after spamming many ways to do f2l-1+eo i found this after your start: L B' U B L2 U2 F' L F L2 U2 B' U2 which leaves 3 corners. which is OK depending on cancellations. Turns out this doesn't cancel much either I could only cancel 1 move though IF says you can cancel 2 to get a 25 move solution.
congrats on your solve!
I found an interesting continuation for your R' F' R F xxx-cross thing, which gives L4C in 18 moves, resulting in a total of 26 moves, using the optimal insertions
L' B R B2 R D' // your 2x2x3
L' B' L B // your xxx-cross B' U B L U L' U L U' L' // AB4C
I got exactly the same solution as yours (25-move).
This was the best I could do in 1-hour.
Another attempt after 1-hour:
(Inverse)
Pre-scramble: L' F
1st square: U L' D2
2nd square: R' U B
3rd square: L'
F2L minus 1 slot: U2 L' B *
All but 5 corners: D2 L' D2 L
Correction: L' F
Corner 3-cycle: F' D F U F' D' F U'
Insert at *: L U L' D2 L U' L' D2
24 moves in total.
Yet another attempt:
(Normal)
Pre-scramble: L
2x2x1 block: F' U2
2x2x2 block: B2 * R F2
More square: L2 [@1] B'
More square: U2 L' B2
All but 4 corners: R' U' R
Correction: L
Insert at the beginning: D F' U' F D' F' U F
Insert at *: F L2 F' R F L2 F' R'
which also results in 24 moves. But IF says the optimal insertion is:
Insert at @1: L B' D R2 D' B L' B' D R2 D' B = [L, B' D R2 D' B]
I wasn't sure whether I should post this here or in the BLD section, but I wanted to know if anyone has ever done a FMC BLD solve. In other words, you come up with a solution in the fewest moves that you can without doing any turns on the cube.
R' B2 F R2 F' // premoves (2x2x2)
U' L B L' U' L B U' R L2 F2 D' R2 U' F2 B2 R2 F2 D // scramble
F' U' L D' L' U // 2x2x3
L' F' L // EO & 2 pairs
end:
F D' F' D' F2 D F' // leaves 2 twist (IF gives 28)
or
F D2 F2 U F' D F U' F' // leaves 2e2c (insert?)
or
F D2 F D2 F D' F D F2 D2 F2 D F D' F D F // SuneLL (32 moves lol)
Trial & error with the help of NISS (and my experience, which is quite hard to explain).
For example, on FMC 465/classic (your URL points not 464, but 465), U makes two c/e
pairs on the normal scramble, which gave me a big hint of the premoves used in the
submitted solution.