[Help Thread] FMC Discussion

[Smiles]

This has already probably been said before, but a good continuation for me is to build a 1x2x3 the add the two edges that make it a 2x2x3. Even if it has been used a lot before, I haven't seen it be used lately.

if you're going for a 2x2x3, i guess it doesn't matter if u get there via a 1x2x3 or 2x2x2. I just do whichever is easier.

 

[Memphis3000]

Yeah I was implying that, but I was just saying that another approach was to do that way. I haven't seen this way a lot, maybe it's just a lot of moves, but I've used it a few times in my FMC solutions.

I finally got a sub 43 single!

222-F R2 L F' L2 B R F2
223-L' U2 B U L U2 L
F2L-U L U2 L' U2 B2 U B2 U' B' U' B'
OLL-L U F U' F' L'
PLL-L F' L B2 L' F L B2 L2 U'
FINAL-F R2 L F' L2 B R F2 L' U2 B U L U2 L U L U2 L' U2 B2 U B2 U' B' U' B' L U F U' F2 L B2 L' F L B2 L2 U'

What could I have done better/differently? IF gives it 39.

 

[Kit Clement]

Yeah I was implying that, but I was just saying that another approach was to do that way. I haven't seen this way a lot, maybe it's just a lot of moves, but I've used it a few times in my FMC solutions.

I've done it many times, but I don't document my FMC life on this thread

2x2x2 -> 2x2x3 is just typically an easier path than 1x2x3 -> 2x2x3, as 2x2x2 leaves you more options for extending, and the 3 free faces have all unsolved pieces. But hey, sometimes you can get lucky on the 1x2x3 path, try this scramble out: R' D2 F2 D2 L2 D2 R' B2 U2 L B' R B R' D B2 R' B D

 

[Memphis3000]

I've done it many times, but I don't document my FMC life on this thread

2x2x2 -> 2x2x3 is just typically an easier path than 1x2x3 -> 2x2x3, as 2x2x2 leaves you more options for extending, and the 3 free faces have all unsolved pieces. But hey, sometimes you can get lucky on the 1x2x3 path, try this scramble out: R' D2 F2 D2 L2 D2 R' B2 U2 L B' R B R' D B2 R' B D

Yeah, now that I've tested it out, 2x2-2x2x3 seems like a lot fewer moves than 1x2x3-2x2x3. That scramble has an easy 1x2x3, as well as an ok 2x2x2. Being my noobish self, I would probably do the 2x2x2 because that's what I always do. Yeah I know that you shouldn't limit yourself to one "method".

 

[Ranzha]

One 27 and two 29s from last night and today with the dankers:

D2 B2 R2 U L2 B2 R2 U' F2 D' B2 R B R U' L2 F U' B2‏

Spoiler

N: R2 B // 2x2x2 [2]
R' D2 R' F' R F R' D R2 @ // 2x2x3 [9/11]
F D2 F' R' D R // 3x-cross + square [6/17]
F' D' F' D // AB3C [4/21]

@ R F' L' F R' F' L F [8-2/27]

Final: R2 B R' D2 R' F' R F R' D R' F' L' F R' F' L F2 D2 F' R' D R F' D' F' D (27)

F2 R2 F2 R2 U L2 B2 D R B' L' D2 L' F' D L2 R D' F'‏

Spoiler

B' D2 F B' U' // 2x2x3 [5]
switch
B R' F' R' B' R' F B' D' B // F2L [10/15]
B R B U' B' U R' B' // CLL [8-1/22]
B L2 F2 D R2 F2 L2 U B R' // ELL [9-2/29]‏

Final: B' D2 F B' U' R B' U' L2 F2 R2 D' F2 L2 R U' B U B' R' B2 D B F' R B R F R B' (29)

MultiBLD #28 from this week's forum competition
L2 D2 L2 B2 L2 U R2 U B2 U B2 L' U' B' L F2 L F D F' R'‏

Spoiler

Skeleton:
D B2 R F' B' // squares and stuff
R D R' // 2x2x2
L' U2 L2 // 2x-cross
R B2 R2 U R U' // EO3S
R B2 R' B' R B' R'‏ // Antisune to L3C [24]

Between lines 2 and 3, switch the R' and L'. Insert between: [U' L' U, R'].

Final: D B2 R F' B' R D L' U' L' U R' U' L U' L2 R B2 R2 U R U' R B2 R' B' R B' R' (29)

 

[Meneghetti]

All my solves from Pré-Mundial 2015 (mo3: 32/36/32 = 33.33)

1. B2 L F2 R F2 L F2 D2 L2 U' B L D' U B' D2 L' F U'

Spoiler

U2 F’ L D’ F2 // 2x2x2
L B2 * L2 // square
U R’ U R // AB3E5C

insert at *: B’ F R B’ @ R’ B F’ # U B U’ // [y: M', U R' U']
insert at @: B R2 B’ L2 B R2 B’ L2 // [B R2 B', L2]
insert at #: F R F’ L2 F R’ F’ L2 // [F R F', L2]

Final solution: U2 F’ L D’ F2 L B F R’ B’ L2 B R2 B’ L2 R’ B R F’ L2 F R’ F’ L2 U B U’ L2 U R’ U R (32 OBTM)

IF gives 30!

2. U2 R U2 R U2 R' B F2 L2 U2 L' F D' L2 F2 U' L2

Spoiler

B’ R2 F’ R’ // 2x2x2
D F2 D’ F2 // siamese blocks
R U R’ U’ B’ U’ B // F2L-1
F2 L F L’ F // F2L + EO
R U R’ U R U2 R’ // Sune
R’ U L’ U2 R U’ R’ U2 R L // J-perm

Final solution: B’ R2 F’ R’ D F2 D’ F2 R U R’ U’ B’ U’ B F2 L F L’ F R U R’ U R U2 R2 U L’ U2 R U’ R’ U2 R L (36 OBTM)

This was my backup solution.

3. U' F2 L2 F2 D U' L2 U B2 F' R2 U' B' U2 L F2 R D' U

Spoiler

U R L2 U B’ // 2x2x2
R U R’ L’ U2 // 2x2x3
L D’ L D @ L2 F’ // F2L-1
F U’ F’ U2 * L U’ L // AB4C

insert at *: U2 F’ D’ F U2 F’ D F
insert at @: D’ B’ D F’ D’ B D F

Final solution: U R L2 U B’ R U R’ L’ U2 L D’ L B’ D F’ D’ B D F L2 U’ F2 D’ F U2 F’ D F L U’ L (32 OBTM)

IF gives 30.

 

[jpbrc]

My 23 moves solution from Pré-mundial 2015. New SAR

Scramble: U' F2 L2 F2 D U' L2 U B2 F' R2 U' B' U2 L F2 R D' U

D' R F' U' // EO
B // 2x2x1
R2 D2 // another 2x2x1
L' B L' // 2x2x3
R F' R F2 // AB5C

skeleton: D' R F' U' B R2 D2 L' B L' R * F' R F2

*= R' B' R # F' R' B R F
#= R B2 R' F R B2 R' F'

Solution: D' R F' U' B R2 D2 L' B L' B' R2 B2 R' F R B2 R' F2 R' B R2 F2 (23)

 

[TheDubDubJr]

My 23 moves solution from Pré-mundial 2015. New SAR

Scramble: U' F2 L2 F2 D U' L2 U B2 F' R2 U' B' U2 L F2 R D' U

D' R F' U' // EO
B // 2x2x1
R2 D2 // another 2x2x1
L' B L' // 2x2x3
R F' R F2 // AB5C

skeleton: D' R F' U' B R2 D2 L' B L' R * F' R F2

*= R' B' R # F' R' B R F
#= R B2 R' F R B2 R' F'

Solution: D' R F' U' B R2 D2 L' B L' B' R2 B2 R' F R B2 R' F2 R' B R2 F2 (23)

Welcome to the 23club

 

[Hssandwich]

How does one do L5C well?

 

[Berd]

How does one do L5C well?

Seconded.

 

[guysensei1]

How does one do L5C well?

First insertion will solve any 2 corners+affect one other random corner of the remaining 3. Here's where you have lots of choices to look for cancellations. Second one solves the rest.

 

[Sebastien]

Current Average of 12 (not sure if PB or not): 26, (30), 27, 25, 27, 27, 26, (20), 22, 21, 22, 26 = 24,9

Thanks to another nice Berkeley scramble:

25, 27, 27, 26, (20), 22, 21, 22, 26, 21, (28), 26 = 24,3

Definitely PB ao12 now.

 

[Sebastien]

My 23 moves solution from Pré-mundial 2015. New SAR

Congratz.

How comes that you DNF'd the second solve?

 

[TheDubDubJr]

How does one do L5C well?

Seconded.

First you have to make sure you have a good 5corners skeleton. Make sure there are no twisted corners basically.

Then I sticker each piece 1 goes to 2, to 3, to 4, and to 5. (5 back to 1)

Then I go though each move of the skeleton and look at all 5 different 3cycles, 123 234 345 451 512, and see if I can cancel at least 2 moves on any of them (unless I am getting low on # of insertions, then I start writing the 1move cancellations too). If so then I write down the insertion and which 3-cycle it is.

When you get to the end, you have all insertions and which cycles they are. The way that each insertions goes with another is if it continues into the next cycle. (AND MAKE SURE THE ORDER IS CORRECT)

Example: cycle 123 goes with cycle 451 (as long as 123 comes first).
and cycle 451 goes with cycle 234 (as long as 451 comes first).

Usually you are able to find optimal unless the insertions are Nested inside the first insertion.

 

[Berd]

First you have to make sure you have a good 5corners skeleton. Make sure there are no twisted corners basically.

Then I sticker each piece 1 goes to 2, to 3, to 4, and to 5. (5 back to 1)

Then I go though each move and look at all 5 different 3cycles, 123 234 345 451 512, and see if I can cancel at least 2 moves on any of them (unless I am getting low on # of insertions, then I start writing the 1move cancellations too). If so then I write down the insertion and which 3-cycle it is.

When you get to the end, you have all insertions and which cycle it is. The way that each insertions goes with another is if it continues into the next cycle. (AND MAKE SURE THE ORDER IS CORRECT)

Example: cycle 123 goes with cycle 451 (as long as 123 comes first).
and cycle 451 goes with cycle 234 (as long as 451 comes first).

Usually you are able to find optimal unless the insertions are Nested inside the first insertion.

Whaaaa!?

 

[bubbagrub]

Whaaaa!?

I really recommend this tutorial for everything to do with FMC, including 5-cycles.

But the short explanation is this:

So, having got your skeleton, you sticker the unsolved cubies, 1, 2, 3, etc.

If you have a three-cycle, you basically want to do something like 1->2->3. Meaning the cubie at 1 needs to go to the place where the cubie labeled 2 is and 2 goes to 3 and 3 goes to 1.

With a 5-cycle, there are lots of possibilities, but the best case is when it's a single 5-cycle -- 1->2->3->4->5. In that case, if you do any of the 3-cycles contained in that 5-cycle (e.g., 1->2->3 or 3->4->5 or 5->1->2) it will leave another 3-cycle. There's a slightly complicated bit here to do with whether you look for the second insertion in a skeleton including the first insertion or not. If you do the former, then you will find (by seeing which stickered cubies are now unsolved) what cycle you need to solve the rest. If you do the latter, then you can use the fact that the two cycles need to follow each other and start and end with the same number.

E.g., if you find 2->3->4 as your first cycle, then you can either insert 4->5->1 before it, or 5->1->2 after it.

HTH!

 

[jpbrc]

Congratz.

How comes that you DNF'd the second solve?

Thx! I arrived 30 minutes late and didn't have time to finish the insertions I found a 18 moves skeleton that could lead to a 28 moves solution if I had enough time. Really sad about that

 

[Sebastien]

Thx! I arrived 30 minutes late and didn't have time to finish the insertions I found a 18 moves skeleton that could lead to a 28 moves solution if I had enough time. Really sad about that

Oh, I see. Well, you were already lucky that you were allowed to still participate when being so late. You should have just focused on getting some solution, e.g. applying commutators at the end of your skeleton when time was runnign out. Any solution of 44 or below would have been sufficient for you to win the event. :/

 

[Memphis3000]

Can anyone find a good continuation to this F2L-1? The best I found was a 31 move solution. I want to see what the experts would do. IF gives my skeleton a 29.

Spoiler: F2L-1

Scramble:B U2 B' R2 F2 D2 U2 R2 U R B2 L U F U2 B U' B' R2
2x2x2-F U2 L D'
2x2x3-B U2 R U' R'
F2L-1-U2 B

 

[Kit Clement]

Got a PB 23 single doing some Skype FMC tonight

Scramble: F' D R' F D R2 B' D2 R' F U2 L2 F R2 D2 B' L2 F' U2 L2

I: F2 D F2 D U2 F2 D' F \\PS 2x2x3 (8/8)
N: B D B' (L' \\F2L-1 (3/11)
L) U' L' U B' L' B2 L \\L3C (7/18)

Skel: B D B' U' L' U B' L' B2 (1) L F' D F2 U2 D' F2 D' F2

(1): B R B' L B R' B' L'

Final: B D B' U' L' U B' L' B' R B' L B R' B' F' D F2 U2 D' F2 D' F2 (23)