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[Help Thread] FMC Discussion

I'm quite sure that this situation has occurred many times before, but I desperately need help...

I've finally decided to attempt FMC. After conducting some research, I've found that the general approach for a solution seems to be blockbuilding, and then finishing with corner commutators. I have little problems with the latter, as I have recently explored the BH method from BLD. However, I am encountering difficulties when blockbuilding in methods such as Petrus. I find that I would always blockbuild using inefficient CFOP techniques. Therefore, my question is: how can I decrease the average move counts of my blockbuilding? I suspect that the answer may simply be practice. But I would prefer a more specific answer. How exactly should I practise? I feel that simply practising without a specific goal is merely reinforcing my bad habits from CFOP.

Thanks.
 
Experience on about 300 insertions I did in the past 5 years.
But we could apply math on that I suppose

That's good enough for me! :)

I am curious though, how would one go about the math for this? The cube state during a solve isn't a truly random, so it seems like it would be difficult to determine the "true" value behind insertions.

I suppose one could do an empirical study though by analyzing solves from the FMC challenge. Though, processing the data properly would be no small feat.

EDIT: Also, our guesses are surprisingly similar. I said 3.5 moves, and you said 1 per 7 in the frame. So that means 3.5 moves would be saved in a 24.5 skeleton, giving a final move count of 29.8, and I've personally always considered 30 moves as "the number to beat."
 
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I can't think of a better formula off-hand right now, but I certainly don't average over 3 moves per insertion, and my skeletons for L3C do average at least 21. I think I average just over 2 moves cancelling. That's just my feeling - I have no exact figures to back that up.
 
Well, insertions provide a hidden benefit, because they (practically) guarantee an 8f* commutator, whereas applying the 3-cycle at the end, as Guus pointed out, averages 8.8 moves. So the average value of an insertion is .8 + average # of cancellations.
 
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But statistics can lie too: Tomoaki Okayama got a 22 move solve for Per's FMC #372 (http://fmc.mustcube.net/results.php?round=372&format=classic&metric=htm)

Scramble: R L' U2 D' R2 U2 B L D2 F' L' R' D2 R2 F D2 U' F' L2 U L2 R U' F' L2 U2 D' F L' F'

Solve: U2 L' U' L2 U L2 F U B' U' B L' F L' F' U' L2 R U2 B' F D'

(For inverse scramble)
Pre-scramble: U2

2x2x1 block: D F'
2x2x2 block: B U2 R'
2x2x3 block: L2 U
Finish F2L: F L F' L F'

Then

All but 3 corners: B' U B U' * L2 U' L2 U L
Correction: U2

Insert at *: U B' U' F U B U' F' (8 moves cancel!)

Congratz Tomoaki, but you could have done that insertion straight into your linear solve.
 
But statistics can lie too: Tomoaki Okayama got a 22 move solve for Per's FMC #372 (http://fmc.mustcube.net/results.php?round=372&format=classic&metric=htm)

Scramble: R L' U2 D' R2 U2 B L D2 F' L' R' D2 R2 F D2 U' F' L2 U L2 R U' F' L2 U2 D' F L' F'

Solve: U2 L' U' L2 U L2 F U B' U' B L' F L' F' U' L2 R U2 B' F D'

(For inverse scramble)
Pre-scramble: U2

2x2x1 block: D F'
2x2x2 block: B U2 R'
2x2x3 block: L2 U
Finish F2L: F L F' L F'

Then

All but 3 corners: B' U B U' * L2 U' L2 U L
Correction: U2

Insert at *: U B' U' F U B U' F' (8 moves cancel!)

Congratz Tomoaki, but you could have done that insertion straight into your linear solve.

WTF!? congrats for F2L in 12 moves!
 
But statistics can lie too: Tomoaki Okayama got a 22 move solve for Per's FMC #372 (http://fmc.mustcube.net/results.php?round=372&format=classic&metric=htm)

Scramble: R L' U2 D' R2 U2 B L D2 F' L' R' D2 R2 F D2 U' F' L2 U L2 R U' F' L2 U2 D' F L' F'

Solve: U2 L' U' L2 U L2 F U B' U' B L' F L' F' U' L2 R U2 B' F D'

(For inverse scramble)
Pre-scramble: U2

2x2x1 block: D F'
2x2x2 block: B U2 R'
2x2x3 block: L2 U
Finish F2L: F L F' L F'

Then

All but 3 corners: B' U B U' * L2 U' L2 U L
Correction: U2

Insert at *: U B' U' F U B U' F' (8 moves cancel!)

Congratz Tomoaki, but you could have done that insertion straight into your linear solve.

WTF!? congrats for F2L in 12 moves!
 
Congratz Tomoaki, but you could have done that insertion straight into your linear solve.
No offence, but that seems to be limited LL knowledge rather than a fantastic insertion though :p

Yeah, you're right. If you know all of the 10-move LL, you can solve that LL in one step:
F B' U B U' F' L2 U' L2 U
but I currently know only COLL + quite-easy LL... :fp
By the next competition I will learn more LL. :)

EDIT: In my experience, two moves (or so) cancel on an average by a corner 3-cycle insertion.
 
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Spols Open fail-fest

Scramble 1: B' D2 F R2 B F L B U' F U2 F R F L' U R' B R
Scramble 2: L' D2 R2 F U B' L D L F2 R B2 D' B2 D2 B D2 R2

1st
Premoves F D L'
L' F' U2 L2 - 2x2x2
R . F' D2 - 2x2x3
R2 F R2 F2 - F2L-1
could not find good continuation


After comp, same start
Premoves F D L'
L' F' U2 L2 - 2x2x2
R . F' D2 - 2x2x3
R' F R' F R2 F2 - F2L-1 (just inserting F into R2 of original solution)
R2 F D' F' D R' D R' D' R - leaves 3 corners
F D L' - undo premoves
At . insert R B R' F' R B' R' F to cancel 3 moves

L' F' U2 L2 R2 B R' F' R B' R' D2 R' F R' F R2 F2 R2 F D' F' D R' D R' D' R F D L' = 31 HTM

2nd
I cannot believe I missed the obvious 2x2x2 block...
I did see that L' made a pair, how could I not see that F' made the square????
At a given moment I decided to just put in a ZZ solve just to get "a result"
6 move EO-line into bad continuation and a notation error to top it off.


On a more positive note:
I've been helping manhobbyfreak a little with FMC techniques and he came very close to a 31 on the 1st scramble.
19 HTM for L5C
1st insertion with 2 moves cancel
2nd insertion with 2 moves cancel but unfortunately the com was faulty. (time pressure)
We've got a future winner here!

Tristan's solution
L' B2 F' L - 2x2x2
R . U2 R2 U' R - 2x2x3
U' R U R' F2 U' F U' F' U2 - leaves 5 corners
at . insert R' B2 R F2 R' B2 R F2 to cancel 2 moves
don't have the wrong comm anymore...
We checked what happend, it included an R2 as interchange move but there was only one corner in the R face ;)

I also ran a check on the L5C and found a 4 move comm after the very first move, leaving 3C in 23 HTM.
We'll both do a full check and compare.
 
20 move FMC :)

[22:50] <+Kirjava> scramble: R F U2 R2 U L2 D2 L2 F' L' F' B' L2 B2 D F' U2 R F' D2 F2 L' B' D F'
F2L-1: L2 B' F' R F D2 :)
Continue: D L F L' F2 D F D2 L (2 twisted corners left)
So the skeleton is: L2 B' F' R F * . D' L F L' F2 D F D2 L (14)
Insert F' R' F L F' R F L' at * to cancel 6 moves (standard conjugate cancellation)
Insert L' U' L D' L' U L D at . to cancel 4 moves

Solution: L2 B' L F' R F L2 U' L D' L' U L2 F L' F2 D F D2 L (20 moves)
 
20 move FMC :)

[22:50] <+Kirjava> scramble: R F U2 R2 U L2 D2 L2 F' L' F' B' L2 B2 D F' U2 R F' D2 F2 L' B' D F'
F2L-1: L2 B' F' R F D2 :)
Continue: D L F L' F2 D F D2 L (2 twisted corners left)
So the skeleton is: L2 B' F' R F * . D' L F L' F2 D F D2 L (14)
Insert F' R' F L F' R F L' at * to cancel 6 moves (standard conjugate cancellation)
Insert L' U' L D' L' U L D at . to cancel 4 moves

Solution: L2 B' L F' R F L2 U' L D' L' U L2 F L' F2 D F D2 L (20 moves)
That solution is incredible, the F2L-1 is simply ':eek:'. You've shown me that 2 twisted corners aren't as bad as I thought.
 
20 move FMC :)

[22:50] <+Kirjava> scramble: R F U2 R2 U L2 D2 L2 F' L' F' B' L2 B2 D F' U2 R F' D2 F2 L' B' D F'
F2L-1: L2 B' F' R F D2 :)
Continue: D L F L' F2 D F D2 L (2 twisted corners left)
So the skeleton is: L2 B' F' R F * . D' L F L' F2 D F D2 L (14)
Insert F' R' F L F' R F L' at * to cancel 6 moves (standard conjugate cancellation)
Insert L' U' L D' L' U L D at . to cancel 4 moves

Solution: L2 B' L F' R F L2 U' L D' L' U L2 F L' F2 D F D2 L (20 moves)

My solution also 20 moves :)
F2U2BF’L’U’FU’R’F2L2B2L’FB’U2FB’RF2
F2U2BF’L’U’FU’R all corners and 5 edges,
R2F2L2B2L’FB’U2FB’RF2 2 edges swap , L5E.
 
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