Scramble: B L2 D2 F2 D2 B R2 D2 B R2 B2 U' R2 F' U' R D L2 R U' L
U' D' L B' D2 //2x2x2
Switch to inverse Premoves D2 B L' D U
U F' R U' R' //2x2x3
//U L2 U2 L U //F2L-1 - Also played with U L U2 L2 U - Problem was three edges were already solved on LL and it my understanding from the heise I have learned and played with that it is a difficult case to solve.
//It then dawned on my the advice given by Cubenovice. Perhaps a premove to misalign one of the F2L blocks at that stage would mean realigning that block would no longer give three solved edges,
hence:-
On inverse, premoves U' (D2 B L' D U)
U F' R U' R //2x2x3
U L2 U2 L U //F2L-1
--Indeed a nicer looking F2L-1 with a pair that could be preserved and even made into a 2x2x1 whilst permuting edges
L2 F' L F L U . L // Leaves 4 corners, bah 4!
R' D' R U' R' D R U // Spotted a direct 8 mover at the end to leave 3 and when I stepped through I didnt find a cancellation
Insert at . = R D2 R' U R D2 R' U' // 1 cancellation
Final solution = U' D' L B' D2 U L' R D2 R' U R D2 R' U2 L' F' L' F L2 U' L' U2 L2 U' R U R' F U' R' D' R U' R' D R U = 38 HTM