Official Blindfold Algorithm List

[malcolm]

U2M2U2M2 is faster, less moves. Its actually the same as yours, but you had the M2 at the end as M' twice at the beginning and start.

 

[Suraimu]

[R U' R' U]x3 [R' U R U']x3 2 Pair

 

[masterofthebass]

It's a lot easier to do R2 H-perm U2 R2.

 

[Suraimu]

Yes. I know use H-Perm But this Alg is very slow and trouble.
I don't think my alg is difficult.

 

[philkt731]

Yes. I know use H-Perm But this Alg is very slow and trouble.
I don't think my alg is difficult.

H perm slow and troublesome????? no way...

(R' F R F')x3 (F' R F R') x3

Also, What is the alg for switching UFL-DFL and UFR-DFR?

 

[Lucas Garron]

At least do something like a commutator (I thought of F2DaBDa'F2DaB'Da').

But really, I'd do r2 U' M2' U2' M2' U' M2' U2' R2...

 

[Erik]

I found:
M2 E M2 E' (RLFB)*3

 

[AvGalen]

It's a lot easier to do R2 H-perm U2 R2.

So that would become:
U2 R U2 R2 U2 R2 U2 R U2 R2 U2 R2

 

[dlzcy]

I like [R U' R' U]x3 [R' U R U']x3 2 Pair

 

[Kenneth]

Possibly already in use but a nice double 2-cycle:

M U M U' M' U M' U'

Binary: 00 01 10 11

M--> XX <--U

0 = clockwise
1 = counter clockwise.

Do leftmost bit first

 

[Stefan]

Flip all U and D edges:
(Rry)6

From:
http://www.math.rwth-aachen.de/~Mar...ey__Language_in_Rubik's_Cubic_Compendium.html

 

[KConny]

Stefan: I wanted to post (RrBb)*3 a couple of days ago, but found that (DwDRwR)*3 is already in the first post.They are all really the same alg, right?

 

[fanwuq]

my algs:
CP: lars v's A perms and their reflections.
EP: Erik's M trigger U, Z, and H perms.
CO: 1/sune from left hand, sune from right hand.
2/inverse of that
3/triple sune, H perm, U2
4/sune,U, U perm,U
5/ other COLL-PLL combos.
EO: macky's BLD EO

 

[fanwuq]

For CO, I do color neutral and it always turns out to be COLL cases on opposite layers and setup with xyz turns. Macky apparently did not like this idea, but I don't see why it won't work.
">I do CO color neutral.

You mean replacing U/D with, for example, F/B? So you would change the
restriction on the set-up moves when solving the permutation?

>There is always a face-pair that you can do COLL without any setup.

Is this easy to prove?

-macky"

Perhaps he didn't understand my confusing explanation. Don't change set up restrictions, simply do xyz as set up for CO only.

 

[Lucas Garron]

>There is always a face-pair that you can do COLL without any setup.

Is this easy to prove?

-macky"

Perhaps he didn't understand my confusing explanation. Don't change set up restrictions, simply do xyz as set up for CO only.

It's not easy to prove. In fact, it's impossible.
That's because there's an easy disproof.

U R U2 R U R2 U2 L' D' R F'

EDIT:
Wow, I was silly. There's a REALLY easy disproof: U L2 U' B R2 B' U L2 U' B R2 B'

 

[fanwuq]

ok, but in cases that it happen, i'm allowed to do that right?

 

[fanwuq]

wow, that scramble is so weird! I don't think that kind of situation is very common. I suppose I can memorize more algorithms for weird cases. So it's not always, but most of the time?

 

[Lucas Garron]

wow, that scramble is so weird! I don't think that kind of situation is very common. I suppose I can memorize more algorithms for weird cases. So it's not always, but most of the time?

19/27 of the time. (70.37%)

Now I wanna see a simple explanation for that (i.e. why we can treat CO on the axes as independent).
Hey, does this apply to center permutation orientation definition schemes? Hmm...

 

[fanwuq]

I realized that
U R U2 R U R2 U2 L' D' R F'
isn't too bad, You can do opposite side sunes and do headlights on another face. Now is there a case where you have to applied 4 algorithms to solve CO?

 

[Blue Transaparent]

Is this useful?

Corner Orientation (1 2 4)
(L2 D' L U2 L' D L U2 y' L' B L F L' B' L)

and mirror alg on opposite side.