cubernya
Premium Member
I would do a D after a z2 so 2 edges are lined up, then perform my usual R D R' D' R to swap 2 edges
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F' R' L2 F' D B' U' B' U L' U2 B' U2 L2 R' D' R B2 F2 U' D2 R2 L B' F
EDIT: lol D2 F2 R2 D' R2 B L2 B R' U R2 F' B2 U R D2 L F' R' B U' L2 F U F
First :
x2 y' L' D2 L2 R F U2 F' U2 R // XXcross + pair setup (9)
d' R U R' // F2L 3 (4, 13)
F L' U' L U r U' r' // F2L 4 (8, 21)
U r' U2 R2 B' R' B R2' U2 r U' // ZBLL (11, 32)
Second : I don't see anything special.
Oo, interesting start, I didn't see that.
Second: y' z'
D' L D2
d' R U R'
y R U R'
R' U R L U L'
y R U R' U R U' R' (use sledgehammer results in Chameleon + N-perm)
U2 R' F R U R' U' F' U R
A perm U'
you can easily avoid diag PLLs with that particular OLL, just mirror your normal alg from RFU to RBU or do y2 LFU
r' U' R U r' B' R' B
or
y2 l' U' L U l' F' L' F
or (my personal favorite)
y' x' R U R' D R U' R' D'
All have exactly the same effect.
technically those are COLLs (which do however fall under OLLCP.)
OLLCP usually refers to OLLs that don't have all edges oriented, like COLL.
that last alg is a basic 8 move pure commutator. I can do it consistently in about .4x
U D2 F2 R' B2 L2 R2 D U2 F2 D2 B' R B F2 L2 R D2 L' U2 B2 D2 B F R2
First post in this thread
B' U R2 D2 L2 F B L' D2 U F' B L R2 F R' F2 R F B2 D L2 U2 R' U'