, but how about this...
R D' F' U F' U' F R2 F R' D // 3 corners (think of it as building the RBW block in a convoluted way, while making an extra pair)
Skeleton B2 U * L F2 D R' F B2 R D' F' U F' U' F R2 F R' D
Insert B' L F2 L' B L F2 L' to cancel 4 moves = 23 moves

Nice, thanks for the tip! Still wouldn't have beaten your solution though.

 

[kinch2002]

I know I DNFed, but I was quite content with my 22 moves to 4C, sadly, it was two 2 cycles.

B2
F' U F U R' U2
L F' D F
...

Switch to inverse then D L B L' F' R' B R F B' D' to leave 3 corners
Skeleton B2 * F' U F U R' U2 L F' D F B' D B R' B' R L B' L' D' (23)
Insert at * D' F' U2 F D F' U2 F to cancel 3 moves
28 moves

Optimal double insertion from your actual skeleton gets you 30 btw. What else did you expect apart from two 2cycles when you had 4 corners left? 2+2 and 3+1twisted are both just double insertions.

 

[Hssandwich]

Switch to inverse then D L B L' F' R' B R F B' D' to leave 3 corners
Skeleton B2 * F' U F U R' U2 L F' D F B' D B R' B' R L B' L' D' (23)
Insert at * D' F' U2 F D F' U2 F to cancel 3 moves
28 moves

Optimal double insertion from your actual skeleton gets you 30 btw. What else did you expect apart from two 2cycles when you had 4 corners left? 2+2 and 3+1twisted are both just double insertions.

Cool solution! I knew that the solve would not be 0 and I was hoping it might be sub 35. I ran out of time for insertions, so I just tried to do OLL and PLL, but I messed something up hence the DNF...

 

[adimare]

Not that the dadams scrambles are the highest honor in all of FMC, but I really think these two solutions are beyond suspicious. They seem like Kociemba 2-phase solutions to me.

https://www.ocf.berkeley.edu/~dadams/fmc/profile/218/

I kind of lost interest in submitting solutions to that competition because of how often that happens. Last time I competed these were the results:
https://www.ocf.berkeley.edu/~dadams/fmc/107/

 

[andersonaap]

Can anybody help me with this?

B2 D' R2 D L2 R2 F2 D F2 D2 F2 R B2 D' L' U L F U' L2 D'

(D2) // HOLDS PAIR
(B2 U' B) // EO
(L' U) // SQUARE
(L) // PSEUDO 2X2X2
R2 B2 // SQUARE
R B2 // SQUARE
L // 2X2X2
U' // F2L-1 -1CORNER
R2 // AB2E5C

Can I finish with 5 corners left?
Some insertion is applied for edges from here?

 

[irontwig]

Generally, no. You should go back and see if you can continue on your start in another way, since parity takes too many moves to fix.

 

[Cale S]

23 for current Weekly FMC with insane edge insertions

Spoiler

Scramble: U L2 F2 B R2 L B2 U' R2 B' U2 F' B R F2 D2 L R' B' U2

(B2) // square
B' L // another one
(U) U2 R' D' U // 2x2x3
U D' L' D (L) // F2L - 1
(U' F U F' U L') // L4E

skeleton: B' L U2 @ R' D2 U2 L' D L U' F U' F' U L' U' B2
@ = [E, R2] // 6 mover cancels 2

L3E skeleton: B' L U' D' F2 % U' D R U2 D2 L' D L U' F U' F' U L' U' B2
% = [F D F', E'] // 10 mover cancels 8

Final solution: B' L U' D' F' D F' U' D R U2 D L' D L U' F U' F' U L' U' B2 (23)


20 in ATM heh

 

[BQ]

I just got the solution from Jiejie Du (2010DUJI01), who broke the AsR in the Cross-strait FMC 2016 last weekend.
#1

Spoiler

scramble: R' U' F R2 U2 R D2 L D2 R2 U2 R D R F' D2 B2 R' U2 L D L2 B' R' U' F
solution:
pseudo 222: NISS L D2 //2
222: NISS D2 * //1
223: NISS D R D2 F2 D F' //6-1
TEC: R F R F' U2 //5
233: R2 F R F' //4
L3C: U' R' B' R B U //6
insert at *：F' U' B' U F U' B U //8-4
final solution:
D2 F' U' B' U F U' R' B R U F R' F' R2 U2 F R' F' R' F D' F2 D2 R' D L' //27f

#2

Spoiler

scramble: R' U' F R2 F2 D2 F2 D2 U' B2 R2 D2 L2 B R2 U2 F2 R' U2 L D' B2 U B R' U' F
solution:
223: R * D L' D' F D R D2 //8
233-1C: B' R2 B R' B R B //7
L3C: R2 D' R F' R' F R' D R' //9
insert at *: R2 D L' D' R2 D L D' //8-7
final solution:
R' D L' D' R2 F D R D2 B' R2 B R' B R B R2 D' R F' R' F R' D R' //25f

#3

Spoiler

scramble: R' U' F R' B2 R D2 R2 U2 B2 L2 D R B R' F2 R U2 L D2 R2 B R' U' F
solution:
222: R U B' R' B2 * //5
pseudo TEC: D2 F D' F' R' D' //6
TEC: NISS F //1
233: NISS U' R' U R U' R' U //7
L3C: U R F R' F' U' R2 //7-1
insert at *：F' U' F D2 F' U F D2 //8-3
final solution:
R U B' R' B2 F' U' F D2 F' U F2 D' F' R' D' U' R' U R U' R' U2 R F R' F' U' R2 F' //30f

 

[Laura O]

From time to time the insertion finder uses a special kind of edge commutators I do not understand.
Example:
L F R U' R' F' L' B' U B

One thing I noticed is that you can swap moves, so the commutator above can be written like this:
F (R U' R') F' L' (B' U B) L

This way the structure is much clearer, but I still have no idea how and why they work.
Anyone?

 

[Daniel Lin]

This way the structure is much clearer, but I still have no idea how and why they work.
Anyone?

It is a cyclic shift ABA' CB'C'

 

[Hssandwich]

Can anyone find any decent insertions for this?
B2 U2 F2 D' F2 U L2 U B2 U R' D2 B R' D2 R B U' B' U'


To 3c: U F R2 F’ L’ F R2 F’ R L’ D R' B2 L' D L D' B L2 B2 U B U'
I had 16 to 4c, but I could only find insertions that could cancel one move, so I did that and now I'm left with 3c...

 

[irontwig]

Optimal for your L3C skeleton is 29:

U F R2 F' L' [@1] F R2 F' R L' D R' B2 L' D L D' B L2 B2 U B U'
Insert at @1: L' B2 L F' L' B2 L F
Fewest moves: 29. 2 moves cancelled
The final solution: U F R2 F' L2 B2 L F' L' B2 L F2 R2 F' R L' D R' B2 L' D L D' B L2 B2 U B U'

However the cruel truth is that, if you had done a different cycle at the same place you'd get a 26:

U [@1] L2 R D R' B2 L' D L D' B L2 B2 U B U'
Insert at @1: F L' B L F' L' B' L
After the 1st insertion: U F L' B L F' L' B' [@2] L' R D R' B2 L' D L D' B L2 B2 U B U'
Insert at @2: B L B' R' B L' B' R
Fewest moves: 26. 6 moves cancelled
The final solution: U F L' B L F' B' R' B L' B' R2 L' D R' B2 L' D L D' B L2 B2 U B U'

 

[irontwig]

From time to time the insertion finder uses a special kind of edge commutators I do not understand.
Example:
L F R U' R' F' L' B' U B

One thing I noticed is that you can swap moves, so the commutator above can be written like this:
F (R U' R') F' L' (B' U B) L

This way the structure is much clearer, but I still have no idea how and why they work.
Anyone?

God damn, why do edges have to be so complicated? Speaking of IF, is there a way to recognize 10 move 3C3E cases?

 

[Hssandwich]

Optimal for your L3C skeleton is 29:

U F R2 F' L' [@1] F R2 F' R L' D R' B2 L' D L D' B L2 B2 U B U'
Insert at @1: L' B2 L F' L' B2 L F
Fewest moves: 29. 2 moves cancelled
The final solution: U F R2 F' L2 B2 L F' L' B2 L F2 R2 F' R L' D R' B2 L' D L D' B L2 B2 U B U'

However the cruel truth is that, if you had done a different cycle at the same place you'd get a 26:

U [@1] L2 R D R' B2 L' D L D' B L2 B2 U B U'
Insert at @1: F L' B L F' L' B' L
After the 1st insertion: U F L' B L F' L' B' [@2] L' R D R' B2 L' D L D' B L2 B2 U B U'
Insert at @2: B L B' R' B L' B' R
Fewest moves: 26. 6 moves cancelled
The final solution: U F L' B L F' B' R' B L' B' R2 L' D R' B2 L' D L D' B L2 B2 U B U'

Ahh thanks, IF couldn't come up with anything.

 

[porkynator]

I have two differet nice solutions for this week's weekly scramble.

Scramble: U L2 F2 B R2 L B2 U' R2 B' U2 F' B R F2 D2 L R' B' U2

Spoiler

"Standard" solution with nice ending (24 HTM)

Spoiler

(B2 U') //Square (2/2)
B2 //Another square (1/3)
U' F' U2 R' //XXcross (4/7)
F L' D2 L F' D //All but 4c4e (6/13)
(R F R U2 R) D2 (R' U2 R' F' R') //Conjugate and solve (11/24)

Corners first/domino solution (24 HTM)

Spoiler

B' * U' L F' //Orient corners (4/4)
* = B2 D2 B2 D2 B2 D2 //Domino reduction (5/9)
U2 R2 D' F2 L2 U L2 F2
B2 U' B2 U B2 U B2

 

[Cale S]

27 for Weekly FMC with inserted T perm:

Spoiler

Scramble: D F B U2 R L' U' B2 L' D' B' L2 F2 R2 U' F L' D2 F2 B'

B // square
(B U') // roux block
(B' R B L2) // 2x2x3
U F' U2 R U // EO
F2 (L') L' // cool thing to F2L - 1
R' F R' F' R2 // 2c2e

B U F' U2 R U F2 L' R' F R' F' R2 L' B' R' B U @ B'
@ = U' B2 D L2 D' B2 R2 D' F2 D R2

Final solution: B U F' U2 R U F2 L' R' F R' F' R2 L' B' R' B' D L2 D' B2 R2 D' F2 D R2 B' (27)

and the 25 I submitted:

Spoiler

Scramble: D F B U2 R L' U' B2 L' D' B' L2 F2 R2 U' F L' D2 F2 B'

B // square
(B U') // roux block
(L2) F' L' U L // 2x2x3
R' D' F D F // pseudo F2L - 1
R2 F2 L' F R F' L // L3E

skeleton: B F' @ L' U L R' D' F D F R2 F2 L' F R F' L' U B'
@ = [F R' F', M]

Final solution: B R' F' L' R U R U' R' U R' L D' F D F R2 F2 L' F R F' L' U B' (25)




22, 28, 28, 27, 26, 23, 24, 27, 24, 23, 23, 26, 26, 26, 26, 28, 28, 24, 25, 25, 29, 24, 24, 25, 27, 26, 28, 23, 25, 24, 26, 24, 26, 25, 23, 25

currently at 25.10 avg12, hopefully I can roll the 27 next week

 

[irontwig]

I have two differet nice solutions for this week's weekly scramble.

Scramble: U L2 F2 B R2 L B2 U' R2 B' U2 F' B R F2 D2 L R' B' U2

Spoiler

"Standard" solution with nice ending (24 HTM)

Spoiler

(B2 U') //Square (2/2)
B2 //Another square (1/3)
U' F' U2 R' //XXcross (4/7)
F L' D2 L F' D //All but 4c4e (6/13)
(R F R U2 R) D2 (R' U2 R' F' R') //Conjugate and solve (11/24)

Corners first/domino solution (24 HTM)

Spoiler

B' * U' L F' //Orient corners (4/4)
* = B2 D2 B2 D2 B2 D2 //Domino reduction (5/9)
U2 R2 D' F2 L2 U L2 F2
B2 U' B2 U B2 U B2

Cool solutions, but didn't you orient something else too in your first step? Cool swap I just learned from IF:

Spoiler

B2 U2 F2 D2 F2 U2

.