Thank you for the reply. I thought I understood your instructions, but then I tried it, and it did not work. Even so, if it did work, I wouldn't be able to tell why it does work just from your instructions. Maybe if I had the solution I am looking for, I could figure it out by working backwrds. anyway, using what you said, this is what I did:
(stuff done on inverse scramble)(scramble)(stuff done on regular scramble) as instructed
(D' B' U B U' D F2 U F U2 F' U2 R2 U' F' R2 F R2 F' R F R U R' D' R U' R' D)S(F2 L2 F B D')
Add premoves as instructed
(D' B' U B U' D F2 U F U2 F' U2 R2 U' F' R2 F R2 F' R F R U R' D' R U' R' D)S(F2 L2 F B D')(U' F')
Move inverse side to far right
(F2 L2 F B D')(U' F')(D' B' U B U' D F2 U F U2 F' U2 R2 U' F' R2 F R2 F' R F R U R' D' R U' R' D)
Refer back to my original outline of what I did if you're as confused as I am, all of my moves are there.
Here's how i do it, if it helps. At the end of this post is your solution in this notation.
Basically, I still imagine some moves to be on the "left side" of the scramble, and some on the right.
To differenciate, I put the moves on the left side / inverse scramble in brackets.
Let's ignore premoves for now, because they are only confusing. ^^
So if my 2x2x3 start works like this: (This is how I would post it in this thread, for example)
normal: R U R2
switch to inverse: B' L2 B'
switch to normal: D F D F
switch to inverse: R2
, I would actually write it down on my sheet like this:
R U R2 (B' L2 B') D F D F (R2)
The moves in brackets are the *inverted* premoves, so they are the moves I actually do on the inverse.
Note how this notation represents exactly the order in which you found the moves!
Now, if this is your current solution start, and, say, you now want to continue on the normal scramble, your premoves are the *inverted* moves in brackets, starting from the left.
So in this case your premoves would be
R2 B L2 B
Then the normal scramble has to be performed. Then you perform the "normal" moves, without inverting them, in the order you wrote them down:
R U R2 D F D F.
If, instead, you want to continue on the inverse scramble, you have to use the inverse of what I just described. So you start with the *inverted* non-bracketed moves from the right:
F' D' F' D' R2 U' R'
Then you perform the inverse scramble. Then then the moves in brackets, not inverted, and starting from the left:
B' L2 B' R2
This might seem complicated at first. But the nice thing is it is very easy to write down. To add some moves on the normal, just write them at the right hand end without brackets. To add moves on the inverse, write them to the right hand end, too, but in brackets. No need to start in the middle of your sheet, or something like that.
Always remember that the moves in brackets are the inverted premoves for the normal scramble, and the moves without brackets are the inverted premoves for the inverse scramble.
It is also worth noting that, if you want to make your start more readible, you can rearrange the parts of the solution a bit, by grouping the normal and inverse moves - as long as the normal scramble moves stay in their order, and the inverse scramble moves stay in their order. So to rearrange the above 11 moves you could write
R U R2 D F D F (B' L2 B' R2)
which is equivalent.
Now, the next thing you can use are premoves (for pseudo-blocks). The easiest thing to do is switching and treating the premove as moves like all the other moves. (With a bit of experience, this won't be necessary.)
But don't get confused by the order of premoves and moves on the inverted scamble. In my above example, the "last" move to create a 2x2x3 is a bracketed (R2). So after the first ten moves there will remain a pseudo-2x2x3 on the normal scramble, and a 2x2x3 with a missing move on the inverse scramble. The easiest thing to do is to apply that missing move on the inverse scramble (adding another switch, basically).
Now, when your skeleton is finally ready (which is when you should write down all the normal and inverse moves as just moves on the normal), what you have to write down are
- first, the moves on the normal, in the order you wrote them down
- second, *the moves you would normally apply as premoves before the scramble*, so the moves in brackets starting from the right (inverted).
So if we imagine that our little example above creates a L3C-skeleton already, this skeleton would look like:
R U R2 D F D F | R2 B L2 B
I hope this helps. It takes a bit of practise, but once you get used to it, I think this is the easiest way to keep track of your solution.
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Here is your above solution in my (actually, porkinator's) notation:
Scramble: D' B2 D L2 D2 B2 U' F2 L2 U L2 R F' U R2 B' F D' R D L2
Your solution: F2 L2 F B D' (D B U' B' U D' F2) F' (U' F' U2 F U2 R2 U) U' (F R2 F' R2 F R' F') (R' U' R D R' U R D')
Solution written down correctly: F2 L2 F B D' F' U' | D R' U' R D' R' U R F R F' R2 F R2 F' U' R2 U2 F' U2 F U F2 D U' B U B' D'
(As you can see your premoves were inverted.)
Again, my advise would be to just do another switch to perform a premove.
