B2 R2 D2 R D' U' L R' D2 R2 B [@1] R' F2 L F' L' R U' R' U2 F U' F' U F2
Insert at @1: B' L B R B' L' B R'
Fewest moves: 30. 3 moves cancelled
The final solution: B2 R2 D2 R D' U' L R' D2 R2 L B R B' L' B R2 F2 L F' L' R U' R' U2 F U' F' U F2
Hm, might do this later. Unfortunately I closed the window before thinking about it, so I have to write it all again. Has anyone tried to ask Per personally about this yet?
Scramble: F' B' L' R U2 F' D2 F2 U' D L' D2 U B' U D L D R' F2 B U2 F2 R' U2 F' D R' B' D'
invers: D B R D' F U2 R F2 U2 B' F2 R D' L' D' U' B U' D2 L D' U F2 D2 F U2 R' L B F
invers :
2x2x3 Block : B' F U' L' R' [1] F' R2 F' D' F2 //(10/10)
All but 3 corners : U' B R' U R B2 U //(7/17)
Insert at [1]: R F' L F R' [2] F' L' F
Insert at [2]: R' B R F' R' B' R F
final solution: U' B2 R' U' R B' U F2 D F L R B R F R' B' R2 F' L' F L U F' B //(25 HTM)
Hm, might do this later. Unfortunately I closed the window before thinking about it, so I have to write it all again. Has anyone tried to ask Per personally about this yet?
I'm quite proud of the solution I found today in a 1-hr time limit FMC, so I wanted to share it. It's not my best result if you consider only the number of moves (29, and yesterday I got a 26) but it's nice, in my opinion, since I did some "non-standard" blockbuilding and two insertions (one of which isn't a 3-cycle).
Scramble: R2 U2 F' R2 D2 U2 B2 D2 R2 U2 B' L D' L' F R' U' L2 D' F2 L'
Solution: R2 D L' D' R D L B' R' B2 R2 D' R' D2 B' D' U R2 U' D F' R' B' R U D' F U L (29 HTM)
On inverse scramble (L F2 D L2 U R F' L D L' B U2 R2 D2 B2 U2 D2 R2 F U2 R2)
L' U' F' D U' F //2x2x2 (6/6)
F' R' B R F //2x2x1, 2 moves cancel out (3/9)
D' U R2 U' //Another 2x2x1 (4/13)
* B2 R' B R B + D' R //All but 2 edges (flipped) and 3 corners (cycle) (7/20)
* = D B D2 R D R2 B R B2 //Orient 2 edges, 5 moves cancel out (4/24)
+ = L' D' R' D L D' R D //Corners 3-cycle, 3 moves cancel out (5/29)
Final Solution (to be inverted): L' U' F' D U' R' B R FD' U R2 U' D B D2 R D R2 B2 R B L' D' R' D L D' R2 (29 HTM)
Also, IF says 31 is optimal for that skeleton (after selecting "corners 3-cycle", "edges 3-cycle", "edge flip" and "other").
1st scramble: B2 R F2 B' L2 D2 B' R' D2 F' U F2 B2 L' B2 R2 L U2
1st solution: R' D' F R' F' L F R F' L B' L' F2 R D R D' R2 D' R D2 R2 B R2 B' R F B2 (28 moves)
30 min backup solution.
Pre-scramble: B R2 B' (EO) R F B2 (pseudoness correction)
Two squares: R' D' *
2x2x3 block: L2 B' L' F2
More square: R D R D'
All but 3 corners: R2 D' R D2 R2
Correction: B R2 B' R F B2
Insert at *: F R' F' L F R F' L'
I believe this scramble has potential for Sub 27, but I couldn't find any better solution in the remaining time.
2nd scramble: U2 L2 U2 F L2 F' U2 F' L2 U2 F2 L D' B' D' B U' F L B
2nd solution: L' B D L2 R B U' L2 F' L R U2 R' F' R U R' F2 U F L F' R F' L' F R' F' U2 (29 moves)
30 min backup solution.
2x2x2 block: L' B D L2 R B
2x2x3 block: U' L2 F' L
More square: R U2 R' F'
More c/e pair: R U R'
All but 3 corners: F2 U F L F2 * L' U2
Insert at *: F R F' L' F R' F' L
3rd scramble: D' R2 U F' R2 D2 B' R2 L' F R F2 L' U2 R2 B2 L B2 U2
3rd solution: U2 R' U2 D2 L' U' L U2 D2 R' U2 F2 U' F' U F2 L F' L' F R U R' L2 F L U2 R D' B2 (30 moves)
NISS solve.
(Inverse)
Pre-scramble: U' R2 U2
2x2x2 block: B2 D R'
2x2x3 block: U2 L' F' L2
F2L minus 1 slot: R U' R'
(Normal)
Pre-scramble: R U R' L2 F L U2 R D' B2
F2L minus 1 slot: U2 R2 * U
More 2 c/e pairs: F2 U' F' U [@1]
All but 3 edges: F2 L F' L' F
Correction: R U R' L2 F L U2 R D' B2
I don't have enough time to find an insertion, so I quickly did:
Insert at *: R U2 D2 L' U' L U2 D2 R' U (= R E2 R' U' R E2 R' U)
One of the optimal insertion is:
Insert at @1: U2 Fw2 U2 L' U2 Fw2 U2 L'
which results in 29 moves.
1st scramble seems to be a great scramble, and actually Yuki Tanaka got 25 moves for that.
The best solve for the 2nd scramble was 26 moves by Hideki Niina, and the best solve for
the 3rd scramble was 27 moves by Wataru Hashimura.
... so I couldn't stand on the podium, my god :fp
But I'm still proud of my results as mean of 3: 28, 29, 30 = 29, ranked in the second in the world.
First is (of course) Sébastien Auroux: 25, 23, 30 = 26.00, and third is Hideki Niina: 28, 26, 35 = 29.67.
I also improved my average of 12: 27, 29, 30, 31, 28, 27, 29, 31, (DNF), 28, (25), 28 = 28.8
Hello, I'm Yuki Tanaka, a Japanese cuber.
My solution of Cube Camp Kanazawa 1st scramble.
scramble : B2 R F2 B' L2 D2 B' R' D2 F' U F2 B2 L' B2 R2 L U2
solution : B R' D' F' B L B L B2 D B' D' L D L2 F' R' F L F' R F2 L F' D (25 moves)
2x2x2 : B R' D' F'
2x2x3 : B L B2
psuedo-F2L#3 : B' L B2 D B'
making a corner edge pair and part of EP : D' L D
making 1x2x2 on L surface : L' * F L F'
premove : D
insert at * : L' F' R' F L F' R F (2 moves cansel)
Many others did in the same way to make 2x2x3 block though, all went well after that in my solution.
It was very lucky and much improved my PB. (including my unofficial best : 28 )
2nd and 3rd was poor and my mean is 25 33 33 = 30.33, (oh, not sub30...)
But both best and mean is too good for me. I'd practice more to make sub30 again.
Quite interesting case where 10-move commutator beats 8-move commutator.
From the 1st scramble of Cube Camp in Kanazawa 2013.
Scramble: B2 R F2 B' L2 D2 B' R' D2 F' U F2 B2 L' B2 R2 L U2
Skeleton: U D' F' D2 U' R2 U L2 U' L F [@1] L U L2 U' L2 F' L F U L' U' R (premove R)
Hideki Niina got 28 moves by inserting an 8-move commutator, but IF gives
Insert at @1: F' L U' L' U F U' L U L' = [F', L U' L' U]
which results in 27 moves.
And his nice 26-move solution for the 2nd scramble:
Scramble: U2 L2 U2 F L2 F' U2 F' L2 U2 F2 L D' B' D' B U' F L B
Solution: L B L' U R U' L2 U2 R B' U R' B F U2 F' U B F' U B2 U' F U B U (26 moves)
Cross with some preparation: L B L' U R U' L2
More slot: U2
Store the slot: R B' U R' B
XX-cross: F U2 F'
F2L minus 1 slot: U B * U B'
All but 3 corners: U
I found a nice solution for fmc.mustcube.net round #466 (contest still running) in 90 minutes (so no time limit):
Scramble: B2 U2 R' U L' F' B2 L2 F2 L' R D2 B2 F L2 U2 L R2 U F2 R2 L F2 L2 R F2 B L' B2 U'
Right after submitting my 29 HTM 1-hour solution, I found out that the last 10 moves were a 3-cycle of edges (stupid me). I found this incredible insertion in 30 more minutes:
R2 D2 B2 F2 L * F B' //EO + blocks (7/7)
+ U' F2 L F2 B2 D' //All but 3 edges and 3 corners (6/13)
* = R B' R' F R B R' F' //3 corners (6/19)
+ = L2 B2 R2 D B2 L2 F2 U //3 edges, 5 moves cancel out (3/22)
this would be optimal:
D F R U2 R2 U' [@1] R' U R2 D B' R' D R' D2 F' R F R'
Insert at @1: U F' D' F U' F' D F
-> 25 Moves
search a commutator in the solution, which solves the three corners
edit:
there is already a commutator at the and of the solution possible which cancels one move:
D F R U2 R2 U' R' U R2 D B' R' D R' D2 F' R F R'
R' F L' F' R F L F' -> 26 Moves
Hey, with Heise-style solving, when you finish the cube and are left with 2 unsolved c/e pairs, what would you do? Only thing that comes in my mind now is to insert a PLL somewhere .. Thanks
Hey, with Heise-style solving, when you finish the cube and are left with 2 unsolved c/e pairs, what would you do? Only thing that comes in my mind now is to insert a PLL somewhere .. Thanks
Hey, with Heise-style solving, when you finish the cube and are left with 2 unsolved c/e pairs, what would you do? Only thing that comes in my mind now is to insert a PLL somewhere .. Thanks
Atm I'm not good at insertions and commutators due to this I seldom do FMC but I love FMC and I'm kinda noobish at FMC 
