3x3 PBL Theoretical Method (3BL) (CFOP Variant)

[Duncan Kimmett]

U can reduce the EPLL on D cases to just Solved, Z and one of the Uperms using just D moves
Adj and W can D or D' to either Uperm, Opp is a D or D' away from a Z perm, and the Os have been accounted for
So it'll just be 63+2 = 65
D or D' just does 3 edge swaps so parity on bottom is easily avoidable

Also, if you don’t do W perm perm with aligning the edge perfectly, then you just get Adj. case. Just something to think about.

 

[Jorian Meeuse]

I didn't list the cases in order. All the numbers are correct tho.



Can you show an example of this? This doesn't sound right to me.

No, it is 132 cases. Everytime you have 21 in your breakdown, it should be 22.


What hyn suggestes is indeed correct. He means that if you have parity on the cross, you can do a D or D' to get no parity.

 

[Cuber987]

This is a really good theoretical idea! I'd love to try it out if we ever find all the algs.

 

[Silky]

No, it is 132 cases. Everytime you have 21 in your breakdown, it should be 22.

We agree, I said 132. Reread the post.

 

[Jorian Meeuse]

We agree, I said 132. Reread the post.

Oops sorry i didn't catch that

 

[Duncan Kimmett]

This is a really good theoretical idea! I'd love to try it out if we ever find all the algs.

Oh, I’m finishing all the algs today.

 

[Duncan Kimmett]

I’m at 115 algs of 132 (More like 129) so the algs will be finished today.

 

[Duncan Kimmett]

I am very glad to announce I have finished every single algorithm!

 

[Jorian Meeuse]

I am very glad to announce I have finished every single algorithm!

Well that's ambiguous.

 

[Duncan Kimmett]

Well that's ambiguous.

Check the doc. I have Pll skips, and all the algs for W Perm cross, Z Perm cross, Ua Perm cross, Ub Perm cross, Adj. cross, and opp. cross!

 

[Jorian Meeuse]

Check the doc. I have Pll skips, and all the algs for W Perm cross, Z Perm cross, Ua Perm cross, Ub Perm cross, Adj. cross, and opp. cross!

Awesome!
(With ambiguous I meant that 'finishing' algs can also mean 'killing' algs)

 

[Duncan Kimmett]

Awesome!
(With ambiguous I meant that 'finishing' algs can also mean 'killing' algs)

Ah! That’s my bad!

 

[Duncan Kimmett]

Could you do EFLL (Edge Flip Last Layer)? Have a flipped cross edge, and then you do an alg to fix the swapped edges on both cross and PLL. Math: 1 edge flipped on PLL, 4 different edge positions, so (21 PLLs) (4 Positions) = 84. 84 x 4 because you can have 1 flipped edge, 2 flipped edges, 3 flipped edges, and 4 flipped edges. My math is probably very wrong, because 2 flipped cross edges and 4 flipped cross edges is 21 algs each, so I’ll just fix the math in the final math, meaning 21 + 21 = 42 and then 84 x 2 = 168. 168 + 42 = 210. Any thoughts?

 

[Silky]

Could you do EFLL (Edge Flip Last Layer)? Have a flipped cross edge, and then you do an alg to fix the swapped edges on both cross and PLL. Math: 1 edge flipped on PLL, 4 different edge positions, so (21 PLLs) (4 Positions) = 84. 84 x 4 because you can have 1 flipped edge, 2 flipped edges, 3 flipped edges, and 4 flipped edges. My math is probably very wrong, because 2 flipped cross edges and 4 flipped cross edges is 21 algs each, so I’ll just fix the math in the final math, meaning 21 + 21 = 42 and then 84 x 2 = 168. 168 + 42 = 210. Any thoughts?

You cannot have 3 flipped edge pieces

 

[Duncan Kimmett]

You cannot have 3 flipped edge pieces

ah, thanks

 

[Duncan Kimmett]

math is still correct

 

[Duncan Kimmett]

Algs are too long

 

[Duncan Kimmett]

Been a while, but I think I’m gonna try and learn 2 look 3BL (correct to EPLL bottom and then correct to EPLL top) so I’ll be learning 12 algs, being UbUb, Hub, Hua, UaUb, UbUa, UaUa, ZUa, ZUb, ZZ, UaZ, UbZ, HZ.

 

[OreKehStrah]

Been a while, but I think I’m gonna try and learn 2 look 3BL (correct to EPLL bottom and then correct to EPLL top) so I’ll be learning 12 algs, being UbUb, Hub, Hua, UaUb, UbUa, UaUa, ZUa, ZUb, ZZ, UaZ, UbZ, HZ.

You can solve the CP on both layers simultaneously very very easily

 

[Deleted member 36445]

You can solve the CP on both layers simultaneously very very easily

That's what I use for the method I developed.
As I don't know all algs I solve any cp with j/j cp just like on sq1 beginner and then ep in 2 looks, one reducing the top layer to phased, the other I do z2 and solve the rest with algs from epll and ocell

For cp i use this alg for j/j

 Twizzle link 

R2 U R2 U' D' R2 D R2

Ocell algs (i use the algs with all edges orientes)

Meep.

To solve j/j I will put bars on front.
If i have just one adj swap I put one bar on left to reduce to j/j
If i have opp/opp I do j/j to reduce to j/j

Here you can try this example solve game

3x3 PBL example solve game

Ok so I wanted to see what you guys can think of to solve 3x3 PBL efficiently. Scramble generator: https://filipeteixeira.com.br/pbl/ Click on "NEW PBL SCRAMBLE" to generate new pbl...

www.speedsolving.com

@Duncan Kimmett