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[Help Thread] FMC Discussion

The feature for setups was just easily added by extending the algorithms. The IF finds one or more optimal insertions at a time. But it gives the first one found. Now I'm going to fix the problem. I want to print out all optimal results order by the moves of insertions. Do you have any other ideas?

Yes, that would fix it I guess. I have no other ideas currently. :)
 
Can anyone explain me, why the IF can't find the optimal solution for this skeleton?
http://www.speedcubers.de/showthread.php?tid=4572&pid=175659#pid175659

Laura found this in the German forum competition some weeks ago and I can't explain it to myself. Maybe it is because there is a 9 move cancellation?

Yeah, you are right. The IF consumes that after any insertion the moves should be more than before.

And, I have a question. Since Laura found a insertion with 9 moves cancellation, why didn't he do the L4C like U2 B2 R' D' U R' D R2 U' R'? I think that skeleton can be easy found.
 
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My winning solution from Tachikawa 3x3 Fest 2013.

Scramble: D2 R2 U2 R' D2 B2 D2 L2 U' B2 R2 F' D2 U L F' L2 U' L2
Solution: D2 F U D F2 U R' U2 L2 F2 L U2 F2 R U' R' L' U L2 U L' U L U2 R2 (25 moves)
30 min backup solution.

Pre-scramble: L R2

Orient edges: D2 F
2x2x2 block: U D F2 U R'
2x2x3 block: U2 L2 F2 L
F2L minus 1 slot: U2 F2 R U' R'
Finish F2L: L' U L
LL: L U L' U L U2 L'
Correction: L R2

Relatively easy scramble, but I couldn't find any better solution in the remaining time.
 
fmc.mustcube.net round 463, no time limit.
Scramble: L' B U D L' R' D2 B L2 R' F2 U' F2 L2 F2 L' R U D2 L D2 L R' U D R' F2 D' B2 F'
Method: Columns (lol) with insertions
D2 F2 L U' L2 B' U B + //Pairs
U L' R * D' U F B' //Centres
* = R2 D2 R2 D2 R2 D2 //Some Edges
+ = B U' F' ° U B' U' F U //Corners
° = F D' F' D U' R D R' D' U //Edges
Final Solution: D2 F2 L U' L2 B' U B2 U' D' F' D U' R D R' D' U2 B' U' F U2 L' R' D2 R2 D2 R2 D U F B' (32 HTM, 30 STM and 26 ATM if I counted correctly)
It was fun to play with this method, but looking for 3 insertions is a pain.
 
Since Laura found a insertion with 9 moves cancellation, why didn't he do the L4C like U2 B2 R' D' U R' D R2 U' R'? I think that skeleton can be easy found.

Laura is a "she". ;)

That's the cool thing about insertions. You don't have to see things like that for making your skeleton, because if you're able to find the according insertion you will end up with this anyway.
 
N8W8 2013 FMC podium

1 Robert - 31 HTM
1 Sebastien - 31 HTM
1 Cubenovice - 31 HTM

Scramble: L2 D2 L2 B D2 F' D2 U2 F' D2 F' L U L2 F' U' B D' U2

My (too) simple solution:

On inverse:
U2 F L D2 B' U - 222 plus pair - 6
D2 F L' F2 L - XXcross plus pair - 11
R' F R - F2L-1 with edges oriented - 14
F' D' F2 D F2 D' F2 D - leaves 2C2E (Y-perm) - 22

Here I noted the inverse as solution up to 2C2E to check my solution so far.
D' F2 D F2 . D' F2 D F R' F' R L' F2 L F' D2 U' B D2 L' F' U2
And :) now the 2C2E are already in a 10 move LL alg configuration: F' R F' U2 B L' B' U2 F2 R'
And since none of these pieces are in the U-layer I perform this alg before the final U2 so it cancels the first move.

Final solution:
D' F2 D F2 D' F2 D F R' F' R L' F2 L F' D2 U' B D2 L' F2 R F' U2 B L' B' U2 F2 R' U2 = 31 HTM


Alternative:
at . insert F2 L' F L F2 R' L' F L F' R - two move cancel but since the insertion is 11 moves the net total is the same.
 
This is my solution. I'll just give the skeleton to 3 corners.

R' B D' F' U' F' - 2x2x2 block
B' L U' L' - simple expansion to 2x2x3
L' U R' U' L - expand to pseudo F2L-1
R U' R U2 F' U' F - complete pseudo F2L and EO
R' U2 - permute edges on right, then correct the top layer, leaving 3 corners

This totals to 23 moves to 3 corners.

I fail at insertions :fp
 
Can anyone find a good continuation?

Scramble: D' U' B2 U' L2 D2 U' R2 U' L2 U' F D F2 L F' L' D' R' F' R2
On normal:
L' U L U B
Switch to inverse with premoves B' U' L' U' L:
B' L' D F' R' D' (F2L-1 in 11 HTM)

The best I could find was a 34 HTM solution without insertions or a 17 HTM skeleton leaving 2 edges flipped, 2 other edges swapped, 2 corners swapped and 1 other corner twisted (sounds awful, but can be solved with 2 inserted algs).
 
U F R F' R' U' R2 U' B' R B U R2 leaves 2 twisted corners --> 30

U R F R' F' U' R' F R F' U' R' U R2 leaves 3 corners --> 32

still not very satisfying...
 
N8W8 2013 FMC
Scramble: L2 D2 L2 B D2 F' D2 U2 F' D2 F' L U L2 F' U' B D' U2
This is what I found:
2x2x2: U F L2 F2 D (5)
But, insert 2 moves to make it a 2x2x3: U R2 D' F L2 F2 D (7) Note that the R2 places the extra edge and the D' sets up the YB edge (and luckily the YBR corner) to where they will need to be
Some EO + pair: B' U' B (10)
Square + pair : L U L2 (13)
Place them, leaving 4 corners: F U F' (16)
I couldn't be bothered to insert, but IF tells me 26 is optimal
Incidentally, 26 moves would have made UK NR a 4-way tie (3 for me, 1 for Rob)
 
Hey guys! I know I'm a little late for this, but here are my solutions from worlds. Critique is welcome. I know insertions and premoves, but I haven't gotten around to figuring out NISS. Solve 1 was my first time using a premove. XD


Solve 1: 34

Scramble: U2 R' U F' L2 F' B' U' R U' F' R2 F2 D2 R2 F2 D' B2 D2

R' F R' D R F' D' - 2x2x2 (7/7)
B' L U' L' U' - 2x2x3 (5/12)
D L' D' - Pseudo F2L minus a corner (3/15)
(premove L')
R D' R' D * B D B' D' - To 4 corners (8/23)

* = U ** B D B' U' B D' B' - To 3 corners (2/25)
** = B U' F2 U B' U' F2 U - Last 3 corners (8/33)
L' - Undo premove (1/34)

Solution without cancellations:

R' F R' D R F' D' B' L U' L' U' D L' D' R D' R' D (U (B U' F2 U B' U' F2 U) B D B' U' B D' B') B D B' D' L'

Final solution:
R' F R' D R F' D' B' L U' L' U' D L' D' R D' R' D U B U' F2 U B' U' F2 U B D B' U' D' L'

NOTES: I got pretty lucky with the F2L, but I am proud of myself for inserting correctly even though I couldn't find any cancellations for the second one.


Solve 2: 31

Scramble: D' L2 R2 F2 D R2 D2 R D B2 F U' L B R F2 R2 D' U

F2 U2 B D' R - 2x2x2 (5/5)
L U B2 U' - Pseudo 2x2x3 (4/9)
(Premove B)
B D B' L D2 L D2 B D' B' - Pseudo F2L (10/19)
(Premove L2)
B' D F' D2 B D' B' D2 B F D2 - L perm LL (10/29 not counting cancelled move)
L2 B - Undo premoves (2/31)

Final solution: F2 U2 B D' R L U B2 U' B D B' L D2 L D2 B D' B2 D F' D2 B D' B' D2 B F D2 L2 B

NOTES: I'm not sure if this is a lol solution. On one hand, I used two premoves and had some nice blockbuilding at the beginning, but on the other, the end of F2L was very lucky and I got an OLL skip that cancelled into one of the shortest PLLs.


Any advice is welcome.
 
Better L perms for FMC:

F2 L' U' L F2 R' D R' D' R2
R2 D R D' R F2 L' U L F2

That's all I've really got though. My FMC had the exact same pseudo 2x2x3 solution as you and ended with easy F2L into 1LLL (With the same 2 premoves as well :p).
 
Got 29 on the current FMC Mustcube Scramble (quite hard one in my opinion) and forgot again to add the slashes. :D

Did the page get fixed meanwhile?
 
Hello FMC thread, I did FMC at this random scramble: D' F' R' U' L2 R' F' U B2 R' L F D2 U2 B R' F2 D B2 F D' L D' F2 R2
Here's my partial solution:
B2 R2 D2 R D' (1x2x2 5/5)
U' L R' D2 R2 B R' (back block 7/12)
F2 L F' L' R U' R' (EO 7/19)
U2 F U' F' U F2 (6/25)
I'm currently stuck at this Last 3 corners :(, what is your solution here? Thanks!
 
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Insertions? ;)

B2 R2 D2 R D' U' L R' D2 R2 B [@1] R' F2 L F' L' R U' R' U2 F U' F' U F2
Insert at @1: B' L B R B' L' B R'
Fewest moves: 30. 3 moves cancelled
The final solution: B2 R2 D2 R D' U' L R' D2 R2 L B R B' L' B R2 F2 L F' L' R U' R' U2 F U' F' U F2

I don't think so, unfortunately.
You should submit it again with backslashes.

Hm, might do this later. Unfortunately I closed the window before thinking about it, so I have to write it all again. Has anyone tried to ask Per personally about this yet?
 
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