[Help Thread] FMC Discussion

[theos]

can anyone give me an optimal solution for a 3cycle w/ setup:

R2 U F2 R2 F2 D' F2 D R2 B D' F2 D B' R2 U'

Source for all possible 3-cycles gives us this algorithm for this case: R B R2 B L' B' R2 B L B2 R'
For your case's orientation this transposes to: L D L2 D R' D' L2 D R D2 L' (11 moves)
This is [L D: [L2, D R' D']]

 

[Duncan Bannon]

Because I don't know how to make Comms for FMC. Nor do I know insertions.(Will learn here in a few days over break) I would like you to help me with getting a good skeleton. I would like to work on getting around 35 for whole solve. For now I want to get okay with just use normal scramble (until break then Ill learn NISS).


Scramble 1 -R' U' F L2 U' L2 B2 U R2 F2 U' R2 U' R2 F' U L' B R B2 R D2 R' U R' U' F

Spoiler

B' D2 R' F U F- X Cross (6/6) (I was building 2x2x2 block and cross pieces fell in)
U R' U' R' B' R' B- F2L-2 (7/13)
R' D2 F D2 F'- F2L-1 (5/18)
R B R' B'- F2L - 1 Corner (4/22)
R2- (1/23)Left you with L3C and 2 edges to swap


It that pretty good?

Edit- B R' B R2 B' R2 F' R B R' F B2 (12f*) is optimal making it a 35!!! However I don't think a human could get the optimal could they???

Scramble 2- R' U' F B R' F' L B U' D2 L' B' L2 D2 L2 U B2 U' R2 B2 U D L2 R' U' F

Spoiler

R' F' R' D' R B' D' F' D' -2X2X2 (9/9)
U B' U' L U L' U' F U' F' U' B' U B2- Pair inserting (14/25)
U2 B' F' B L F B' (7/32) F2L
R' F R B' R' F' R B (8/40) OLL
Optimal U perm is 9 more moves. Or a 49

I know doing LL is a bad idea but this one wasn't bad. Because of this, it doesn't need to be critiqued as I know I probably shouldn't have done LL.

Scramble 3-R' U' F D2 F2 R2 F2 U' R2 U' L2 U B2 L2 F D2 L U F' R2 B D' R' D' R' U' F

Spoiler

F2 L' F U R' U2-2X2X2 (6/6)
D B' L' B-2X2X3 (4/10)
L2 F L' F D' L' D -F2L-1 (7/17)

Anything good after this???

Also what is a good number of moves for:

EO at start
2x2x2
2x2x3
F2L-1
L3C

 

[Robert Marik]

FMC Europe solutions:


R' U' F D' B2 U B2 D2 L2 D B2 L D2 L2 B' L' D2 R D' B2 F L2 U' R' U' F


(D') B' R' U //EO
B2 (B) //square
U2 R' //two squares!
(U2 R2 B2) //F2L-1
D L' D' L //15 to 3c3e


25, 27, 27 = 26.33 mean, 2nd place

This is really amazing solution. I was surprised that you switch fom inverse even inside EO or during square in the second step.

Do you look for these moves on the cube with inverse scramble or do you recognise these one-movers (D’ on the first line and B on the second line) on the reguar scramble?

In the first case, how often do you check the inverse? After each move? If the second case is true, do you have some explanation for the first move - D’?

Thank you.

Because I don't know how to make Comms for FMC. Nor do I know insertions.(Will learn here in a few days over break) I would like you to help me with getting a good skeleton. I would like to work on getting around 35 for whole solve. For now I want to get okay with just use normal scramble (until break then Ill learn NISS).


Scramble 1 -R' U' F L2 U' L2 B2 U R2 F2 U' R2 U' R2 F' U L' B R B2 R D2 R' U R' U' F

Spoiler

B' D2 R' F U F- X Cross (6/6) (I was building 2x2x2 block and cross pieces fell in)
U R' U' R' B' R' B- F2L-2 (7/13)
R' D2 F D2 F'- F2L-1 (5/18)
R B R' B'- F2L - 1 Corner (4/22)
R2- (1/23)Left you with L3C and 2 edges to swap


It that pretty good?

Edit- B R' B R2 B' R2 F' R B R' F B2 (12f*) is optimal making it a 35!!! However I don't think a human could get the optimal could they???

Scramble 2- R' U' F B R' F' L B U' D2 L' B' L2 D2 L2 U B2 U' R2 B2 U D L2 R' U' F

Spoiler

R' F' R' D' R B' D' F' D' -2X2X2 (9/9)
U B' U' L U L' U' F U' F' U' B' U B2- Pair inserting (14/25)
U2 B' F' B L F B' (7/32) F2L
R' F R B' R' F' R B (8/40) OLL
Optimal U perm is 9 more moves. Or a 49

I know doing LL is a bad idea but this one wasn't bad. Because of this, it doesn't need to be critiqued as I know I probably shouldn't have done LL.

Scramble 3-R' U' F D2 F2 R2 F2 U' R2 U' L2 U B2 L2 F D2 L U F' R2 B D' R' D' R' U' F

Spoiler

F2 L' F U R' U2-2X2X2 (6/6)
D B' L' B-2X2X3 (4/10)
L2 F L' F D' L' D -F2L-1 (7/17)

Anything good after this???

Also what is a good number of moves for:

EO at start
2x2x2
2x2x3
F2L-1
L3C

Estimates for move count can be found in the famous FMC tutorial by Sebasriano Tronto (porkynator) on page 19. This source does not provide estimate for EO, however.

 

[G2013]

Just rolled my ao5 PB!
Scramble: R' U' F D2 U2 F U2 B R2 B' F' L2 D2 F D' L' U R' U R2 F R' U' R' U' F
Inverse: F' U R U R F' R2 U' R U' L D F' D2 L2 F B R2 B' U2 F' U2 D2 F' U R

Spoiler

B2 U F2 // 1x2x3
D' U' L' D L' U2 //2x2x3 (9 moves)
(D' F' R2 F ) //EO
D' R2 D2 R2 D' //L3C L3E ske=18
Skeleton: B2 * U F2 @ D' U' L' D L' U2 D' R2 D2 R2 D' F' R2 F D = 18+8-2+6-3 = 27
Insertion 1:
* = (R' U L U' R U L' U')
@ = (R2 U' D B2 D' U)

Final solution: B2 R' U L U' R U L' F2 R2 U' D B2 D2 L' D L' U2 D' R2 D2 R2 D' F' R2 F D (27 HTM)

Giving PB ao5! (25, 26, 27, 30, 27) = 26.66 noiceice

Any tips are welcome, as always

 

[cubeshepherd]

I was doing a FMC solve but I am confused how to write out the final solution.
Premoves: L2 F' L2 R D R' L2
The scramble is: R' U' F D R2 B U2 R' F2 R2 U' R' L2 D' B2 L2 U R2 L2 B2 D R2 U' R' U' F

I started by doing (L2 R D' R' L2 F L2) 2x2x2 block
I then reversed that (L2 F' L2 R D R' L2) and did the inverse scramble.
Once I did that I did the rest of the solution with the inverse scramble, and my question is: Do I count the 7 move 2x2x2 block in the solution or not.
After the 2x2x2 block and inverse scramble is complete this is the rest of the solution:
D' R' F' D R2 D R D2 L D L'//F2l-1
D' F D F' D' F D// Last F2L slot
L D L' D' F' Fw L D L' D' Fw'//OLL
F2 L2 F R F' L2 F R' F//PLL 38 Moves)
For some reason I am really confused on how to write out the solution and I am sorry for not understanding it, but any and all help is very much appreciated.

 

[asacuber]

I was doing a FMC solve but I am confused how to write out the final solution.
The scramble is: R' U' F D R2 B U2 R' F2 R2 U' R' L2 D' B2 L2 U R2 L2 B2 D R2 U' R' U' F

I started by doing (L2 R D' R' L2 F L2) 2x2x2 block
I then reversed that (L2 F' L2 R D R' L2) and did the inverse scramble.
Once I did that I did the rest of the solution with the inverse scramble, and my question is: Do I count the 7 move 2x2x2 block in the solution or not.
After the 2x2x2 block and inverse scramble is complete this is the rest of the solution: D' R' F D R2 D R D2 L D L' D' L D L' D' L D L' F L D L' D' Fw L D L' D' Fw' F2 L2 F R F' L2 F R' F (39 moves).
For some reason I am really confused on how to write out the solution and I am sorry for not understanding it, but any and all help is very much appreciated.

Your solution will be:
(2x2x2 block on normal)(Invert whatever you did on the inverse scramble)
Watch Jay's video on NISS, it helped me a lot.

 

[theos]

I was doing a FMC solve but I am confused how to write out the final solution.
Premoves: L2 F' L2 R D R' L2
The scramble is: R' U' F D R2 B U2 R' F2 R2 U' R' L2 D' B2 L2 U R2 L2 B2 D R2 U' R' U' F

I started by doing (L2 R D' R' L2 F L2) 2x2x2 block
I then reversed that (L2 F' L2 R D R' L2) and did the inverse scramble.
Once I did that I did the rest of the solution with the inverse scramble, and my question is: Do I count the 7 move 2x2x2 block in the solution or not.
After the 2x2x2 block and inverse scramble is complete this is the rest of the solution:
D' R' F' D R2 D R D2 L D L'//F2l-1
D' F D F' D' F D// Last F2L slot
L D L' D' F' Fw L D L' D' Fw'//OLL
F2 L2 F R F' L2 F R' F//PLL 38 Moves)
For some reason I am really confused on how to write out the solution and I am sorry for not understanding it, but any and all help is very much appreciated.

To help piece things together at the end it's useful to write out moves on the inverse scramble in brackets (and moves on the normal scramble without brackets). This is a simple case, but if you start switching between the normal and inverse scramble frequently in a solve then it will help to keep things straight.

Scramble: R' U' F D R2 B U2 R' F2 R2 U' R' L2 D' B2 L2 U R2 L2 B2 D R2 U' R' U' F
L2 R D' R' L2 F L2 // 2x2x2
(D' R' F' D R2 D R D2 L D L') // F2L-1
(D' F D F' D' F D) // F2L
(L D L' D' F' Fw L D L' D' Fw') // OLL
(F2 L2 F R F' L2 F R' F) // PLL

At any point while solving if you want to see how things look on the inverse scramble, do:

• inverse of all non-bracketed moves
• inverse scramble
• all bracketed moves

To see how things look on the normal scramble, do:

• inverse of all bracketed moves
• normal scramble
• all non-bracketed moves

Now to get to your question, when you want to write your final solution (or skeleton if you do insertions), do:

• all non-bracketed moves
• inverse of all bracketed moves

So in your case this solution will be:
L2 R D' R' L2 F L2 ... F' R F' L2 F R' F' L2 F2 ... Fw D L D' L' Fw' F D L D' L' ... D' F' D F D' F' D ... L D' L' D2 R' D' R2 D' F R D
(You'd leave out the ellipses in your written solution; they're just there to show the different steps of your solution.)

More detailed example of a solution to this scramble with multiple sections on the normal and inverse scrambles:

Spoiler: 28 moves

Scramble: R' U' F D R2 B U2 R' F2 R2 U' R' L2 D' B2 L2 U R2 L2 B2 D R2 U' R' U' F
(B D B' D' B2 R) // pseudo-2x2x2
R' // 2x2x2
(U B2 U) // pseudo-2x2x3
U // 2x2x3
D' B' D // edge orientation
L B' L' B2 L' // F2L-1
(B2 L' B' L) // build last F2L pair on last layer
B' L' B2 L // F2L
B' // LL skip
Assemble the solution: R' ... U ... D' B' D ... L B' L' B2 L' ... B' L' B2 L ... B' ... L' B L B2 ... U' B2 U' ... R' B2 D B D' B'
Final solution: R' U D' B' D L B' L' B2 L' B' L' B2 L B' L' B L B2 U' B2 U' R' B2 D B D' B' (28 moves)

 

[Cale S]

pretty cool solution

R' U' F D2 B D2 U2 B D2 B' F R2 D' B' D B2 F' U' R U2 R' U2 R' U' F

B U B2 D // 222
F U' F' // square
R2 F' (R) // F2L - 1
F U F' // 11 to 3c5e

^ B U B2 @ D F U' F' R2 U F' R'
^ = R' U R % U' // to 3e3c
@ = U2 L R' F2 R L' // to 3c
% = [R' F' R, B]

Solution: R' U F' R B R' F R B' U' B U B2 U2 L R' F2 R L' D F U' F' R2 U F' R'

27 moves

Insertion finder found a 25 by nesting the edge comm in the corner comm

 

[Hssandwich]

This is really amazing solution. I was surprised that you switch fom inverse even inside EO or during square in the second step.

Do you look for these moves on the cube with inverse scramble or do you recognise these one-movers (D’ on the first line and B on the second line) on the reguar scramble?

In the first case, how often do you check the inverse? After each move? If the second case is true, do you have some explanation for the first move - D’?

Thank you.

Thanks
I found the first (D') when looking on the inverse scramble for EO starts. I saw that it reduced the EO from that orientation down to 4 bad edges, so I could hopefully solve EO with a few moves after switching.
I knew that B2 made a pseudo square after EO, since it lined up a 2x1x1 with the correct centre with a solved E-layer edge, so after switching, there would be a one move square.
I always check the inverse at the end of each step, or sometimes halfway through on rare occasions. Here though, I knew that after B2, (B) would make the square, so I knew to switch to solve that.
Hope this helps

 

[Duncan Bannon]

Normally before posting a question I do some research and if I don't get a relatively quick answer Ill post here. It seems like I've been working on Commutators and Conjugates for forever Here are my questions.

1-Difference between Commutator and Conjugate? ( I get the A B A' B' vs A B A', just not in a solve part)

2- To solve a twisted corner in say ab4c, do I just do a 3 cycle that solves 1 piece then do ab3c case?

3- I seem to get most ab3c cases, although I'm still figuring out some, I don't seem to be able to solve ab4c or ab5c. Is there a general tip to help know how to solve ab4c/ab5c?

4-Sometime when doing a 3 cycle I get 2 twisted corners? How to solve the 3 cycle right? For example- Do R U' R' D R U R' D' as scramble, then when I do what I think the right cycle - L D R D' L' D R' D' It ;eaves 2 twisted corners.

Thanks a million.

 

[theos]

1-Difference between Commutator and Conjugate? ( I get the A B A' B' vs A B A', just not in a solve part)

Conjugate (A B A') is for when you need to use a set-up move to apply an algorithm, e.g. solving 2C2E you might be 2 moves away (D2 L' say) from a T-perm in your skeleton. So you do D2 L' [T-perm alg] L D2.

Commutator (A B A' B') is for making an algorithm. The only pieces affected are those affected by both A and B, and their projections by A' and B'. Practically you mainly just need to know how to make the commutators for 3C and 3E cases, though maybe there's some more niche cases you'll want to learn much later.

2- To solve a twisted corner in say ab4c, do I just do a 3 cycle that solves 1 piece then do ab3c case?

Yip. Solve 1 corner of the twisted 3-cycle and ensure the 3rd corner of your insertion is the twisted corner (otherwise you're left with 2 or 3 twisted corners).

3- I seem to get most ab3c cases, although I'm still figuring out some, I don't seem to be able to solve ab4c or ab5c. Is there a general tip to help know how to solve ab4c/ab5c?

• AB5C - 5-cycle. You need to solve 2 corners with your first insertion to leave a 3-cycle. So if corner [1] is being solved into position [2] you need to also solve [2]->[3] or [5]->[1] at the same time.
• AB4C - twisted 3-cycle + twisted corner. Solve exactly 1 corner of the twisted 3-cycle to leave a 3-cycle. (The 3rd corner of the insertion is the twisted corner.)
• AB4C - (twisted) 2-cycle + (twisted) 2-cycle. Solve any 1 corner to leave a 3-cycle. (The 3rd corner of the insertion is from the other 2-cycle.)
• All other AB4C and AB5C cases require more than 2 insertions.

4-Sometime when doing a 3 cycle I get 2 twisted corners? How to solve the 3 cycle right? For example- Do R U' R' D R U R' D' as scramble, then when I do what I think the right cycle - L D R D' L' D R' D' It ;eaves 2 twisted corners.

You have to make sure you're solving 2 corners into the correct position and orientation (and then the 3rd one will be solved for free).

In your example the corners are FDL --> RDF --> FLU --> FDL. The orientation is important: the F facelet of FDL must go in the position of the R facelet of RDF which must go in the position of the F facelet of FLU.

The commutator you used here is [L, D R D']. The L move puts the FDL corner into the right position but wrong orientation.

To see a working commutator you can look for 1 move that will solve a corner (position AND orientation) and leaves a 3rd corner untouched. From your scramble a D move will solve RDF into the correct position and orientation. So our commutator is either [D, X] or [Y, D'].

But this only solves 1 corner, so we need to be careful choosing X/Y such that we also solve another corner:

• For the X in [D, X] we need the inverse of the 3-move sequence that will solve FLU. X' = R U R' works, i.e. X = R U' R', so the solution is [D, R U' R'] (which is just the inverse of the scramble).
• For the Y in [Y, D'] we need the 3-move sequence that will solve FDL. Y = L' U' L works. So the solution is [L' U' L, D'].

 

[Duncan Bannon]

This makes it so much clearer! Thank you ever so much.

 

[cubeshepherd]

I was working on this scramble and I got to a few different solutions that lead to either F2L-1 or AB4C/2E. None of my solves seem to have a good move count, but I am sure that there is something that I am missing that could reduce the move count or cancel moves, but I can not seem to figure that out hence why I ask for enlightenment from the higher and better FMC solvers.

Scramble: R' U' F R2 F' R2 D2 R2 U2 D L' B U2 R2 U L2 D R2 U L2 F2 L2 R' U' F

F U' L U L2 U [2x2x2 Block] 6/6
D L' F' L' F' L F' D' L2 F' [Diagonal F2L pairs] 10/16

And from there I came across two different solutions, with the first being a better move count, and seemingly better all around.

First Solution: R' D' R D F' R F R' [F2L-1] 8/24
B D' B' D' B D' B' D L' D L D B D B' L' D L [OLL] AB4C and 2E 17/41

Second Solution: B D' B' F L' D L D' F' [Orange and Green 2x2x3 Block] 9/25
R B' R2 B' R' B' R' U R U' R' B U' B' U [F2L] 15/40
D' R' D R' D' R2 D [OLL] 7/47
D' R2 D R2 D' F D R D' R' D' F' D2 R2 [PLL] 14/61 Really bad solution, but I wanted to see what I missed.

Thank you all very much in advance, for you time and to help train me in the ways of the FMC. : )

 

[theos]

I was working on this scramble and I got to a few different solutions that lead to either F2L-1 or AB4C/2E. None of my solves seem to have a good move count, but I am sure that there is something that I am missing that could reduce the move count or cancel moves, but I can not seem to figure that out hence why I ask for enlightenment from the higher and better FMC solvers.

Scramble: R' U' F R2 F' R2 D2 R2 U2 D L' B U2 R2 U L2 D R2 U L2 F2 L2 R' U' F

F U' L U L2 U [2x2x2 Block] 6/6
D L' F' L' F' L F' D' L2 F' [Diagonal F2L pairs] 10/16

And from there I came across two different solutions, with the first being a better move count, and seemingly better all around.

First Solution: R' D' R D F' R F R' [F2L-1] 8/24
B D' B' D' B D' B' D L' D L D B D B' L' D L [OLL] AB4C and 2E 17/41

Second Solution: B D' B' F L' D L D' F' [Orange and Green 2x2x3 Block] 9/25
R B' R2 B' R' B' R' U R U' R' B U' B' U [F2L] 15/40
D' R' D R' D' R2 D [OLL] 7/47
D' R2 D R2 D' F D R D' R' D' F' D2 R2 [PLL] 14/61 Really bad solution, but I wanted to see what I missed.

Thank you all very much in advance, for you time and to help train me in the ways of the FMC. : )

Almost any solution with OLL and PLL is going to look bad in comparison to a solution using insertions to solve the last pieces.

The simplest reasonable continuation that I spotted from your F2L-2:
Scramble: R' U' F R2 F' R2 D2 R2 U2 D L' B U2 R2 U L2 D R2 U L2 F2 L2 R' U' F
F U' L U L2 U // 2x2x2 given [6/6]
D L' F' L' F' L F' D' L2 F' // F2L-2 given [10/16]
R' D2 R F D2 F' // F2L-1 [6/22]
B D B' D L' D' L // AB5C [7/29]
Optimal insertions results in 37 moves.

Still not great. My preference is to go for a 2x2x3 block after 2x2x2:
F U' L U L2 U // 2x2x2 given [6/6]
F2 D' F2 D L' D' L2 // 2x2x3 [7/13] - just the first 2x2x3 block I spotted
R' D2 R2 F' R' // Orient edges [5/18]
D F D' // F2L-1 [3/21]
D' F' D F' // AB5C [3/24]
And optimal insertions results in 33 moves.

I'm sure much better is possible, but as long as you can do corner cycle insertions, sub-40 move solutions are pretty easy to come by.

 

[asacuber]

this scramble looks pretty good but i couldnt expand on my nice 2x2x2s and 2x2x3s and panicked and got a crappy 46(i had found a 43 or 44 before on one of the 2x2x3s but didnt write it down) EO looks quite nice for this scramble, but I couldn't find anything.

Generated By csTimer on 2018-3-24
single: 46.00

Time List:
1. 46.00 R' U' F D2 L' B2 U2 R' B2 R U2 R B2 L2 F' L' F D' L' D U' L F2 R' U' F

I found:

R' F B R B R2 B L' B' U' L2 U

And

F B R B R2
Switch
D' L' D B' R D2 R'

 

[Duncan Bannon]

R' U' F U L2 B2 U' B2 U2 F2 L2 U' L2 D' R' U R' D2 B' D L B2 U2 L2 R' U' F

Inverse-F' U R L2 U2 B2 L' D' B D2 R U' R D L2 U L2 F2 U2 B2 U B2 L2 U' F U R
U2 L' F2 D R2-2X2X2 5/5
U F' L U-2X2X3 5/9
F2 L2 D' L D U L U'-F2L 8/17
F U L U' L' F'-EO 6/23
D L D' L D L2 D'- EP 7/30


IF said
U2 L' F2 D R2 U F' L U F2 L2 D' L D U L [@1] U' F U L U' L' F' D L D' L D L2 D' L2
Insert at @1: L' F' L B2 L' F L B2
Fewest moves: 37. 2 moves cancelled
The final solution: U2 L' F2 D R2 U F' L U F2 L2 D' L D U F' L B2 L' F L B2 U' F U L U' L' F' D L D' L D L2 D' L2

I cant do inserstions but Ill work on them.

Really happy with 37 honestly. I know I 1/2 cheated though. Any help is appreciated.

 

[theos]

R' U' F U L2 B2 U' B2 U2 F2 L2 U' L2 D' R' U R' D2 B' D L B2 U2 L2 R' U' F

Inverse-F' U R L2 U2 B2 L' D' B D2 R U' R D L2 U L2 F2 U2 B2 U B2 L2 U' F U R
U2 L' F2 D R2-2X2X2 5/5
U F' L U-2X2X3 5/9
F2 L2 D' L D U L U'-F2L 8/17
F U L U' L' F'-EO 6/23
D L D' L D L2 D'- EP 7/30


IF said
U2 L' F2 D R2 U F' L U F2 L2 D' L D U L [@1] U' F U L U' L' F' D L D' L D L2 D' L2
Insert at @1: L' F' L B2 L' F L B2
Fewest moves: 37. 2 moves cancelled
The final solution: U2 L' F2 D R2 U F' L U F2 L2 D' L D U F' L B2 L' F L B2 U' F U L U' L' F' D L D' L D L2 D' L2

I cant do inserstions but Ill work on them.

Really happy with 37 honestly. I know I 1/2 cheated though. Any help is appreciated.

Starting from your 2x2x3, I got a decent continuation by switching to the inverse scramble.

Scramble: R' U' F U L2 B2 U' B2 U2 F2 L2 U' L2 D' R' U R' D2 B' D L B2 U2 L2 R' U' F
U2 L' F2 D R2 // 2x2x2 given [5/5]
U F' L U // 2x2x3 given [4/9]
(L2 D' L2 D L') // Switch to inverse, F2L-1 and this also orients our edges [5/14]
L F L' F2 L F' L' F // Switch back to normal, solve edges leaving AB4C [8/22]
Insertions from IF...
Skeleton: U2 L' F2 * D R2 U F' L U L F L' F2 @ L F' L' F L D' L2 D L2
Inset at *: L D R2 D' L' D R2 D' [4/26]
Insert at @: F R F' L F R' F' L' [4/30]
Solution: U2 L' F2 L D R2 D' L' D U F' L U L F L' F' R F' L F R' F2 L' F L D' L2 D L2 (30 moves)

 

[Duncan Bannon]

When I switch to inverse (at 2x2x3) Its seems I only get 2x2x2 with extra pair. Missing the White/Red edge. Am I doing something wrong when using NISS.

 

[theos]

When I switch to inverse (at 2x2x3) Its seems I only get 2x2x2 with extra pair. Missing the White/Red edge. Am I doing something wrong when using NISS.

When you switch from normal to inverse (and vice-versa) the blocks already built should remain. That implies a mistake somewhere. Looks like a problem with the inverse you've written: it should end F' U R not F U R. (My solution was based on the correct inverse as validated by IF.)

 

[Duncan Bannon]

Okay! Gotcha! I thought I was doing the steps right. With Inverse moves in solution then inverse. Thanks. Ill start to add NISS to my solves. I get most 3 cycles except when no corner is orientated. The next solve I do will be just fun practice. Ill try to use Pseudo blocks if there is a good case. Ill also try to do EO at F2L-1 or after 2x2x3.