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[Help Thread] FMC Discussion

[*]by Cielo: L' R2 B2 D2 B2 R' B L' D' U F' L' F2 D' R2 B' U2 R F2 U'*

My solution (within 1 hour): 28

F2L-1: U' R' F' L' F B' D U2 F U B' R' B R' U2
L3C: R B2 R' B2 U' B * U B' U' B U

Nice insertion saves the day:

* = B' D' B U B' D B U'

Solution: U' R' F' L' F B' D U2 F U B' R' B R' U2 R B2 R' B2 U' D' B U B' D U' B U
 
kinch: Once you've found insertion with the most moves cancelled, do you look for an insertion within that insertion?
No. That is the one thing that escapes my method. 2-passing by picking the best first cancellation of course is also fallible. The question of which one does not find optimal more times is up for debate imo.

Writing down ALL insertions that cancel moves? That sounds like lots of work and most of this work will be useless.

What I like about my approach is especially is, that huge cancelations are very difficult to miss. Finding the next insertion is easier then, as you have less pieces to track and it is less likely to miss the best second insertion.

I have never tried your approach though (well, at least not exactly as you do it). How much time does this take you?
I don't actually write down each insertion, for most I just note the point at which the insertion is, what it cycles (e.g. (451)) and how many it cancels. If I find a good one (3 or more) I would write the first 4 moves down as these ones are more likely to be used. Once I have finished checking, I will pick my pair of insertions and go and find the exact moves if it was one I did not write down during the pass.
For your method, you have to look at all 5 options after each move anyway, so you're still checking just as much during the first pass. I just don't have to go back through again afterwards looking for another insertion.
I really don't know how long it takes tbh, but I'm sure I'd be several minutes slower if I did 2-pass.
 
(About those whose FMC record < 3x3 time)
I shall remain anonymous until I get the opportunity to "officialise" my signature.
Should be next weekend :)
FYI there are some people with such official results. :o
EDIT: Oops, I investigated 333 average, not single. But Nico Kurmann is still such a person.
Anyway good luck on your next competition!
I found a spanish guy who is surprisingly good at FMC with not so excellent 3x3 time:
and from his result, I also found that FMC with multiple attempts were held many times in late years in Spain.
For example, 2012-2013(until May):
 
[*]Dutch Open 2009: R2 D B2 U B2 D B' D' R' U' F' D2 B2 R D L' B' F*

Eventually a scramble from this list that looks quite normally. :)

My solution (didn't really watch the time, but should have been within 1 hour, if you ignore that I competed in the competition in 2009):

1x2x2: U' L' U'
Another 1x2x2: F2 R B * R
2x2x3: F2 U2 B'
L4C: B D R D2 U F D F' U' # B' D

* = B' R F2 R' B R F2 R' (7 moves cancelling!)
# = R' F2 R B' R' F2 R B (2 moves cancelling)

Solution: U' L' U' F2 R2 F2 R' B R U2 D R D2 U F D F' U' R' F2 R B' R' F2 R D

26 moves (optimal for the skeleton)
 
I agree with that. Quickly finding insertions is my weakness. It cost me about 10 minutes to find a insertion. So I always made a skeleton with 3 corners left.

This reminds me of a question i've been trying to answer for myself. After EO+F2L-1, I can easily force edges to solve in few moves. However, whether i get 0 2 3 4 or 5 though is almost completely down to chance, at this stage, with so much restriction, how does one force as many corners to solve whilst solving the edges? I suck at insertions too so if I could give myself last 3 corners instead of other options this would help me out a lot.
 
I am willing to get into FMC. I have been following this thread for quite some time and it seems very interesting.

How should I start, any tutorial or such?

Sent from my A75 using Tapatalk 2

Bump

Wow, just wow. UWR, I assume? (17 moves)

Sorry but I cannot see the solution :confused:

Sent from my A75 using Tapatalk 2
 
Yeh, sure!
(we both know maths, do we?).
I will post my solution on monday
Wow, just wow. UWR, I assume? (17 moves)
I also think so. (See my post)
Finding an optimal 17-move solution within 20 min is beyond the pale of human conduct...
God descended to this world. :cool:
Sorry but I cannot see the solution :confused:
He posted his solution to the submission site: http://www.speedsolving.com/competitions/,
so you can see it if you have an account.

Guus, the solution and its explanation are definitely worth posting here or the competition page,
so that anyone can refer the awesome result. Amazing, fantastic, that is legendary for the fierceness. :D
 
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here it is, my solution for FMC of this forums weekly competition 2013-15:
scramble: D2 F2 U' L2 D B2 U' F2 L2 F2 U' L' D' L2 B' D' F D U' R U
my solve: B U F2 D' F L2 D L2 D L' R F R' D' F' R2 D (17)

my first moves: quick start: B U F' L F'
to fix pseudoblock at the right add premoves (R2 D)
continue obvious start: 2 blocks: B F' U (3+2)
I investigated this start for several minutes, parked it for later, and investigated an alternative start with these same promising pre-moves (R2 D):
2x2x2: B U (2+2)
save pair before creating next block: F2 (3+2)
block and extra pair: D' F L2 D (7+2)
another block and extra pair: L2 D L' (10+2)
finish F2L and LL-skip: R F R' D' F' (15+2)
undo pre-moves (R2 D) (17)
Very lucky solve, 20min!
PB and optimal solution!
 
Weekly Competition 16 Scramble
B2 F2 D' R2 U2 B2 L2 D2 B2 U F2 R' B' D L' D2 L F' D' U'
I found some other bad Insertions:
F‘ D U L
D2 F R2 F‘
R D2 R2 D‘ R2 D‘ B'

2 pure 3cornercycles in 15 Moves. Optimal are 2 move cancellation -.-
 
and another frustrating solution:

U2 R D2 F2 L' B2 L D2 F2 U2 R2 B L F' D F2 R D' L2 F2
F2 L2 D R‘ F2 D‘ F L‘ B‘ R2 U2 F2 D2 L‘ B2 L F2 D2 R‘ U2

Pre: F‘

R U‘ B2 R B2 U2 R‘ B‘ R‘ - 2x2x3 [9+1/10]
F2 R‘ B‘ D‘ B - F2L-1 [5/15]
U‘ R‘ U R F R‘ F‘ R - Finish [8/23]

R U‘ B2 R B2 U2 R‘ B‘ R‘ F2 R‘ B‘ . D‘ B U‘ R‘ U R F R‘ F‘ R F‘
. = U L‘ U‘ R2 U L U‘ R2 [8/31] optimal insertions -.- and single option to insert.

Solution:
R U‘ B2 R B2 U2 R‘ B‘ R‘ F2 R‘ B‘ U L‘ U‘ R2 U L U‘ R2 D‘ B U‘ R‘ U R F R‘ F‘ R F‘ - 31 Moves
 
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and another frustrating solution:

U2 R D2 F2 L' B2 L D2 F2 U2 R2 B L F' D F2 R D' L2 F2
F2 L2 D R‘ F2 D‘ F L‘ B‘ R2 U2 F2 D2 L‘ B2 L F2 D2 R‘ U2

Pre: F‘
R U‘ B2 R B2 U2 R‘ B‘ R‘ - 2x2x3 [9+1/10]
F2 R‘ B‘ D‘ B - F2L-1 [5/15]
U‘ R‘ U R F R‘ F‘ R - Finish [8/23]

R U‘ B2 R B2 U2 R‘ B‘ R‘ F2 R‘ B‘ . D‘ B U‘ R‘ U R F R‘ F‘ R F‘
. = U L‘ U‘ R2 U L U‘ R2 [8/31] optimal insertions -.- and single option to insert.

Solution:
R U‘ B2 R B2 U2 R‘ B‘ R‘ F2 R‘ B‘ U L‘ U‘ R2 U L U‘ R2 D‘ B U‘ R‘ U R F R‘ F‘ R F‘ - 31 Moves

Had more luck:

R' U L' U' B2 L B D F' D2 L D' R2 D L' U' R D2 R' U R D R2 D' R D F2 (27)

R' U L' U' B2 L B D F' D R2 D.R..D' R2 D' R D F2

.=D' R2 D L D' R2 D L'
..=R' U' R D2 R' U R D2
 
my relatively lucky solution on the second scramble at German Open 2013:

Scramble: R U2 L' U2 L2 B' L D' B D2 B2 R' L2 U2 L' F2 L2 B2 U2

Start on normal: F' U2 B2 L2 F L (6/6)
Switch: D R' D' (same stuff would've worked on the normal scramble too, but afterwards I just found crap to continue with) (3/9)
continuing on invers: F' U F2 (3/12)
End on normal: U2 F R' F' U' R U' R' U2 R U2 (11/23)

Basti told me shortly afterwards that it could've been a 21 if i had put in the last F2L pair with U R U R' U' F' U2 F U but I didn't know that case and was quite happy about the 23. So in the 10 minutes I had left I wrote down the solution and didn't look for anything else.

F' U2 B2 L2 F L U2 F R' F U R U' R' U2 R U2 F2 U' F D R D'
23 moves
 
Ok, can some one explain how I go about to cycle these three edges.. This framework is fmc.mustcube.net nr 447 what I got in 7 moves:

fmc447.jpg
 
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